/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Find and sketch the domain of th... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find and sketch the domain of the function. \( g(x, y) = \dfrac{x - y}{x + y} \)

Short Answer

Expert verified
The domain is all \((x, y)\) such that \( x + y \neq 0 \).

Step by step solution

01

Understand the Function

The given function is \( g(x, y) = \dfrac{x-y}{x+y} \). This is a rational function, meaning it is a ratio of two polynomials. The key to solving domain problems with rational functions is to find where the denominator is not zero.
02

Identify Restrictions

The domain of the function is defined wherever the denominator is not zero. Here the denominator is \( x + y \). Thus, the primary restriction to the domain is that \( x + y eq 0 \).
03

Set the Restriction as an Equation

We set up the equation \( x + y = 0 \) to understand where the function would be undefined. Solving this gives the line \( y = -x \). The function is undefined on this line.
04

Determine the Domain

The domain consists of all points \((x, y)\) such that \( x + y eq 0 \). This means any point not on the line \( y = -x \) is in the domain.
05

Sketch the Domain

To illustrate the domain, sketch the coordinate plane. Draw the line \( y = -x \) using a dashed line to denote that points on this line are not included in the domain. The domain includes all other points on the plane, so shade the regions on either side of the line.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Functions
A rational function is a type of function that is expressed as the ratio of two polynomials. In simpler terms, it is a fraction where both the numerator and the denominator are polynomials. In the given function, \( g(x, y) = \frac{x-y}{x+y} \), we clearly see this structure. The numerator is \( x - y \) and the denominator is \( x + y \).

Rational functions are quite common in algebra and calculus because they help describe many natural phenomena. However, they can raise challenges because the denominator cannot be zero, which directly impacts the domain of the function.
Domain of a Function
The domain of a function is the set of all possible input values (in this case, \( x \) and \( y \)) for which the function is defined. Determining the domain is crucial because it lets us know where the function "works" without any problems.

For a two-variable function like \( g(x, y) = \frac{x-y}{x+y} \), we need to find all pairs \((x, y)\) such that the function produces a real number. This involves ensuring that the denominator is not zero, which brings us to the next important aspect.
Denominator Restriction
In rational functions, denominator restriction is one of the most important considerations. This restriction means finding values of \( (x, y) \) that do not make the denominator zero.

For the function \( g(x, y) = \frac{x-y}{x+y} \), we have the denominator \( x + y \). To avoid division by zero (which is undefined), \( x + y \) must not equal zero. Therefore, we derive the line equation \( y = -x \).

Points on this line make the denominator zero and thus restrict the domain since the function is undefined at these points. Understanding this restriction is key to understanding where the function operates correctly.
Sketching a Domain
Sketching a domain helps visualize where a function is defined, especially with two variables. In our case, for \( g(x, y) \), we begin by graphing the restriction.

Using the equation \( x + y = 0 \) or equivalently \( y = -x \), we sketch this line on a coordinate plane. Since \( x + y e 0 \) indicates the domain is all points except on this line, we draw \( y = -x \) as a dashed line. This visually denotes that points on it are excluded from the domain.

Finally, to complete the sketch, shade the regions on both sides of the dashed line. These shaded areas represent valid input pairs \( (x, y) \) that define the domain of the function, thus providing a clear visual guide to where the function is operational.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Cobb and Douglas used the equation \( P(L, K) = 1.01L^{0.75}K^{0.25} \) to model the American economy from 1899 to 1922, where \( L \) is the amount of labor and \( K \) is the amount of capital. (See Example 14.1.3) (a) Calculate \( P_L \) and \( P_K \). (b) Find the marginal productivity of labor and the marginal productivity of capital in the year 1920, when \( L = 194 \) and \( K = 407 \) (compared with the assigned values \( L = 100 \) and \( K = 100 \) in 1899). Interpret the results. (c) In the year 1920, which would have benefited production more, an increase in capital investment or an increase in spending on labor?

Use a graph or level curves or both to estimate the local maximum and minimum values and saddle point(s) of the function. Then use calculus to find these values precisely. \( f(x, y) = x^2 + y^2 + x^{-2}y^{-2} \)

Graph the surface and the tangent plane at the given point. (Choose the domain and viewpoint so that you get a good view of both the surface and the tangent plane.) Then zoom in until the surface and the tangent plane become indistinguishable. \( z = x^2 + xy + 3y^2 \), \( (1, 1, 5) \)

Find the maximum and minimum volumes of a rectangular box whose surface area is \( 1500 cm^2 \) and whose total edge length is \( 200 cm \).

Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the extreme values of the function subject to the given constraint. \( f(x, y) = xy \); \( 4x^2 + y^2 = 8 \)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.