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Write the standard form of the equation of the ellipsoid centered at the origin that passes through points \(A(2,0,0), B(0,0,1)\), and \(C\left(\frac{1}{2}, \sqrt{11}, \frac{1}{2}\right)\)

Short Answer

Expert verified
The equation of the ellipsoid is \( \frac{x^2}{4} + \frac{y^2}{11} + z^2 = 1 \).

Step by step solution

01

Understanding the Standard Form of an Ellipsoid

The standard form of the equation of an ellipsoid centered at the origin is given by \( \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1 \). Here, \(a\), \(b\), and \(c\) are the semi-axis lengths along the x, y, and z directions, respectively.
02

Setting Up Equations with Given Points

The ellipsoid passes through points \(A(2,0,0)\), \(B(0,0,1)\), and \(C\left(\frac{1}{2}, \sqrt{11}, \frac{1}{2}\right)\). Substitute each point into the ellipsoid's equation:For point \(A\): \( \frac{2^2}{a^2} + \frac{0^2}{b^2} + \frac{0^2}{c^2} = 1 \Rightarrow \frac{4}{a^2} = 1 \).For point \(B\): \( \frac{0^2}{a^2} + \frac{0^2}{b^2} + \frac{1^2}{c^2} = 1 \Rightarrow \frac{1}{c^2} = 1 \).For point \(C\): \( \frac{\left(\frac{1}{2}\right)^2}{a^2} + \frac{(\sqrt{11})^2}{b^2} + \frac{\left(\frac{1}{2}\right)^2}{c^2} = 1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ellipsoid Geometry
Ellipsoid geometry is all about smooth, symmetrical surfaces. Imagine an inflated balloon or a stretched sphere — that's what an ellipsoid looks like. It's a three-dimensional shape with three axes of different lengths. Each axis represents a direction: x, y, or z, and they intersect at the center point of the ellipsoid. This center point is like the heart of the ellipsoid. For simplicity, we often place this point at the origin in coordinate space, which is the center of our geometric universe.

An ellipsoid's equation captures its symmetry and size. The longer the axis, the more elongated the ellipsoid is in that direction. Ellipsoids come up in many fields, including physics and engineering. Understanding them is a core skill in geometry because they help us model real-world objects. For example, Earth's shape can be modeled as an ellipsoid rather than a perfect sphere because of its slight bulging at the equator.
Coordinates of Ellipsoid
Coordinates for an ellipsoid are based on its equation, which is written as \( \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1 \). In this equation, \(a\), \(b\), and \(c\) correspond to the semi-axes, which are half the lengths of the whole ellipsoid in the x, y, and z dimensions respectively.

When we say an ellipsoid is centered at the origin, we mean its central point or center of symmetry is at (0,0,0). This makes it easier to reference different points on the ellipsoid. To describe any point on its surface, you can plug its coordinates into the ellipsoid's equation. Points like A(2,0,0), B(0,0,1), and C\( \left(\frac{1}{2}, \sqrt{11}, \frac{1}{2}\right) \) each meet the required property: when substituted into this equation, they satisfy it completely.

The use of coordinates allows us to verify points on the shape, ensuring accuracy when plotting or modeling ellipsoidal objects.
Mathematical Substitution
Mathematical substitution is a vital tool for solving equations in geometry. It involves replacing variables in an equation with specific values or expressions to simplify and solve it. In our case, to find the equation of the ellipsoid passing through given points, we begin by substituting these points into the standard ellipsoid equation.

For instance, with point A at (2,0,0), substitution into \( \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1 \) gives \( \frac{4}{a^2} = 1 \). This shows that \( a = 2 \). Similarly, substituting B(0,0,1) gives \( \frac{1}{c^2} = 1 \), indicating \( c = 1 \).

We repeat this process for all given points to calculate each semi-axis. This step is crucial because it directly influences the ellipsoid's shape and spatial orientation. Substitution helps break down complex determinations into manageable computations, ensuring clarity.

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Most popular questions from this chapter

Sketch and describe the cylindrical surface of the given equation. $$ x^{2}+y^{2}=9 $$

In cartography, Earth is approximated by an oblate spheroid rather than a sphere. The radii at the equator and poles are approximately \(3963 \mathrm{mi}\) and \(3950 \mathrm{mi}\), respectively. a. Write the equation in standard form of the ellipsoid that represents the shape of Earth. Assume the center of Earth is at the origin and that the trace formed by plane \(z=0\) corresponds to the equator. b. Sketch the graph. c. Find the equation of the intersection curve of the surface with plane \(z=1000\) that is parallel to the xy-plane. The intersection curve is called a parallel. d. Find the equation of the intersection curve of the surface with plane \(x+y=0\) that passes through the \(z\) -axis. The intersection curve is called a meridian.

For the following exercises, the equations of two planes are given. Determine whether the planes are parallel, orthogonal, or neither. If the planes are neither parallel nor orthogonal, then find the measure of the angle between the planes. Express the answer in degrees rounded to the nearest integer. Consider the plane of equation \(x-y-z-8=0\) a. Find the equation of the sphere with center \(C\) at the origin that is tangent to the given plane b. Find parametric equations of the line passing through the origin and the point of tangency.

Rewrite the given equation of the quadric surface in standard form. Identify the surface. $$ -3 x^{2}+5 y^{2}-z^{2}=10 $$

Find the trace of the given quadric surface in the specified plane of coordinates and sketch it. $$ -4 x^{2}+25 y^{2}+z^{2}=100, y=0 $$

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