/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 Find the values of the parameter... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the values of the parameter \(p>0\) for which the following series converge. $$\sum_{k=2}^{\infty} \frac{1}{k(\ln k)(\ln \ln k)^{p}}$$

Short Answer

Expert verified
**Answer:** The series converges for all values of \(p > 0\).

Step by step solution

01

State the given series

Let's consider the following series: $$\sum_{k=2}^{\infty} \frac{1}{k(\ln k)(\ln \ln k)^{p}}$$
02

Check conditions for the integral test

We have a function \(f(k) = \frac{1}{k(\ln k)(\ln \ln k)^{p}}\) which is positive, continuous, and decreasing for all \(k \geq 2\).
03

Calculate the improper integral

Now, we need to evaluate the following improper integral: $$\int_{2}^{\infty} \frac{1}{k(\ln k)(\ln \ln k)^{p}} dk$$ Let \(u = \ln \ln k\). Then, \(\frac{du}{dk} = \frac{1}{k \ln k}\). So, \(dk = k \ln k du\). The bounds of integration also need to be changed; as \(k=2\), \(u=\ln \ln 2\), and as \(k \to \infty\), \(u \to \infty\). The integral now becomes: $$\int_{\ln \ln 2}^{\infty} \frac{k \ln k du}{k(\ln k)(\ln \ln k)^{p}}$$ Now, we can cancel the \(k\) and \(\ln k\) terms: $$\int_{\ln \ln 2}^{\infty} \frac{du}{(\ln \ln k)^{p}}$$ The integral further becomes: $$\int_{\ln \ln 2}^{\infty} \frac{du}{u^{p}}$$
04

Determine the convergence of the integral

Now, we calculate the integral: $$\int_{\ln \ln 2}^{\infty} \frac{du}{u^{p}} = \frac{1}{1-p}u^{1-p}\Big|_{\ln \ln 2}^{\infty}$$ For the integral to converge, we need the exponent of \(u\) to be less than \(1\), i.e. \((1-p) < 1\). This gives us \(p>0\), which is the same condition given in the problem. Thus, the integral converges for all \(p>0\).
05

Conclude the convergence of the series

Since the integral converges for all \(p > 0\), by the integral test, the given series also converges for all \(p > 0\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integral Test
Understanding whether an infinite series converges or diverges is made simpler with the integral test. This test compares a series to an improper integral to determine convergence. Specifically, for a series \( \sum_{k=1}^{\infty} f(k) \), where \( f(k) \) is a positive, continuous, and monotonic decreasing function for \( k \geq a \), one can look at the corresponding integral \( \int_{a}^{\infty} f(x) \, dx \). If the integral converges, so does the series, and if the integral diverges, the series diverges as well.

When applying the integral test, there are several points to remember: The function \( f \) should be positive and decreasing over the range of summation. This means that as \( k \) increases, \( f(k) \) decreases. Additionally, \( f \) must be continuous on that interval. If the function doesn’t meet these criteria, the integral test cannot be used. In the given exercise, we considered \( f(k) = \frac{1}{k(\ln k)(\ln \ln k)^{p}} \), verified it met these conditions, and thus, the integral test was applicable.
Improper Integral
An improper integral involves integration over an unbounded interval or with an integrand that approaches infinity at one or more points in the interval of integration. In the case of \( \int_{a}^{\infty} f(x) \, dx \), where \( a \) is finite, the integral is called improper because it deals with an infinite upper limit.

To evaluate such an integral, we usually turn it into a limit problem. We replace the infinity with a variable like \( t \) and then evaluate \( \int_{a}^{t} f(x) \, dx \) as \( t \) approaches infinity. If the limit exists, the improper integral converges, otherwise, it diverges. In the exercise, we faced the improper integral \( \int_{2}^{\infty} \frac{1}{k(\ln k)(\ln \ln k)^{p}} \, dk \) and used substitution to make the evaluation feasible, leading us to handle \( \int_{\ln \ln 2}^{\infty} \frac{du}{u^{p}} \) instead.
Series Convergence Criteria
Infinity poses unique challenges when it comes to series, and as such, mathematicians have developed a set of criteria to determine when an infinite series converges. Some of these include the integral test, the comparison test, the ratio test, the root test, and the alternating series test, among others.

