/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Graph several level curves of th... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graph several level curves of the following functions using the given window. Label at least two level curves with their z-values. $$z=\sqrt{y-x^{2}-1} ;[-5,5] \times[-5,5]$$

Short Answer

Expert verified
The equation of the level curve for z = 1 is $$y = x^2 + 2$$, and for z = 2, it is $$y = x^2 + 5$$.

Step by step solution

01

Rewrite the function for level curves

First, we will rewrite the given function in terms of level curves by setting z = constant (representing a constant height on the surface). Let's set this constant as c, so we have: $$c= \sqrt{y-x^{2}-1}$$
02

Solve for y

Now, we will solve for y in terms of x and c, to find the equation of the level curves on the xy-plane. First, we will square both sides of the equation to get rid of the square root: $$c^{2}= y-x^{2}-1$$ Now, solve for y: $$y = c^{2}+x^{2}+1$$
03

Find level curves for different z-values

Now that we have y in terms of x and c, we will find the level curves (y = f(x)) for different z-values. We can do this by setting different values for c and observing the shape of the curve. We will start with c = 1 and c = 2. For c = 1: $$y = 1^{2}+x^{2}+1 = x^{2}+2$$ For c = 2: $$y = 2^{2}+x^{2}+1 = x^{2}+5$$
04

Plot the level curves

Now we will plot the level curves on the xy-plane within the given window ([-5,5] x [-5,5]). For c = 1, the level curve will be a parabola with vertex (0, 2) and opening upwards. For c = 2, the level curve will also be a parabola with vertex (0, 5) and opening upwards.
05

Label the level curves

Lastly, we need to label at least two level curves with their z-values. Since we used c = 1 and c = 2, we will label the respective level curves: Level curve with c = 1: $$z = \sqrt{y-x^{2}-1}$$ at c = 1 is the curve $$y = x^2 + 2$$ Level curve with c = 2: $$z = \sqrt{y-x^{2}-1}$$ at c = 2 is the curve $$y = x^2 + 5$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Plotting Level Curves
Understanding the concept of plotting level curves is essential in visualizing how a function behaves across different values. A level curve represents points in 2-D where a function takes on a constant value. Imagine walking along a mountainside at a constant altitude to understand the analogy in three dimensions.

When visualizing the function \(z = \sqrt{y - x^2 - 1}\), with \(z\) representing height, setting \(z\) to be a constant allows us to see the 'trail' we'd walk at that constant height on the 3-D surface. By setting \(z\) to different constants, we get various level curves, each corresponding to a 'contour line' on a map. To visualize these curves, we replace \(z\) with a constant value and solve the equation for \(y\) in terms of \(x\), which we did by squaring both sides to eliminate the square root. The resulting parabolas for different values of \(c\) reveal how the surface changes elevation.

Plotting these curves on the \([-5,5]\) window gives a picture of the surface sliced at different heights. Labeling each curve with its corresponding \(z\)-value allows us to understand at which height each curve lies, much like denoting elevations on a topographic map. It is a powerful visual aid that translates a complex 3-D shape into comprehensive 2-D diagrams.
Solving for y in Equations
In calculus, solving for \(y\) in equations is a fundamental skill that allows for the graphing of functions and understanding their behavior. In our example, to find the level curves, we first transformed the 3-D equation \(z = \sqrt{y - x^2 - 1}\) into a 2-D perspective, representing different heights (\(z\)-values) as distinct curves on the \(xy\)-plane.

Starting with \(c = \sqrt{y - x^2 - 1}\), we squared both sides to eliminate the square root, obtaining \(c^2 = y - x^2 - 1\). Then, re-arranging for \(y\), we got our level curve equation \(y = c^2 + x^2 + 1\). This skill of isolating \(y\) is crucial. In doing so, one can input any \(x\)-value and easily determine the corresponding \(y\)-value on the curve, making plotting possible.

By practicing how to solve for \(y\) in various equations, students not only prepare for plotting level curves but also gain the ability to tackle more complex mathematical analysis and problem-solving tasks.
Graphing Parabolas
When the function we're examining is quadratic in nature, such as the level curves \(y = x^2 + 2\) and \(y = x^2 + 5\), we are essentially dealing with graphing parabolas. A parabola is a U-shaped curve that can open up or down, depending on the sign of the leading coefficient in its equation.

In the context of level curves, these parabolas represent cross-sections of a 3-D graph at specific \(z\)-values. If we plot the parabolas obtained for each level on the \(xy\)-plane, we see the shape of the curve and understand how the function behaves horizontally at those levels. This understanding is vital for interpreting the shape and features of the 3-D graph represented by the original function.

To graph a parabola, we find the vertex, which in the case of \(y = x^2 + 2\) is at \((0, 2)\), and for \(y = x^2 + 5\) it's at \((0, 5)\). The vertex forms the lowest point on the curve when it opens upwards as ours do. We then plot additional points by substituting \(x\)-values into the equation and connecting these points smoothly. Doing this provides a clear picture of how the function's value changes with \(x\) at that level.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Graph several level curves of the following functions using the given window. Label at least two level curves with their z-values. $$z=\sqrt{25-x^{2}-y^{2}} ;[-6,6] \times[-6,6]$$

A snapshot (frozen in time) of a set of water waves is described by the function \(z=1+\sin (x-y),\) where \(z\) gives the height of the waves and \((x, y)\) are coordinates in the horizontal plane \(z=0\) a. Use a graphing utility to graph \(z=1+\sin (x-y)\) b. The crests and the troughs of the waves are aligned in the direction in which the height function has zero change. Find the direction in which the crests and troughs are aligned. c. If you were surfing on one of these waves and wanted the steepest descent from the crest to the trough, in which direction would you point your surfboard (given in terms of a unit vector in the \(x y\) -plane)? d. Check that your answers to parts (b) and (c) are consistent with the graph of part (a).

Differentials with more than two variables Write the differential dw in terms of the differentials of the independent variables. $$w=f(x, y, z)=x y^{2}+x^{2} z+y z^{2}$$

a. Determine the domain and range of the following functions. b. Graph each function using a graphing utility. Be sure to experiment with the window and orientation to give the best perspective on the surface. $$p(x, y)=1-|x-1|+|y+1|$$

Travel cost The cost of a trip that is \(L\) miles long, driving a car that gets \(m\) miles per gallon, with gas costs of \(\$ p /\) gal is \(C=L p / m\) dollars. Suppose you plan a trip of \(L=1500 \mathrm{mi}\) in a car that gets \(m=32 \mathrm{mi} / \mathrm{gal},\) with gas costs of \(p=\$ 3.80 / \mathrm{gal}\) a. Explain how the cost function is derived. b. Compute the partial derivatives \(C_{L}, C_{m^{\prime}}\) and \(C_{p^{\prime}}\). Explain the meaning of the signs of the derivatives in the context of this problem. c. Estimate the change in the total cost of the trip if \(L\) changes from \(L=1500\) to \(L=1520, m\) changes from \(m=32\) to \(m=31,\) and \(p\) changes from \(p=\$ 3.80\) to \(p=\$ 3.85\) d. Is the total cost of the trip (with \(L=1500 \mathrm{mi}, m=32 \mathrm{mi} / \mathrm{gal}\). and \(p=\$ 3.80\) ) more sensitive to a \(1 \%\) change in \(L,\) in \(m,\) or in \(p\) (assuming the other two variables are fixed)? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.