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Let \(\mathbf{v}=\langle 1,2\rangle\) a. Find a unit vector with the same direction as \(\mathbf{v}\). b. Find a vector \(\mathbf{w}\) with the same direction as \(\mathbf{v}\) such that \(\|\mathbf{w}\|=7\).

Short Answer

Expert verified
a. \( \left\langle \frac{1}{\sqrt{5}}, \frac{2}{\sqrt{5}} \right\rangle \); b. \( \left\langle \frac{7\sqrt{5}}{5}, \frac{14\sqrt{5}}{5} \right\rangle \)."

Step by step solution

01

Calculate the Magnitude of \(\mathbf{v}\)

To find a unit vector in the same direction as \(\mathbf{v}\), we first need to calculate its magnitude. The magnitude of a vector \(\mathbf{v}=\langle a,b \rangle\) is given by \(\|\mathbf{v}\| = \sqrt{a^2 + b^2}\). For \(\mathbf{v}=\langle 1,2 \rangle\), we have: \[ \|\mathbf{v}\| = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5} \].
02

Find the Unit Vector in the Direction of \(\mathbf{v}\)

A unit vector \(\mathbf{u}\) in the direction of a vector \(\mathbf{v}\) is given by dividing the vector by its magnitude: \(\mathbf{u} = \frac{\mathbf{v}}{\|\mathbf{v}\|}\). Thus, the unit vector in the direction of \(\mathbf{v}=\langle 1,2 \rangle\) is: \[ \mathbf{u} = \frac{1}{\sqrt{5}} \langle 1, 2 \rangle = \left\langle \frac{1}{\sqrt{5}}, \frac{2}{\sqrt{5}} \right\rangle \].
03

Scale the Unit Vector to Desired Magnitude

To find a vector \(\mathbf{w}\) that has the same direction as \(\mathbf{v}\) but a magnitude of 7, multiply the unit vector \(\mathbf{u}\) by 7: \(\mathbf{w} = 7 \cdot \mathbf{u}\). Substitute the unit vector: \[ \mathbf{w} = 7 \left\langle \frac{1}{\sqrt{5}}, \frac{2}{\sqrt{5}} \right\rangle = \left\langle \frac{7}{\sqrt{5}}, \frac{14}{\sqrt{5}} \right\rangle \].
04

Simplify the Vector \(\mathbf{w}\)

Divide the components of \(\mathbf{w}\) by \(\sqrt{5}/5\) to rationalize the denominators: \[ \mathbf{w} = \left\langle \frac{7\sqrt{5}}{5}, \frac{14\sqrt{5}}{5} \right\rangle \]. Thus, the vector \(\mathbf{w}\) with the desired properties has been found.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exploring Vector Magnitude
The magnitude of a vector, also known as its length or norm, is a measure of how long the vector is. Imagine you have a straight line drawn from the origin to a point described by a vector. The magnitude is simply the distance from the starting point to the endpoint in a coordinate space.
To compute the magnitude of a vector represented as \(\mathbf{v} = \langle a, b \rangle\), use the formula:
  • \(\|\mathbf{v}\| = \sqrt{a^2 + b^2}\)
For example, with a vector \(\mathbf{v} = \langle 1, 2 \rangle\), the magnitude is calculated by plugging in the values for \(a\) and \(b\):
  • \(\|\mathbf{v}\| = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5}\)
Understanding how to compute and interpret magnitude is essential when examining vector properties and their applications.
The Concept of Unit Vectors
A unit vector is defined as a vector with a magnitude of 1, which makes it extremely useful for indicating direction without altering scale. Given any vector \(\mathbf{v}\), the corresponding unit vector \(\mathbf{u}\) in the same direction can be found by dividing the original vector by its magnitude.Let's consider \(\mathbf{v} = \langle 1, 2 \rangle\) with a magnitude \(\sqrt{5}\). The unit vector \(\mathbf{u}\) is calculated as:
  • \(\mathbf{u} = \frac{\mathbf{v}}{\|\mathbf{v}\|} = \frac{1}{\sqrt{5}} \langle 1, 2 \rangle = \left\langle \frac{1}{\sqrt{5}}, \frac{2}{\sqrt{5}} \right\rangle\)
This process of normalizing a vector ensures that while the direction remains unchanged, its size becomes manageable. Unit vectors are pivotal in physics and engineering for maintaining direction when working with diverse scales of magnitude.
Understanding the Direction of a Vector
The direction of a vector describes its orientation in space, defined by the angle it makes with the coordinate axes or relative to another vector. It's a vital component when vectors are utilized to express physical quantities like velocity or force.For a vector \(\mathbf{v}\) expressed as \(\langle x, y \rangle\), the direction can be depicted through an angle \(\theta\), calculated by using trigonometric functions. The angle is typically measured from the positive x-axis, going counterclockwise:
  • \(\theta = \tan^{-1}\left(\frac{y}{x}\right)\)
A vector's direction is kept constant unless specifically altered by a transformation or manipulation such as scaling, ensuring that it's always pointing in the same way, regardless of its magnitude.

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