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Find the radius of convergence and interval of convergence of the series. $$\sum_{n=1}^{\infty} \frac{10^{n} x^{n}}{n^{3}}$$

Short Answer

Expert verified
Radius of convergence is \( \frac{1}{10} \), interval is \( ( -\frac{1}{10}, \frac{1}{10} ) \).

Step by step solution

01

Identify the Series

The series given is \( \sum_{n=1}^{\infty} \frac{10^{n} x^{n}}{n^{3}} \). This is a power series in terms of \( x \), characterized by the general term \( a_n = \frac{10^n x^n}{n^3} \).
02

Apply the Ratio Test

To find the radius of convergence, we use the ratio test. Compute the limit \( L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \). Substitute \( a_{n} = \frac{10^n x^n}{n^3} \) to get: \[ L = \lim_{n \to \infty} \left| \frac{10^{n+1} x^{n+1}}{(n+1)^3} \times \frac{n^3}{10^n x^n} \right| = |10x| \lim_{n \to \infty} \frac{n^3}{(n+1)^3} \].
03

Evaluate the Limit

We need to evaluate the limit \( \lim_{n \to \infty} \frac{n^3}{(n+1)^3} \). Simplify the expression to get \( \frac{n^3}{(n^3 + 3n^2 + 3n + 1)} \). As \( n \to \infty \), \( \frac{n^3}{n^3 + 3n^2 + 3n + 1} \to 1 \). Thus, the limit is \( 1 \).
04

Determine Radius of Convergence

Substitute the result from the limit into the ratio test: \( L = |10x| \times 1 = |10x| \). For convergence, \( L < 1 \). Therefore, \( |10x| < 1 \), leading to \( |x| < \frac{1}{10} \). Hence, the radius of convergence \( R = \frac{1}{10} \).
05

Find Interval of Convergence

The interval of convergence is based on the inequality \( |x| < \frac{1}{10} \), thus \( -\frac{1}{10} < x < \frac{1}{10} \). The ratio test doesn't provide information on convergence at endpoints, so we check for convergence separately using other tests if needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interval of Convergence
When working with power series, understanding the interval of convergence is crucial. This interval is essentially the set of all values of the variable for which the series converges. In our problem, the series is defined with respect to the variable \( x \), and we found that it converges when
  • \(-\frac{1}{10} < x < \frac{1}{10}\)
This interval is derived from the inequality resulting from the ratio test. An important point to note is the series might not converge at the endpoints \( x = -\frac{1}{10} \) and \( x = \frac{1}{10} \). Therefore, convergence at these endpoints must be checked separately. This can involve applying different tests like the Alternating Series Test or the p-series Test, depending on the series' behavior at those specific points.
Power Series
A power series is a series of the form \( \sum_{n=0}^{\infty} c_n (x-a)^n \), which is a polynomial with infinitely many terms. In this exercise, the series \( \sum_{n=1}^{\infty} \frac{10^n x^n}{n^3} \) is already in a form where the center is \( a = 0 \), making it a simple power series about zero.
Power series converge based on the value of \( x \) relative to its coefficients and degree. The convergence can be tested using methods such as the ratio test to determine a range of \( x \) called the "interval of convergence."
Understanding power series is essential in many areas including calculus and differential equations, as they can represent functions as sums of infinite terms, providing a way to analyze functions that are otherwise difficult to handle.
Ratio Test
The ratio test is a popular method for determining the radius of convergence of a power series. We apply it by examining the limit of the ratio of consecutive terms in the series. For our series, we computed:
  • \( L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = |10x| \cdot 1 \)
The result, \( L = |10x| \), indicates the series converges when \( L < 1 \), leading us to the criterion \( |x| < \frac{1}{10} \).
The ratio test is useful because it provides an easy-to-compute condition for the convergence of power series. It works particularly well when the series’ terms are composed of factorial or exponential elements, making it a common choice for handling geometric or growth series.
Convergence of Series
The concept of convergence in series is about determining when an infinite series approaches a specific value as more terms are added. For any series, including power series, convergence occurs if the sum of its infinite terms is finite.
There are different tests for checking convergence, such as the ratio test, which we used here. For the series \( \sum_{n=1}^{\infty} \frac{10^n x^n}{n^3} \), convergence depended on finding when the series satisfies \( |x| < \frac{1}{10} \).
Understanding convergence helps decide the validity and usefulness of a series in approximating functions and solving mathematical problems, especially in fields like mathematical analysis and applied mathematics where series often represent complex functions.

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Most popular questions from this chapter

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