Chapter 1: Problem 32
Let $$ g(t)=\left\\{\begin{array}{ll}{t-2,} & {t<0} \\ {t^{2},} & {0 \leq t \leq 2} \\\ {2 t,} & {t>2}\end{array}\right. $$ Find $$ \begin{array}{llll}{\text { (a) } \lim _{t \rightarrow 0} g(t)} & {\text { (b) } \lim _{t \rightarrow 1} g(t)} & {\text { (c) } \lim _{t \rightarrow 2} g(t)} & {\text { (c) } \lim _{t \rightarrow 2} g(t)}\end{array} $$
Short Answer
Step by step solution
Determine the limit as t approaches 0 from the left
Determine the limit as t approaches 0 from the right
Evaluate the overall limit at t = 0
Evaluate the limit at t = 1
Determine the limit as t approaches 2 from the left
Determine the limit as t approaches 2 from the right
Evaluate the overall limit at t = 2
Answer question c (repeated in the prompt)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits in Calculus
- For \( \lim_{t \to 0} g(t) \), the left-hand limit \( g(t) = t - 2 \) gives \( -2 \), while the right-hand limit \( g(t) = t^2 \) gives \( 0 \). These limits are not equal, so \( \lim_{t \to 0} g(t) \) does not exist.
- For \( \lim_{t \to 1} g(t) \), we focus on the interval \( 0 \leq t \leq 2 \) where \( g(t) = t^2 \). The limit thus equals \( 1^2 = 1 \).
- For \( \lim_{t \to 2} g(t) \), the left limit using \( g(t) = t^2 \) and the right limit using \( g(t) = 2t \) both approach 4. So, \( \lim_{t \to 2} g(t) = 4 \).
Continuity
- The limit \( \lim_{t \to a} g(t) \) must exist.
- The function value \( g(a) \) must be defined.
- The limit must equal the function value, \( g(a) = \lim_{t \to a} g(t) \).
Understanding continuity helps identify where a function behaves predictably without jumps or breaks.
Calculus Problem Solving
- **Analyze the function:** Break down the piecewise function into its respective intervals and formulas. Know which expression to use for each range of \( t \).
- **Determine limits:** Use left-hand and right-hand approaches to calculate limits at points of interest. When left and right limits are unequal, note that the overall limit doesn't exist.
- **Check for continuity:** Apply the three conditions for continuity at key points to see if the function graphs smoothly without interruption.