/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Find the indicated Trapezoid Rul... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the indicated Trapezoid Rule approximations to the following integrals. \(\int_{0}^{1} \sin \pi x d x\) using \(n=6\) subintervals

Short Answer

Expert verified
Answer: The Trapezoid Rule approximation of the integral is approximately \(\frac{1}{12} [8 + 4\sqrt{3}]\).

Step by step solution

01

1. Determine the width of each subinterval

Since the integral ranges from 0 to 1 and we have 6 subintervals, the width of each subinterval, denoted as \(\Delta x\), can be calculated as: \(\Delta x = \frac{1 - 0}{6} = \frac{1}{6}\)
02

2. Find the function values at the endpoints of the subintervals

Since we have 6 subintervals, there will be a total of 7 function values, including the endpoints: \(x_0 = 0\), \(x_1 = \frac{1}{6}\), \(x_2 = \frac{1}{3}\), \(x_3 = \frac{1}{2}\), \(x_4 = \frac{2}{3}\), \(x_5 = \frac{5}{6}\), and \(x_6 = 1\). The function is given by \(f(x) = \sin \pi x\). Thus, the function values are as follows: $$ f(x_i) = \sin \pi x_i \textrm{ for } i = 0, 1, 2, 3, 4, 5, 6 $$
03

3. Apply the Trapezoid Rule formula

The Trapezoid Rule formula is given by: $$ T_n = \frac{\Delta x}{2} [f(x_0) + 2f(x_1) + 2f(x_2) + \cdots + 2f(x_{n-1}) + f(x_n)] $$ Plugging in our values for \(\Delta x\), \(f(x_0), \dots, f(x_6)\), we get: $$ T_6 = \frac{1}{12} [f(0) + 2f\left(\frac{1}{6}\right) + 2f\left(\frac{1}{3}\right) + 2f\left(\frac{1}{2}\right) + 2f\left(\frac{2}{3}\right) + 2f\left(\frac{5}{6}\right) + f(1)] $$
04

4. Calculate the approximation of the integral

To calculate the approximation of the integral, simply evaluate the function values and plug them into the equation for \(T_6\): $$ T_6 = \frac{1}{12} [\sin(0\pi) + 2\sin\left(\frac{1}{6}\pi\right) + 2\sin\left(\frac{1}{3}\pi\right) + 2\sin\left(\frac{1}{2}\pi\right) + 2\sin\left(\frac{2}{3}\pi\right) + 2\sin\left(\frac{5}{6}\pi\right) + \sin(1\pi)] $$ $$ T_6 \approx \frac{1}{12} [0 + 2(0.5) + 2(\frac{\sqrt{3}}{2}) + 2(1) + 2(\frac{\sqrt{3}}{2}) + 2(0.5) + 0] $$ $$ T_6 \approx \frac{1}{12} [2 + 2\sqrt{3} + 4 + 2\sqrt{3} + 2] $$ $$ T_6 \approx \frac{1}{12} [8 + 4\sqrt{3}] $$ So, the approximation of \(\int_{0}^{1} \sin \pi x d x\) using the Trapezoid Rule with 6 subintervals is approximately: $$ T_6 \approx \frac{1}{12} [8 + 4\sqrt{3}] $$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Numerical Integration
When attempting to calculate the area under a curve, especially when the exact integral is difficult to determine, numerical integration is a highly useful strategy. It's a method to approximate the definite integral of a function when an exact analytical solution is either impossible or inefficient to obtain. One of the most common techniques within numerical integration is the Trapezoid Rule. This method involves dividing the area under the curve into trapezoids rather than rectangles (as in the case of Riemann sums), which can provide a more accurate approximation in many cases.

Consider the example of approximating \( \int_{0}^{1} \sin \pi x dx \) using the Trapezoid Rule. The process starts by splitting the interval from 0 to 1 into smaller subintervals, calculating the heights of the trapezoids at these points, and then utilizing the Trapezoid Rule formula to compute the area. The benefit of using numerical integration is that it allows for the calculation of approximate values of integrals in situations where an analytical solution would be cumbersome or when the function doesn't have a nice antiderivative to work with.
Definite Integrals
The area under a curve between two points can be precisely represented by a definite integral. It has upper and lower limits, which in our example are 1 and 0, respectively. The notation \( \int_{a}^{b} f(x) dx \) encapsulates the entirety of this concept, where \(f(x)\) is the function, and \(a\) and \(b\) are the limits of integration. A definite integral gives the net area, which can lead to positive, negative, or zero values depending on the function's behavior within the specified interval.

For instance, the definite integral of \( \sin \pi x \) from 0 to 1 represents the signed area between the \(x\)-axis and the sine curve within these bounds. An approximation like the Trapezoid Rule becomes particularly valuable when the function's antiderivative is complex, or if we're working with empirical data that isn't defined by an algebraic function.
Subintervals in Integration
The concept of subintervals in integration involves dividing the total interval over which the integral is to be computed into smaller intervals. These subintervals help in applying numerical methods more effectively. With the Trapezoid Rule, for instance, the accuracy of the approximation often improves as the number of subintervals increases, because more trapezoids mean a better fit to the curve of the graph of the function.

In our exercise, using \(n=6\) subintervals to approximate \( \int_{0}^{1} \sin \pi x dx \) means we are creating 6 smaller intervals of equal width within the interval [0, 1]. This division not only simplifies the process of numerical integration but also improves the approximation's precision as compared to using fewer subintervals. It's also essential to maintain consistency in the width of subintervals to apply the Trapezoid Rule correctly. The value of each subinterval is crucial to calculating the heights of the trapezoids at each point, ultimately determining the accuracy of our numerical approximation.

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