Chapter 3: Problem 33
Find the derivative. Simplify where possible. $$h(x)=\ln (\cosh x)$$
Short Answer
Expert verified
The derivative is \( \tanh(x) \).
Step by step solution
01
Understand the Problem
We need to find the derivative of the function \( h(x) = \ln(\cosh x) \). Simplifying where possible is also part of the task.
02
Apply the Chain Rule
Since \( h(x) = \ln(\cosh x) \) is a composition of functions, we will use the chain rule for differentiation. Let \( f(u) = \ln(u) \) and \( u(x) = \cosh(x) \). Then \( h(x) = f(u(x)) \). The chain rule states that \( h'(x) = f'(u(x)) \cdot u'(x) \).
03
Differentiate \( f(u) = \ln(u) \)
Differentiate \( f(u) = \ln(u) \) with respect to \( u \). The derivative is \( f'(u) = \frac{1}{u} \).
04
Differentiate \( u(x) = \cosh(x) \)
Find the derivative of \( u(x) = \cosh(x) \) with respect to \( x \). Recall that \( \frac{d}{dx}[\cosh(x)] = \sinh(x) \). So, \( u'(x) = \sinh(x) \).
05
Combine Derivatives Using the Chain Rule
Substitute back into the chain rule expression: \( h'(x) = f'(u(x)) \cdot u'(x) = \frac{1}{\cosh(x)} \cdot \sinh(x) \).
06
Simplify the Expression
Use the identity \( \frac{\sinh(x)}{\cosh(x)} = \tanh(x) \) to simplify: \( h'(x) = \tanh(x) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule in Differentiation
The chain rule is a crucial concept in calculus used for differentiating composite functions. A composite function is when one function is applied to the result of another function. In simpler terms, if you have a function like \( h(x) = f(g(x)) \), you use the chain rule to find the derivative.
Here’s a step-by-step approach to using the chain rule:
Here’s a step-by-step approach to using the chain rule:
- Identify the outer function, \( f(u) \), and the inner function, \( u(x) \). For our example, \( h(x) = \ln(\cosh x) \), the outer function is \( f(u) = \ln(u) \), and the inner function is \( u(x) = \cosh(x) \).
- Differentiate the outer function concerning the inner function, which gives us \( f'(u) = \frac{1}{u} \).
- Differentiate the inner function concerning \( x \), giving us \( u'(x) = \sinh(x) \).
- Finally, multiply these two derivatives: \( h'(x) = f'(u(x)) \cdot u'(x) = \frac{1}{\cosh(x)} \cdot \sinh(x) \).
Understanding Hyperbolic Functions
Hyperbolic functions are a set of functions that are analogues of the well-known trigonometric functions but for a hyperbola, just as trigonometric functions are based on a circle. Two essential hyperbolic functions are \( \sinh(x) \) and \( \cosh(x) \).
Here's a quick outline of these key hyperbolic functions:
One critical identity to remember is the relationship \( \frac{\sinh(x)}{\cosh(x)} = \tanh(x) \), which simplifies calculations as exemplified in the problem by transforming \( \frac{\sinh(x)}{\cosh(x)} \) into \( \tanh(x) \). Understanding these identities and properties can help simplify complex calculus problems.
Here's a quick outline of these key hyperbolic functions:
- For \( \cosh(x) \), it's defined as \( \cosh(x) = \frac{e^x + e^{-x}}{2} \).
- \( \sinh(x) \) is defined as \( \sinh(x) = \frac{e^x - e^{-x}}{2} \).
One critical identity to remember is the relationship \( \frac{\sinh(x)}{\cosh(x)} = \tanh(x) \), which simplifies calculations as exemplified in the problem by transforming \( \frac{\sinh(x)}{\cosh(x)} \) into \( \tanh(x) \). Understanding these identities and properties can help simplify complex calculus problems.
Logarithmic Differentiation
Logarithmic differentiation is a method used to differentiate functions in which the traditional differentiation approach might be cumbersome, especially in handling products or quotients of functions.
Here’s how logarithmic differentiation is generally approached:
Here’s how logarithmic differentiation is generally approached:
- Start by taking the natural logarithm on both sides of the function you wish to differentiate, where applicable. This simplifies expressions that are products or powers.
- Differentiate the resulting logarithmic equation using standard differentiation rules, including the chain rule. When you differentiate \( \ln(f(x)) \), the derivative is \( \frac{1}{f(x)} \cdot f'(x) \).