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Differentials with more than two variables Write the differential dw in terms of the differentials of the independent variables. $$w=f(x, y, z)=x y^{2}+x^{2} z+y z^{2}$$

Short Answer

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Question: Find the differential dw of the function $$w = f(x, y, z) = xy^2 + x^2z + yz^2$$ in terms of the differentials of the independent variables x, y, and z. Answer: The differential dw is given by $$dw = (y^2 + 2xz) dx + (2xy + z^2) dy + (x^2 + 2yz) dz$$.

Step by step solution

01

Compute the partial derivatives.

First, we need to compute the partial derivatives of the function f(x, y, z) with respect to x, y, and z. These are as follows: Partial derivative with respect to x: $$\frac{\partial w}{\partial x} = \frac{\partial}{\partial x}(xy^2 + x^2z + yz^2) = y^2 + 2xz$$ Partial derivative with respect to y: $$\frac{\partial w}{\partial y} = \frac{\partial}{\partial y}(xy^2 + x^2z + yz^2) = 2xy + z^2$$ Partial derivative with respect to z: $$\frac{\partial w}{\partial z} = \frac{\partial}{\partial z}(xy^2 + x^2z + yz^2) = x^2 + 2yz$$
02

Compute the differential dw in terms of dx, dy, and dz.

Now, we use the partial derivatives to find the differential dw in terms of the differentials dx, dy, and dz. According to the multivariable chain rule, we have: $$dw = \frac{\partial w}{\partial x} dx + \frac{\partial w}{\partial y} dy + \frac{\partial w}{\partial z} dz$$ Substitute the partial derivatives that we have computed in step 1, and we get: $$dw = (y^2 + 2xz) dx + (2xy + z^2) dy + (x^2 + 2yz) dz$$ Therefore, the differential dw in terms of the differentials of the independent variables x, y, and z is: $$dw = (y^2 + 2xz) dx + (2xy + z^2) dy + (x^2 + 2yz) dz$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Calculus
Differential calculus is the branch of calculus that focuses on how functions change when their inputs change. It is all about understanding the concept of the derivative, which is a way to measure how fast something is changing at any given point. In our context, when dealing with multiple variables, differential calculus helps us explore how a function involving several variables changes when each of those variables is slightly varied. Understanding derivatives in differential calculus is essential to analyzing and predicting the changes in complex systems. It allows us to
  • Determine rates of change
  • Find slopes of tangent lines
  • Analyze local extrema
  • Model real-world phenomena
Differential calculus works hand in hand with integral calculus to form the fundamental backbone of mathematical analysis.
Partial Derivatives
When working with functions of more than one variable, we use partial derivatives. A partial derivative is a derivative where you hold some variables constant while differentiating with respect to another. For a function like \(w=f(x,y,z)\), the partial derivative with respect to \(x\) is found by treating \(y\) and \(z\) as constants.For example, the partial derivatives for our function given in the exercise are:
  • With respect to \(x\): \(\frac{\partial w}{\partial x} = y^2 + 2xz\)
  • With respect to \(y\): \(\frac{\partial w}{\partial y} = 2xy + z^2\)
  • With respect to \(z\): \(\frac{\partial w}{\partial z} = x^2 + 2yz\)
The beauty of partial derivatives is that they allow us to understand how each variable influences the function on its own. This is crucial in fields such as physics and engineering, where multiple variables affect the behavior of systems.
Chain Rule
The chain rule is a fundamental concept in calculus that comes into play when dealing with composite functions. In multivariable calculus, a form of the chain rule helps compute the differential of a function in terms of its independent variables. The multivariable chain rule can be expressed as:\[dw = \frac{\partial w}{\partial x} dx + \frac{\partial w}{\partial y} dy + \frac{\partial w}{\partial z} dz\]This shows how the change in the function \(w\) relates to small changes \(dx\), \(dy\), and \(dz\) in variables \(x\), \(y\), and \(z\). The partial derivatives serve as scaling factors that tell us how much \(w\) changes with each variable's differential.The chain rule is especially useful in predicting the behavior of functions under simultaneous small changes and is foundational in optimization problems and sensitivity analysis.
Independent Variables
In calculus, independent variables are the inputs of the function that can vary freely. When we talk about finding the differential \(dw\) of a function \(w=f(x, y, z)\), \(x\), \(y\), and \(z\) serve as independent variables.These variables are termed "independent" because they can change without being dependent on each other. This independence is crucial for partial derivatives: it allows us to assess the impact of each variable on the output separately.Understanding independent variables is key when:
  • Modeling systems with multiple inputs
  • Identifying the contribution of each variable
  • Conducting experiments where variables can be controlled individually
By recognizing which variables are independent, we can accurately apply techniques like partial differentiation and leverage them to solve complex problems intuitively.

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Most popular questions from this chapter

Determine whether the following statements are true and give an explanation or counterexample. a. The domain of the function \(f(x, y)=1-|x-y|\) is \(\\{(x, y): x \geq y\\}\). b. The domain of the function \(Q=g(w, x, y, z)\) is a region in \(\mathbb{R}^{3}\). c. All level curves of the plane \(z=2 x-3 y\) are lines.

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. a. The planes tangent to the cylinder \(x^{2}+y^{2}=1\) in \(R^{3}\) all have the form \(a x+b z+c=0\) b. Suppose \(w=x y / z,\) for \(x>0, y>0,\) and \(z>0 .\) A decrease in \(z\) with \(x\) and \(y\) fixed results in an increase in \(w\) c. The gradient \(\nabla F(a, b, c)\) lies in the plane tangent to the surface \(F(x, y, z)=0\) at \((a, b, c)\)

Potential functions Potential functions arise frequently in physics and engineering. A potential function has the property that a field of interest (for example, an electric field, a gravitational field, or a velocity field) is the gradient of the potential (or sometimes the negative of the gradient of the potential). (Potential functions are considered in depth in Chapter \(17 .)\) In two dimensions, the motion of an ideal fluid (an incompressible and irrotational fluid) is governed by a velocity potential \(\varphi .\) The velocity components of the fluid, \(u\) in the \(x\) -direction and \(v\) in the \(y\) -direction, are given by \(\langle u, v\rangle=\nabla \varphi .\) Find the velocity components associated with the velocity potential \(\varphi(x, y)=\sin \pi x \sin 2 \pi y\)

a. Determine the domain and range of the following functions. b. Graph each function using a graphing utility. Be sure to experiment with the window and orientation to give the best perspective on the surface. $$G(x, y)=\ln (2+\sin (x+y))$$

Suppose you make a one-time deposit of \(P\) dollars into a savings account that earns interest at an annual rate of \(p \%\) compounded continuously. The balance in the account after \(t\) years is \(B(P, r, t)=P e^{r^{n}},\) where \(r=p / 100\) (for example, if the annual interest rate is \(4 \%,\) then \(r=0.04\) ). Let the interest rate be fixed at \(r=0.04\) a. With a target balance of \(\$ 2000\), find the set of all points \((P, t)\) that satisfy \(B=2000 .\) This curve gives all deposits \(P\) and times \(t\) that result in a balance of \(\$ 2000\). b. Repeat part (a) with \(B=\$ 500, \$ 1000, \$ 1500,\) and \(\$ 2500,\) and draw the resulting level curves of the balance function. c. In general, on one level curve, if \(t\) increases, does \(P\) increase or decrease?

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