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Limits of sequences Write the terms \(a_{1}, a_{2}, a_{3},\) and \(a_{4}\) of the following sequences. If the sequence appears to comerge, make a conjecture about its limit. If the sequence diverges, explain why. $$a_{n}=10^{n}-1 ; n=1,2,3, \ldots$$

Short Answer

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Question: Determine the first four terms of the sequence \(a_n = 10^n - 1\) and state whether the sequence converges or diverges. Answer: The first four terms of the sequence are \(a_1 = 9\), \(a_2 = 99\), \(a_3 = 999\), and \(a_4 = 9999\). The sequence diverges as the terms tend towards infinity with increasing \(n\).

Step by step solution

01

Compute the first four terms of the sequence

To find the first four terms, we'll replace \(n\) with 1, 2, 3, and 4 in the given formula \(a_n = 10^n - 1\). \(a_1 = 10^1 - 1 = 9\) \(a_2 = 10^2 - 1 = 99\) \(a_3 = 10^3 - 1 = 999\) \(a_4 = 10^4 - 1 = 9999\)
02

Identify the behavior of the sequence

Let's analyze the behavior of this sequence. As we can observe, the terms of the sequence get larger and larger as \(n\) increases. As \(n\) goes to infinity, \(10^n\) will also go to infinity. Therefore, the terms of the sequence will diverge to infinity.
03

Determine if the sequence converges or diverges

Since the terms of the sequence tend to infinity as \(n\) increases, we can conclude that the sequence does not converge. Instead, it diverges. In conclusion, the first four terms of the sequence are \(a_1 = 9\), \(a_2 = 99\), \(a_3 = 999\), and \(a_4 = 9999\). The sequence is diverging as the terms tend towards infinity with increasing \(n\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sequence Convergence
Understanding sequence convergence is essential for analyzing how sequences behave as their terms progress. A sequence is said to converge if the terms get arbitrarily close to a specific number, known as the limit, as the sequence progresses towards infinity. This means that for each small, positive number (let’s call it epsilon), there exists a point in the sequence such that all subsequent terms are within epsilon of the limit. For example, the sequence \(1 / 2^n\) converges to 0.

In mathematical terms, a sequence \(a_n\) converges to a limit L if, for every positive number epsilon, there is a corresponding natural number N such that for all \(n > N\), the terms of the sequence \(a_n\) satisfy the condition \( |a_n - L| < epsilon \). Convergent sequences have many important applications, especially in areas such as calculus and analysis, where understanding the behavior of functions and series at infinity is crucial.
Sequence Divergence
In contrast to convergence, sequence divergence occurs when the terms of a sequence do not approach a finite limit as they progress. Instead of getting closer and closer to a certain value, the terms might either increase or decrease without bound or oscillate without settling down to a specific value.

An illustrative example of divergence can be seen in the sequence given by \(a_n = 10^n - 1\), which was outlined in the original exercise. As we calculate the terms \(a_1 = 9\), \(a_2 = 99\), \(a_3 = 999\), and \(a_4 = 9999\), it’s apparent that as \(n\) increases, the terms increase exponentially. In formal terms, a sequence \(a_n\) diverges if we cannot find a finite limit L such that the condition for convergence is fulfilled. Instead, we may find that \(a_n\) tends towards infinity, towards negative infinity, or fails to approach a specific value entirely.
Exponential Sequences
When each term of a sequence is formed by raising a fixed number to a power that increases with each successive term, we have an exponential sequence. These sequences, represented by the general form \(a_n = b^n\), where b is a constant base and \(n\) is the position in the sequence, can show drastically different behaviors based on the value of b.

If b is greater than 1, as in the sequence \(10^n - 1\), the terms grow rapidly and the sequence diverges to infinity. This exponential growth can often be observed in contexts like population dynamics, compounding interest rates, and certain natural processes. In contrast, if b is a positive number less than 1, the sequence will converge to 0, exhibiting exponential decay. Understanding the nature of exponential sequences allows us to predict their long-term behavior, which is especially useful in the fields of finance, computer science, and physics. With exponential sequences, it is often the rate of growth or decay that holds key insights into the underlying processes they model.

