/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Solve the initial-value problem ... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the initial-value problem \(y=(\sin x) / \sin y,\) \(y(0)=\pi / 2,\) and graph the solution (if your CAS does implicit plots.

Short Answer

Expert verified
The equation is implicitly solved with initial condition \( y(0) = \frac{\pi}{2} \), graph numerically.

Step by step solution

01

Identify the Type of Differential Equation

The given equation is \( y = \frac{\sin x}{\sin y} \). Note that it's an implicit function, meaning the variable \( y \) is both on the left and the right side of the equation.
02

Use Initial Conditions

We are given the initial condition \( y(0) = \frac{\pi}{2} \). This gives us the specific value of \( y \) when \( x = 0 \).
03

Attempt to Simplify or Separate

Try isolating \( y \) or otherwise work towards either explicitly expressing \( y \) in terms of \( x \), or observing the behavior at the initial condition and solving numerically.
04

Apply Numeric or Graphing Techniques

Given the complexity of the equation, consider using computer software to solve numerically or graph the function implicitly, focusing around \( x = 0 \) and \( y = \frac{\pi}{2} \).
05

Verify Graph and Solution

Review the graph or numerical solution to confirm it satisfies both the differential equation \( y = \frac{\sin x}{\sin y} \) and the initial condition \( y(0) = \frac{\pi}{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equation
Differential equations are essential in understanding how things change or evolve over time. In the simplest terms, a differential equation is an equation that involves one or more functions and their derivatives. In our example, the equation is \( y = \frac{\sin x}{\sin y} \). Here, both the variable \( x \) and the function \( y \) appear in the equation. The function \( y \) is dependent on the variable \( x \). This type of equation requires us to find a function \( y(x) \) that makes the equation true for all values of \( x \).
Differential equations are used across various fields such as physics, engineering, and economics because they describe processes that are dynamic and continuously changing, like population growth, heat transfer, or motion of objects. A crucial step in solving differential equations is identifying the function we need to solve for, which helps us understand the overall problem structure.
Implicit Function
An implicit function is a function where the dependent and independent variables are not separated on each side of the equation. In our scenario, the equation \( y = \frac{\sin x}{\sin y} \) is implicit because \( y \) appears on both sides. This makes it challenging to write \( y \) explicitly as a function of \( x \).
Implicit functions are often more complex because they require more sophisticated methods to solve. For example, graphical methods or computational tools may be utilized to understand their behavior. With implicit functions, instead of looking for a direct expression like \( y = f(x) \), it is helpful to comprehend the relationship between the variables and solve them using numerical methods or plotting. This understanding allows us to find solutions even when it's not easy to isolate \( y \).
Initial Condition
Initial conditions are specific values of the function and its derivatives at a certain point that are used to find unique solutions in differential equations. In our initial-value problem, we have \( y(0) = \frac{\pi}{2} \). This tells us the value of \( y \) when \( x = 0 \).
Initial conditions are crucial because many differential equations have more than one solution. By providing an initial condition, we can narrow down the possible solutions to a single, unique one. This is similar to giving an initial position and velocity in a physics problem, which allows us to predict the future motion of an object. Without an initial condition, the solution could be a broad family of curves rather than a single trajectory.
Numerical Solution
Numerical solutions are approaches used to approximate the solutions of complex equations, like differential equations, that may not be easily solved analytically. In our case, because the equation \( y = \frac{\sin x}{\sin y} \) is implicit and complex, finding an explicit solution for \( y \) in terms of \( x \) is challenging. This is where numerical solutions become handy.
To obtain a numerical solution, we can use computational tools, such as computer software or calculators that specialize in handling complex calculations. These tools can help graph the implicit function and observe its behavior around the initial condition, like \( x = 0 \) and \( y = \frac{\pi}{2} \), to get a visual representation of the solution.
Using numerical methods allows us to explore solutions precisely in scenarios where the equation's complexity prevents analytical methods from delivering results.

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Most popular questions from this chapter

Find the solution of the differential equation that satisfies the given initial condition. $$y^{\prime} \tan x=a+y, y(\pi / 3)=a, \quad 0

The figure shows a circuit containing an electromotive force, a capacitor with a capacitance of \(C\) farads \((\mathrm{F}),\) and a resistor with a resistance of \(R\) ohms \((\Omega) .\) The voltage drop across the capacitor is \(Q / C,\) where \(Q\) is the charge (in coulombs), so in this case Kirchhoff's Law gives $$R I+\frac{Q}{C}=E(t)$$ But \(I=d Q / d t,\) so we have $$R \frac{d Q}{d t}+\frac{1}{C} Q=E(t)$$ Suppose the resistance is \(5 \Omega,\) the capacitance is \(0.05 \mathrm{F},\) and a battery gives a constant voltage of 60 \(\mathrm{V}\) . (a) Draw a direction field for this differential equation. (b) What is the limiting value of the charge? (c) Is there an equilibrium solution? (d) If the initial charge is \(Q(0)=0 \mathrm{C}\) , use the direction field to sketch the solution curve. (e) If the initial charge is \(Q(0)=0 \mathrm{C},\) use Euler's method with step size 0.1 to estimate the charge after half a second.

Solve the differential equation. $$y^{\prime}=y^{2} \sin x$$

Use Euler's method with step size 0.5 to compute the approximate \(y\) -values \(y_{1}, y_{2}, y_{3},\) and \(y_{4}\) of the solution of the initial-value problem \(y^{\prime}=y-2 x, y(1)=0\)

Another model for a growth function for a limited population is given by the Gompertz function, which is a solution of the differential equation $$\frac{d P}{d t}=c \ln \left(\frac{K}{P}\right) P$$ where \(c\) is a constant and \(K\) is the carrying capacity. (a) Solve this differential equation. (b) Compute lim \(_{t \rightarrow \infty} P(t).\) (c) Graph the Gompertz growth function for \(K=1000\) , \(P_{0}=100,\) and \(c=0.05,\) and compare it with the logistic function in Example \(2 .\) What are the similarities? What are the differences? (d) We know from Exercise 9 that the logistic function grows fastest when \(P=K / 2 .\) Use the Gompertz differential equation to show that the Gompertz function grows fastest when \(P=K / e\) .

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