Each test has its own set of conditions for application. Generally, these tests verify whether the sum of the infinite terms in the series approaches a finite value. When we assess the convergence of a series using the integral test, we check for the convergence of an improper integral. If the improper integral of the sequence’s function over an infinite interval is finite, the series converges. The exercise demonstrated this approach, leading to the conclusion that the series converges for all \( p > 0 \), satisfying the given convergence criteria.
Convergence of Infinite Series
An infinite series is a sum of infinitely many terms. A fundamental question we ask is whether the series converges—to which a single value does the sum approach—or diverges—where the sum grows without bound or oscillates indefinitely. Convergence is crucial for infinite series to be useful in mathematical analysis and applications. Without convergence, the value of a series cannot be accurately expressed or utilized.

In the series \( \sum_{k=2}^{\infty} \frac{1}{k(\ln k)(\ln \ln k)^{p}} \), by employing the integral test and evaluating the improper integral, we determined that the series converges for all \( p > 0 \). This finding not only helps in the understanding of the behavior of this particular series but also in the broader context of series analysis, where similar techniques can be used to understand different series.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Evaluate the limit of the following sequences or state that the limit does not exist. $$a_{n}=\cos \left(0.99^{n}\right)+\frac{7^{n}+9^{n}}{63^{n}}$$

A ball is thrown upward to a height of \(h_{0}\) meters. After each bounce, the ball rebounds to a fraction r of its previous height. Let \(h_{n}\) be the height after the nth bounce and let \(S_{n}\) be the total distance the ball has traveled at the moment of the nth bounce. a. Find the first four terms of the sequence \(\left\\{S_{n}\right\\}\) b. Make a table of 20 terms of the sequence \(\left\\{S_{n}\right\\}\) and determine \(a\) plausible value for the limit of \(\left\\{S_{n}\right\\}\) $$h_{0}=20, r=0.75$$

Consider the sequence \(\left\\{F_{n}\right\\}\) defined by $$F_{n}=\sum_{k=1}^{\infty} \frac{1}{k(k+n)},$$ for \(n=0,1,2, \ldots . .\) When \(n=0,\) the series is a \(p\) -series, and we have \(F_{0}=\pi^{2} / 6\) (Exercises 65 and 66 ). a. Explain why \(\left\\{F_{n}\right\\}\) is a decreasing sequence. b. Plot \(\left\\{F_{n}\right\\},\) for \(n=1,2, \ldots, 20\). c. Based on your experiments, make a conjecture about \(\lim _{n \rightarrow \infty} F_{n}\).

Suppose an alternating series \(\sum(-1)^{k} a_{k}\) with terms that are non increasing in magnitude, converges to \(S\) and the sum of the first \(n\) terms of the series is \(S_{n} .\) Suppose also that the difference between the magnitudes of consecutive terms decreases with \(k .\) It can be shown that for \(n \geq 1\) \(\left|S-\left(S_{n}+\frac{(-1)^{n+1} a_{n+1}}{2}\right)\right| \leq \frac{1}{2}\left|a_{n+1}-a_{n+2}\right|\) a. Interpret this inequality and explain why it is a better approximation to \(S\) than \(S_{n}\) b. For the following series, determine how many terms of the series are needed to approximate its exact value with an error less than \(10^{-6}\) using both \(S_{n}\) and the method explained in part (a). (i) \(\sum_{k=1}^{\infty} \frac{(-1)^{k}}{k}\) (ii) \(\sum_{k=2}^{\infty} \frac{(-1)^{k}}{k \ln k}\) (iii) \(\sum_{k=2}^{\infty} \frac{(-1)^{k}}{\sqrt{k}}\)

Consider the following situations that generate a sequence. a. Write out the first five terms of the sequence. b. Find an explicit formula for the terms of the sequence. c. Find a recurrence relation that generates the sequence. d. Using a calculator or a graphing utility, estimate the limit of the sequence or state that it does not exist. The Consumer Price Index (the CPI is a measure of the U.S. cost of living) is given a base value of 100 in the year \(1984 .\) Assume the CPI has increased by an average of \(3 \%\) per year since \(1984 .\) Let \(c_{n}\) be the CPI \(n\) years after \(1984,\) where \(c_{0}=100\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.