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Show that vectors \(\mathbf{a}(t)=\langle\cos t, \sin t\rangle\) and \(\mathbf{a}(x)=\left\langle x, \sqrt{1-x^{2}}\right\rangle\) are equivalent for \(x=r\) and \(t=2 k \pi\), where \(k\) is an integer.

Short Answer

Expert verified
Yes, the vectors are equivalent at \( x = 1 \) and \( t = 2k\pi \).

Step by step solution

01

Understand Vector Notations

Let's start by analyzing the given vector notations. The vector \( \mathbf{a}(t) = \langle \cos t, \sin t \rangle \) represents a parametric equation for a unit circle using the parameter \( t \). Similarly, the vector \( \mathbf{a}(x) = \langle x, \sqrt{1-x^{2}} \rangle \) represents the same unit circle but with \( x \) as the parameter.
02

Simplification of Equivalence Condition

We need to show equivalence for \( x = r \) and \( t = 2k\pi \), where \( k \) is an integer. For \( t = 2k\pi \), we have \( \cos(2k\pi) = 1 \) and \( \sin(2k\pi) = 0 \), thus \( \mathbf{a}(t) = \langle 1, 0 \rangle \). Since \( x = r = 1 \), substitute into \( \mathbf{a}(x) \) to get \( \left\langle 1, \sqrt{1-1^2} \right\rangle = \langle 1, 0 \rangle \), matching \( \mathbf{a}(t) \).
03

Confirmation of Unit Circle Representation

Both vector forms essentially describe points on a unit circle in their parameter space. For any point \( (x, y) \) on a unit circle, \( x^2 + y^2 = 1 \) holds true. The parametric form \( \mathbf{a}(t) \) uses trigonometric identities for a circle, and \( \mathbf{a}(x) \) is derived directly from the unit circle equation. Substituting specific values shows that they are still representing the same geometric concept.
04

Conclusion of Equivalence

The vectors \( \mathbf{a}(t) \) and \( \mathbf{a}(x) \) coincide for \( x = 1 \) and \( t = 2k\pi \) since both reduce to \( \langle 1, 0 \rangle \). Thus, for \( x = r = 1 \) and \( t = 2k\pi \), the parameterizations of the vectors are equivalent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

unit circle
The unit circle is a fundamental concept in trigonometry. It is a circle with a radius of 1, centered at the origin of the coordinate plane.
  • Coordinates on the unit circle can be described using the equations \( x = \cos t \) and \( y = \sin t \), where \( t \) is the angle in radians measured from the positive x-axis.
  • Every point on the unit circle satisfies the equation \( x^2 + y^2 = 1 \). This is the circle's defining property.
The concept of the unit circle enables the linking of trigonometric functions and geometric interpretations.
For instance, \( \left \langle \cos t, \sin t \right \rangle \) represents a point on the unit circle parametrized by the angle \( t \). This shows how trigonometry can be visualized on a circle rather than just through abstract functions.
When dealing with vectors such as \( \mathbf{a}(t) = \langle \cos t, \sin t \rangle \) and \( \mathbf{a}(x) = \left \langle x, \sqrt{1-x^{2}} \right \rangle \), you are essentially looking at different ways to traverse or describe the circle's path using different parametric forms.
parametric equations
Parametric equations are a common way to represent mathematical situations where multiple variables depend on a single parameter.
In essence, parametric equations define a group of quantities as functions of one or more independent variables called parameters.
  • In the context of the unit circle, parametric equations \( \langle \cos t, \sin t \rangle \) describe the coordinates of points on the circle as \( t \) varies.
  • Another set, \( \left\langle x, \sqrt{1-x^2} \right \rangle \), uses \( x \) as the parameter.
This highlights how different parameters can offer diverse perspectives but essentially describe the same geometric functionalities.
These representations are beneficial because they give directions about a curve's path, like how a specific rotation angle \( t \) maps to a point \( (x, y) \) on the unit circle.
trigonometric identities
Trigonometric identities are equations involving trigonometric functions that are universally true for all values of the relevant variables.
These identities are integral in simplifying trig expressions and proving equations like those involving vectors.
  • A primary example from the unit circle is the identity \( \cos^2 t + \sin^2 t = 1 \). This directly stems from the circle's equation.
  • When you substitute \( t = 2k\pi \) for some integer \( k \), the identities simplify: \( \cos(2k\pi) = 1 \) and \( \sin(2k\pi) = 0 \).
Using these identities helps in proving equivalence or simplifying problems that use trigonometric parameterizations.
In our vectors case: \( \langle \cos t, \sin t \rangle \), when \( t = 2k\pi \), it naturally equates to \( \langle 1, 0 \rangle \), matching with the vector \( \langle x, \sqrt{1-x^{2}} \rangle \) for \( x = 1 \). This equivalence through trigonometric identities highlights how such equations can serve as powerful tools in verifying vector equivalences.

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