Periodic savings Suppose you deposit m dollars at the beginning of every month
in a savings account that earns a monthly interest rate of \(r\), which is the
annual interest rate divided by 12 (for example, if the annual interest rate
is \(2.4 \%, r=0.024 / 12=0.002) .\) For an initial investment of \(m\) dollars,
the amount of money in your account at the beginning of the second month is
the sum of your second deposit and your initial deposit plus interest, or
\(m+m(1+r) .\) Continuing in this fashion, it can be shown that the amount of
money in your account after \(n\) months is \(A_{n}=m+m(1+r)+\cdots+m(1+r)^{n-1}
.\) Use geometric sums to determine the amount of money in your savings account
after 5 years (60 months) using the given monthly deposit and interest rate.
Monthly deposits of 250 dollars at a monthly interest rate of \(0.2 \%\)