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Most popular questions from this chapter

Zeno's paradox The Greek philosopher Zeno of Elea (who lived about 450 B.C.) invented many paradoxes, the most famous of which tells of a race between the swift warrior Achilles and a tortoise. Zeno argued as follows. The slower when running will never be overtaken by the quicker; for that which is pursuing must first reach the point from which that which is fleeing started, so that the slower must necessarily always be some distance ahead. In other words, giving the tortoise a head start ensures that Achilles will never overtake the tortoise because every time Achilles reaches the point where the tortoise was, the tortoise has moved ahead. Resolve this paradox by assuming Achilles gives the tortoise a 1 -mi head start and runs \(5 \mathrm{mi} / \mathrm{hr}\) to the tortoise's \(1 \mathrm{mi} / \mathrm{hr.}\) How far does Achilles run before he overtakes the tortoise, and how long does it take?

Determine whether the following sequences converge or diverge, and state whether they are monotonic or whether they oscillate. Give the limit when the sequence converges. $$\left\\{(-0.7)^{n}\right\\}$$

Fixed-point iteration A method for estimating a solution to the equation \(x=f(x)\). known as fixed-point iteration, is based on the following recurrence relation. Let \(x_{0}=c\) and \(x_{n+1}=f\left(x_{n}\right)\) for \(n=1,2,3, \ldots\) and a real number \(c .\) lf the sequence \(\left\\{x_{n}\right\\}_{n=0}^{\infty}\) converges to \(L\), then \(L\) is a solution to the equation \(x=f(x)\) and \(L\) is called a fixed point of \(f .\) To estimate \(L\) with \(p\) digits of accuracy to the right of the decimal point, we can compute the terms of the sequence \(\left\\{x_{n}\right\\}_{n=0}^{\infty}\) until two successive values agree to \(p\) digits of accuracy. Use fixed-point iteration to find a solution to the following equations with \(p=3\) digits of accuracy using the given value of \(x_{0}\) $$x=\frac{\sqrt{x^{3}+1}}{20} ; x_{0}=5$$

James begins a savings plan in which he deposits \(\$ 100\) at the beginning of each month into an account that earns \(9 \%\) interest annually or, equivalently, \(0.75 \%\) per month. To be clear, on the first day of each month, the bank adds \(0.75 \%\) of the current balance as interest, and then James deposits \(\$ 100 .\) Let \(B_{n}\) be the balance in the account after the \(n\) th payment, where \(B_{0}=\$ 0\) a. Write the first five terms of the sequence \(\left\\{B_{n}\right\\}\) b. Find a recurrence relation that generates the sequence \(\left\\{B_{n}\right\\}\) c. How many months are needed to reach a balance of \(\$ 5000 ?\)

The famous Fibonacci sequence was proposed by Leonardo Pisano, also known as Fibonacci, in about A.D. 1200 as a model for the growth of rabbit populations. It is given by the recurrence relation \(f_{n+1}=f_{n}+f_{n-1},\) for \(n=1,2,3, \ldots,\) where \(f_{0}=1\) and \(f_{1}=1 .\) Each term of the sequence is the sum of its two predecessors. a. Write out the first ten terms of the sequence. b. Is the sequence bounded? c. Estimate or determine \(\varphi=\lim _{n \rightarrow \infty} \frac{f_{n+1}}{f_{n}},\) the ratio of the successive terms of the sequence. Provide evidence that \(\varphi=\frac{1+\sqrt{5}}{2},\) a number known as the golden mean. d. Use induction to verify the remarkable result that \(f_{n}=\frac{1}{\sqrt{5}}\left(\varphi^{n}-(-1)^{n} \varphi^{-n}\right)\)

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