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In Exercises \(1-6,\) find \(d y / d x\). $$y=-x^{2}+3$$

Short Answer

Expert verified
The derivative of the function \(y = -x^{2}+3\) in respect to \(x\) is \(dy/dx = -2x\)

Step by step solution

01

Identify the Function

Identify the given function which is \(y=-x^{2}+3\). The power of x in this equation is \(2\), and the coefficients include \(-1\) and \(3\)
02

Apply the Power Rule to First Term

The power rule states that the derivative of \(x^n\) is \(n*x^{n-1}\). Apply this rule to the first term: \(-x^2\). Multiply the coefficient of the x-term by the exponent: \(-1*2 = -2\). The power of x is then decreased by 1: \(x^{2-1} = x\). The derivative of \(-x^2\) is thus \(-2x\).
03

Apply the Power Rule to Second Term and Sum

The second term, \(3\), is a constant and its derivative is simply zero since constants disappear in differentiation. Finally, you sum up the results of the first and second term, having \(dy/dx = -2x + 0 = -2x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
In calculus, the power rule is a fundamental technique used to find the derivative of a function of the form \( f(x) = x^n \). This rule simplifies the differentiation process by allowing us to systematically bring down the exponent in front of the variable and reduce the exponent by one. For example, if you have \( y = x^3 \), applying the power rule gives us the derivative as \( dy/dx = 3x^{3-1} \), which simplifies to \( 3x^2 \).

Key points to remember about the power rule:
  • It applies to any polynomial term where the variable is raised to a power.
  • You multiply the variable's coefficient by its exponent.
  • Reduce the original exponent by one after multiplying.
In our exercise, the power rule was applied to the term \(-x^2\). We took the exponent, 2, and multiplied it by the coefficient \(-1\) to get \(-2\), then reduced the exponent from 2 to 1, leading us to the derivative \(-2x\).
Constant Rule
The constant rule in calculus tells us that the derivative of a constant is zero. This is because a constant does not change in value, meaning its rate of change—hence its derivative—is zero. Whenever you differentiate a term that does not contain a variable, the result is zero.

Understanding the constant rule is crucial in simplifying the differentiation of more complex equations involving both variables and constants. For instance, if you have a function like \( y = -x^2 + 3 \), when calculating the derivative, the constant \( 3 \) disappears as it contributes nothing to the rate of change of the function. This leaves us only needing to consider variable-containing terms for further operations.

In the step-by-step solution of our exercise, the term \( 3 \) was identified as a constant, and thus its derivative was marked as zero, validating the use of the constant rule.
Calculus
Calculus is a branch of mathematics that deals with the study of change. It is built on two fundamental concepts: differentiation and integration. Differentiation is the process of finding the derivative of a function, which represents the rate of change of the function's value relative to changes in its input value. This concept is essential for analyzing and understanding how functions behave.

To appreciate calculus, consider it as a powerful tool that allows mathematicians, scientists, and engineers to solve real-world problems involving dynamic systems. Whether it's calculating the speed of a moving car or determining the optimal shape of an object, calculus provides the methodologies needed to model and solve these challenges.

In our exercise, we specifically focused on differentiation using the power rule and the constant rule to find the derivative of a polynomial function. By breaking down a function into its components, calculus enables us to tackle complex problems by applying specific rules and techniques. This not only helps in understanding the mechanics of change and motion but also in predicting future behavior of systems.

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Most popular questions from this chapter

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