Chapter 3: Problem 48
\(47 - 50\) Find the first and second derivatives of the function. $$y = x e ^ { a }$$
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Chapter 3: Problem 48
\(47 - 50\) Find the first and second derivatives of the function. $$y = x e ^ { a }$$
These are the key concepts you need to understand to accurately answer the question.
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Find the derivative. Simplify where possible. $$h(x)=\ln (\cosh x)$$
Find the derivative. Simplify where possible. $$y=e^{\cosh 3 x}$$
Establish the following rules for working with differentials (where c denotes a constant and u and \(v\) are functions of \(x )\) . (a) \(\mathrm{dc}=0\) $$ \mathrm{d}(\mathrm{u}+v)=\mathrm{du}+\mathrm{d} v \quad \text { (d) } \mathrm{d}(\mathrm{u} v)=\mathrm{u} \mathrm{d} v+v $$ $$ \mathrm{d}\left(\frac{\mathrm{u}}{v}\right)=\frac{v \mathrm{du}-\mathrm{u} \mathrm{d} v}{v^{2}} \quad \text { (f) } \mathrm{d}\left(\mathrm{x}^{\mathrm{n}}\right)=\mathrm{nx}^{\mathrm{n}-1} \mathrm{d} \mathrm{x} $$
A water trough is 10 \(\mathrm{m}\) long and a cross-section has the shape of an isosceles trapezoid that is 30 \(\mathrm{cm}\) wide at the bottom, 80 \(\mathrm{cm}\) wide at the top, and has height 50 \(\mathrm{cm} .\) If the trough is being filled with water at the rate of 0.2 \(\mathrm{m}^{3} / \mathrm{min}\) , how fast is the water level rising when the water is 30 \(\mathrm{cm}\) deep?
\(19-22\) Compute \(\Delta y\) and dy for the given values of \(x\) and \(d x=\Delta x\) . Then sketch a diagram like Figure 5 showing the line segments with lengths dx, dy, and \Deltay. \(y=2 / x, \quad x=4, \quad \Delta x=1\)
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