Chapter 5: Problem 79
Show that \(\frac{1}{2} x|x|\) is an antiderivative of \(|x|\), and use this fact to get a simple formula for \(\int_{a}^{b}|x| d x\).
Short Answer
Expert verified
The antiderivative is verified, and the integral is \(\frac{1}{2}b|b| - \frac{1}{2}a|a|\).
Step by step solution
01
Understand the Function
We are given the function \(f(x) = \frac{1}{2} x|x|\) and need to verify it serves as an antiderivative of \(|x|\). This means we need to differentiate \(\frac{1}{2} x|x|\) and check if it equals \(|x|\).
02
Differentiating \(\frac{1}{2} x|x|\)
The function \(\frac{1}{2} x |x|\) can be split into two cases: \(x \geq 0\) where \(|x| = x\), and \(x < 0\) where \(|x| = -x\). For \(x \geq 0\), \(\frac{1}{2}x|x| = \frac{1}{2}x^2\). For \(x < 0\), \(\frac{1}{2}x|x| = -\frac{1}{2}x^2\). Now, differentiate for both cases.
03
Differentiate for \(x \geq 0\)
For \(x \geq 0\), the derivative of \(\frac{1}{2}x^2\) is \(x\). Since \(x = |x|\) when \(x \geq 0\), the derivative is \(|x|\).
04
Differentiate for \(x < 0\)
For \(x < 0\), the derivative of \(-\frac{1}{2}x^2\) is \(-x\). Since \(x < 0\), \(-x = |x|\). Thus, the derivative in this case is also \(|x|\).
05
Conclude the Antiderivative Verification
Since in both \(x \geq 0\) and \(x < 0\) cases, the derivative of \(\frac{1}{2} x|x|\) is \(|x|\), we confirm that \(\frac{1}{2} x|x|\) is indeed an antiderivative of \(|x|\).
06
Setup the Integral for \(\int_{a}^{b}|x| dx\)
Use the fundamental theorem of calculus. Since \(\frac{1}{2}x|x|\) is an antiderivative of \(|x|\), \(\int_{a}^{b}|x| \, dx = \left[ \frac{1}{2} x|x| \right]_a^b\).
07
Evaluate the Definite Integral
Compute \(\left[ \frac{1}{2} x|x| \right]_a^b\) as \(\frac{1}{2}b|b| - \frac{1}{2}a|a|\). This uses the expression for the antiderivative at limits \(b\) and \(a\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Absolute Value Function
The absolute value function, denoted as
- \(|x|\),
- For any non-negative number \(x\), the absolute value is simply \(x\) itself.
- For any negative number \(x\), it is \(-x\), effectively making it positive.
Definite Integral
A definite integral is a powerful tool in calculus that calculates the net area under a curve
- between two points on a graph.
- \(|x|\) between two points, \(a\) and \(b\).
Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus is a cornerstone in calculus that bridges the concept of differentiation and integration, two principal operations in calculus. It can be expressed in two parts:
- The first part states that the integral of a function over an interval can be found by using any of its antiderivatives.
- The second part says that the derivative of an integral function is the original function \(f(x)\).
- (like \(\frac{1}{2}x|x|\) for \(|x|\)),