/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 In Exercises \(33-36,\) find \(d... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercises \(33-36,\) find \(d y / d x\) $$y=x^{1-e}$$

Short Answer

Expert verified
The derivative of the function \(y=x^{1-e}\) is approximately \(-1.71828/x^{2.71828}\)

Step by step solution

01

Apply the Power Rule

Start by using the power rule for differentiation, which states that the derivative of \(x^n\), where n is any real number, is \(n*x^{n-1}\). Controlled by the chain rule, doing this with the function given, the derivative dy/dx of \(y=x^{1-e}\) is \((1-e)*x^{(1-e)-1}\) which simplifies to \((1-e)*x^{-e}\). Because e is the Euler's number, you can substitute that value in.
02

Simplify the Result

After performing the aforementioned operation, the resulting function is \((1-e)*x^{-e}\). It is important to remember that the Euler's number e is approximately 2.71828, therefore the derivative is approximately \((1-2.71828)*x^{-2.71828}\), which simplifies to approximately \(-1.71828*x^{-2.71828}\).
03

Express the Solution in a Neater Form

Although this is the correct answer, it's generally better to represent it in a much neater form without a negative power. Thus, you can convert the negative exponent into a positive one and write the derivative as follows: \(-1.71828/x^{2.71828}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

The Power Rule
Understanding the Power Rule is essential for mastering the fundamentals of differentiation in calculus. It allows us to quickly find the derivative of a function that is a power of a variable. The rule states that if you have a function of the form \( f(x) = x^n \), where \( n \) is a real number, then the derivative of that function, \( f'(x) \), is \( nx^{n-1} \).

The application of this rule can be directly observed when differentiating powers of \( x \). It is efficient and saves time, especially compared to using the definition of the derivative as a limit. Here’s a practical example: if we have \( y = x^5 \), according to the Power Rule, the derivative \( dy/dx \) is \( 5x^{5-1} = 5x^4 \).

The Power Rule simplifies the process of finding derivatives and lays the groundwork for understanding more complex differentiation techniques. This rule is particularly powerful because it applies to both positive and negative exponents, as seen in the exercise example \( y = x^{1-e} \).
The Chain Rule
The Chain Rule is another indispensable tool in calculus, especially when dealing with composite functions. This rule is employed when you have a function nested within another function—essentially, a 'function of a function.' The Chain Rule helps us find the derivative of the outer function with respect to the inner function, then multiplies that by the derivative of the inner function itself.

To put it in formal terms, if you have a composed function \( f(g(x)) \), the derivative would be \( f'(g(x)) * g'(x) \). For instance, if \( f(x) = (3x + 2)^2 \), we identify the outer function as something squared and the inner function as \( 3x + 2 \). The Chain Rule tells us to take the derivative of the outer function, which is \( 2(3x + 2) \), and multiply it by the derivative of the inner function, which is 3. Therefore, the derivative \( f'(x) \) becomes \( 2(3x + 2) * 3 \).

Applying the Chain Rule effectively requires identifying the parts of the function correctly and understanding how they fit together, which is essential when working through more intricate differentiation problems.
Understanding Derivatives
A derivative represents an essential concept in calculus, often thought of as the rate at which something changes. Formally, the derivative of a function at a point is the slope of the tangent line to the function's graph at that point. It gives us an instantaneous rate of change, something like a snapshot of how a value is moving at a precise moment in time.

When we calculate the derivative of a function, we're looking to find an expression that describes this rate of change for every point on the function's curve. This is incredibly useful in a variety of scientific and engineering fields where such rates are crucial, such as velocity in physics or growth rates in biology.

Derivatives are often found using rules and formulas like the Power and Chain Rules discussed earlier. Estimating derivatives correctly is essential for predicting and understanding complex phenomena that involve change, which is a common theme across all quantitative disciplines.
Euler's Number
Euler's number, denoted as \( e \), is an irrational and transcendental number approximately equal to 2.71828. It is one of the most important constants in mathematics, particularly in calculus, due to its unique properties when used as the base for exponential functions.

Euler’s number is the foundation of natural logarithms, and it’s an integral part of the exponential growth and decay models. In differentiation and integration, the function \( e^x \) is remarkable because it is the only function that remains unchanged when the derivative is taken; that is, the derivative of \( e^x \) is still \( e^x \).

In the given exercise, Euler's number comes into play as a constant exponent, providing a unique case for differentiation. Calculating derivatives of this nature can be tricky but understanding the properties of \( e \) and how it interacts with other mathematical operations is essential for students who wish to excel in calculus and beyond. The proper manipulation of this constant, as seen in the exercise, often involves recognizing its value and then applying differentiation rules to simplify expressions including it.

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Most popular questions from this chapter

Multiple Choice Find the instantaneous rate of change of \(f(x)=x^{2}-2 / x+4\) at \(x=-1 .\) $$(\mathbf{A})-7 \quad(\mathbf{B})-4 \quad(\mathbf{C}) 0 \quad(\mathbf{D}) 4$$

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