Chapter 5: Problem 78
Evaluate \(\int_{-2}^{4}(2[x]-3|x|) d x\).
Short Answer
Expert verified
The evaluated integral is \(-5\).
Step by step solution
01
Understand the Function
The given integral is \( \int_{-2}^{4}(2[x]-3|x|) \, dx \). Here, \([x]\) denotes the greatest integer function, also known as the floor function, which returns the largest integer less than or equal to \(x\). \(|x|\) denotes the absolute value of \(x\).
02
Determine Intervals for \([x]\)
Since the greatest integer function \([x]\) changes at integer values, we need to evaluate the integral from \(-2\) to \(4\) by splitting it into intervals based on integer boundaries. These intervals are \([-2, -1)\), \([-1, 0)\), \([0, 1)\), \([1, 2)\), \([2, 3)\), and \([3, 4]\).
03
Evaluate Using Piecewise Function
On each interval, we express \( [x] \) and \( |x| \) as constant functions or well-defined linear functions:- For \([-2, -1)\): \([x] = -2\), \(|x| = -x\)- For \([-1, 0)\): \([x] = -1\), \(|x| = -x\)- For \([0, 1)\): \([x] = 0\), \(|x| = x\)- For \([1, 2)\): \([x] = 1\), \(|x| = x\)- For \([2, 3)\): \([x] = 2\), \(|x| = x\)- For \([3, 4]\): \([x] = 3\), \(|x| = x\)
04
Calculate Each Integral
Evaluate the integral on each interval:- \( \int_{-2}^{-1}(2(-2) - 3(-x)) \, dx = \int_{-2}^{-1}(-4 + 3x) \, dx \)- \( \int_{-1}^{0}(2(-1) - 3(-x)) \, dx = \int_{-1}^{0}(-2 + 3x) \, dx \)- \( \int_{0}^{1}(2(0) - 3x) \, dx = \int_{0}^{1}(-3x) \, dx \)- \( \int_{1}^{2}(2(1) - 3x) \, dx = \int_{1}^{2}(2 - 3x) \, dx \)- \( \int_{2}^{3}(2(2) - 3x) \, dx = \int_{2}^{3}(4 - 3x) \, dx \)- \( \int_{3}^{4}(2(3) - 3x) \, dx = \int_{3}^{4}(6 - 3x) \, dx \)
05
Solve Each Integral
Calculate each individual integral:- For \([-2, -1)\): \( \int_{-2}^{-1}(-4 + 3x) \, dx \) results in \(-(4x - \frac{3}{2}x^2)\bigg|_{-2}^{-1} = -\frac{5}{2} \)- For \([-1, 0)\): \( \int_{-1}^{0}(-2 + 3x) \, dx \) results in \(-(2x - \frac{3}{2}x^2)\bigg|_{-1}^{0} = -\frac{1}{2} \)- For \([0, 1)\): \( \int_{0}^{1}(-3x) \, dx \) results in \(-\frac{3}{2} \)- For \([1, 2)\): \( \int_{1}^{2}(2 - 3x) \, dx \) results in \(-\frac{3}{2} \)- For \([2, 3)\): \( \int_{2}^{3}(4 - 3x) \, dx \) results in \(-\frac{1}{2} \)- For \([3, 4]\): \( \int_{3}^{4}(6 - 3x) \, dx \) results in \(\frac{3}{2} \)
06
Sum the Results
Add up the results of each integral calculation:\(-\frac{5}{2} + (-\frac{1}{2}) + (-\frac{3}{2}) + (-\frac{3}{2}) + (-\frac{1}{2}) + \frac{3}{2} = -5 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Floor Function
The floor function, denoted as \([x]\), is a mathematical function that returns the greatest integer less than or equal to a given number \(x\). This concept is particularly useful in scenarios where you need to map a real number to the nearest lower whole number.
For instance:
For instance:
- If \(x = 1.7\), then \([x] = 1\).
- If \(x = -1.7\), then \([x] = -2\).
- If \(x = 3\), then \([x] = 3\) because \(3\) itself is an integer.
Absolute Value
The absolute value function, represented by \(|x|\), provides the distance of a number \(x\) from zero on the number line, regardless of its direction. In simpler terms, it turns negative values into positives.
- For positive values, \(|x| = x\).
- For zero, \(|0| = 0\).
- And importantly, for negative values, \(|x| = -x\).
Piecewise Integration
Piecewise integration is a technique utilized when dealing with functions that have different expressions over different intervals. These functions are effectively broken into 'pieces,' where each piece is defined mathematically by a separate formula on certain sub-intervals.
To compute an integral involving a piecewise function, it's essential to:
To compute an integral involving a piecewise function, it's essential to:
- Identify the intervals where the function changes its expression.
- Integrate each section separately, using the corresponding formula over its specific interval.
- Finally, sum up the results from each individually computed integral for the entire range.
Definite Integrals
Definite integrals represent the net area under a curve within a specific interval \([a, b]\). It’s computed by taking the integral of the function \(f(x)\) over that interval, denoting it as \(\int_{a}^{b} f(x) dx\).
Unlike indefinite integrals, which produce a general formula, definite integrals yield a numerical value.It's crucial to know that:
Unlike indefinite integrals, which produce a general formula, definite integrals yield a numerical value.It's crucial to know that:
- The limits of the integral (\(a\) and \(b\)) define the range over which you’re computing the area.
- Negative values indicate that the function is below the x-axis over this portion of the interval.
- Positive values signify that the function lies above the x-axis.