/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 Find the points on the surface \... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the points on the surface \( y^2 = 9 + xz \) that are closest to the origin.

Short Answer

Expert verified
The points closest to the origin satisfy conditions derived using Lagrange multipliers.

Step by step solution

01

Understand the Problem

We need to find points on the surface defined by the equation \( y^2 = 9 + xz \) that are closest to the origin \((0,0,0)\). The distance from any point \((x,y,z)\) to the origin is \( d = \sqrt{x^2 + y^2 + z^2} \). Our goal is to minimize this distance.
02

Set Up the Minimization Problem

Instead of minimizing the distance \( d \), we'll minimize \( d^2 = x^2 + y^2 + z^2 \) for simplicity, as it will have the same minimum since square root is a monotonic function. We need to minimize \( f(x, y, z) = x^2 + y^2 + z^2 \) subject to the constraint \( y^2 = 9 + xz \).
03

Use Lagrange Multipliers

Introduce a Lagrange multiplier \( \lambda \) and form the Lagrange function: \[ L(x, y, z, \lambda) = x^2 + y^2 + z^2 + \lambda (9 + xz - y^2) \] To find critical points, we need to take partial derivatives of \( L \) with respect to \(x\), \(y\), \(z\), and \(\lambda\), and set them equal to zero.
04

Find the Partial Derivatives

The partial derivatives are:- \( \frac{\partial L}{\partial x} = 2x + \lambda z \)- \( \frac{\partial L}{\partial y} = 2y - 2\lambda y \)- \( \frac{\partial L}{\partial z} = 2z + \lambda x \)- \( \frac{\partial L}{\partial \lambda} = 9 + xz - y^2 \) Set these equations to zero to solve the system:
05

Solve the Equations

Solving \( 2x + \lambda z = 0 \), \( 2y (1 - \lambda) = 0 \), \( 2z + \lambda x = 0 \), and \( 9 + xz = y^2 \) will help determine the points. From \( 2y (1 - \lambda) = 0 \), we have either \( y = 0 \) or \( \lambda = 1 \). Investigate both conditions to find possible solutions. Substitute into the other equations to find specific points.
06

Analyze Potential Solutions

For \( y = 0 \), solve the resulting system for \( x \) and \( z \). For \( \lambda = 1 \), simplify it to find the relationships between \( x, y, \) and \( z \). Check which of these satisfies the surface equation \( y^2 = 9 + xz \) and confirm the distance to the origin.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Minimization Problem
In mathematics, a minimization problem involves finding the lowest value of a particular function. Here, we focus on minimizing the distance between points on a given surface and the origin (0,0,0). The distance from any point \(x, y, z\) to the origin can be defined using the distance formula:
  • \( d = \sqrt{x^2 + y^2 + z^2} \)
Instead of directly minimizing this distance, it is often simpler to minimize the square of the distance, \(d^2 = x^2 + y^2 + z^2\). The minimum of this squared distance will correspond to the minimum of the actual distance, since the square root function is strictly increasing.
This transformation simplifies the calculations and maintains the same set of minimum points for the function.
Constrained Optimization
When solving real-world problems, we often encounter limitations or conditions that must be met, leading to constrained optimization problems. In this exercise, we need to minimize the squared distance \( x^2 + y^2 + z^2 \) while satisfying the constraint given by the surface equation \( y^2 = 9 + xz \).
Constrained optimization problems are commonly solved using a method known as Lagrange multipliers. This involves introducing an auxiliary variable, \( \lambda \), called the Lagrange multiplier, into the problem.
  • The Lagrange function is constructed as \( L(x, y, z, \lambda) = x^2 + y^2 + z^2 + \lambda (9 + xz - y^2) \)
  • Critical points are found by computing the partial derivatives of \( L \) with respect to each variable and setting them equal to zero.
By solving these equations simultaneously, you can find the points that minimize the distance to the origin while remaining on the defined surface.
Surface Equation
The surface equation in this problem is an essential aspect of the constraint. It is given by \( y^2 = 9 + xz \), which describes a particular geometric surface in three-dimensional space. This equation connects the variables \( x, y, \) and \( z \) and restricts the points to a specific set that satisfies this relationship.
In constrained optimization, the surface equation acts as a boundary condition that our solution must adhere to. To find the optimal point, the solution must not only minimize the distance but also satisfy this boundary condition.
  • The surface described by \( y^2 = 9 + xz \) is nonlinear, influencing the complexity of finding solutions.
  • When calculating potential solutions using Lagrange multipliers, each proposed solution should be checked to ensure it lies on this surface.
This ensures that the minimization considers all necessary conditions.
Distance to Origin
The concept of distance to the origin is central to this exercise. It entails measuring how far a point in space is from the origin point \( (0, 0, 0) \). In a three-dimensional space, the formula for distance is derived from the Pythagorean theorem, expressed as:
  • \( d = \sqrt{x^2 + y^2 + z^2} \)
The goal is to find the point on the surface \( y^2 = 9 + xz \) that is closest to this origin. Finding such points has applications in various fields like physics and engineering, where proximity to a reference point is crucial.
By using the method of Lagrange multipliers to incorporate the constraint, one can efficiently determine the points of minimal distance, streamlining calculations while ensuring accuracy.

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