Chapter 7: Problem 17
Evaluate the following integrals. $$\int \sqrt{64-x^{2}} d x$$
Short Answer
Expert verified
Question: Evaluate the integral $$\int \sqrt{64 - x^2} dx$$.
Answer: The evaluated integral is $$32\arcsin\left(\frac{x}{8}\right) + \frac{x\sqrt{64-x^2}}{2} + C$$.
Step by step solution
01
Identify the trigonometric substitution
In this case, we'll make the substitution $$x = 8\sin(\theta)$$, such that $$dx = 8\cos(\theta)d\theta$$. This substitution is chosen because it simplifies the expression inside the square root in the integral.
02
Apply the substitution
Now we will apply the substitution to the integral. Replacing x and dx, we have:
$$\int \sqrt{64 - (8\sin(\theta))^2} (8\cos(\theta) d\theta)$$
03
Simplify the integral
Now, we simplify the expression inside the square root and factor out any constants:
$$\int 8\cos(\theta) \sqrt{64 - 64\sin^2(\theta)} d\theta = 64\int \cos(\theta) \sqrt{1 - \sin^2(\theta)} d\theta $$
Recall the Pythagorean identity:$$1 - \sin^2(\theta) = \cos^2(\theta)$$Now we can further simplify our integral:
$$64\int \cos(\theta) \sqrt{\cos^2(\theta)} d\theta = 64\int \cos^2(\theta)d\theta$$
04
Evaluate the simplified integral
Now, let's evaluate the integral of cos^2(x).
We can use the double angle formula:$$\cos^2(\theta) = \frac{1+\cos(2\theta)}{2}$$Substitute this expression into the integral:
$$64\int \frac{1+\cos(2\theta)}{2} d\theta$$Now, we can separate the two terms and evaluate them individually.
$$\frac{64}{2}\int\left(1+\cos(2\theta)\right)d\theta = 32\left(\int 1 d\theta + \int \cos(2\theta) d\theta\right)$$
Now, let's evaluate the two integrals:
$$32(\theta+\frac{1}{2}\sin(2\theta)) + C = 32\left(\theta+\frac{1}{2}\left(2\sin(\theta)\cos(\theta)\right)\right)+C$$
05
Substitute back
Now we need to substitute back the original variable, x:
$$32\left(\arcsin\left(\frac{x}{8}\right)+\frac{1}{2}\left(2\sin(\theta)\cos(\theta)\right)\right)+C$$
Since $$\sin(\theta) = \frac{x}{8}$$ and $$\cos(\theta) = \sqrt{1-\sin^2(\theta)} = \frac{\sqrt{64-x^2}}{8}$$, we have:
$$32\left(\arcsin\left(\frac{x}{8}\right)+\frac{x\sqrt{64-x^2}}{64}\right)+C$$Thus, the final result is:
$$32\arcsin\left(\frac{x}{8}\right) + \frac{x\sqrt{64-x^2}}{2} + C$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite and Indefinite Integrals
Integrals form a core part of calculus and can be categorized into two main types: definite and indefinite integrals. An **indefinite integral**, also known as an antiderivative, is a function representing an infinite set of antiderivatives of the given function. It is represented by the integral sign without any limits, and typically includes a constant of integration, denoted as **C**. For example, \[ \int f(x) \; dx = F(x) + C \]where **F(x)** is the antiderivative of **f(x)**.
In contrast, a **definite integral** calculates the net area under the curve of a function from a specific starting point, **a**, to an ending point, **b**. It is given as:\[ \int_a^b f(x)\; dx = F(b) - F(a) \]where **F(x)** is the antiderivative of **f(x)**. This process considers the area above the x-axis as positive and below as negative.
In contrast, a **definite integral** calculates the net area under the curve of a function from a specific starting point, **a**, to an ending point, **b**. It is given as:\[ \int_a^b f(x)\; dx = F(b) - F(a) \]where **F(x)** is the antiderivative of **f(x)**. This process considers the area above the x-axis as positive and below as negative.
- Indefinite Integrals: General solutions with an added constant **C**.
- Definite Integrals: Calculated over specific bounds and provide a numerical value.
Pythagorean Identity
The Pythagorean identity is fundamental in simplifying trigonometric expressions, particularly in integration problems. The identity, \[ \sin^2(\theta) + \cos^2(\theta) = 1 \]is derived from the Pythagorean theorem and provides a valuable tool in calculus. By rearranging this identity, you can express one trigonometric function in terms of another, like \[ 1 - \sin^2(\theta) = \cos^2(\theta) \]This relationship is especially useful when the integral involves expressions under a square root, such as \( \sqrt{1 - \sin^2(\theta)} \).
In the exercise, we use the identity to simplify \( \sqrt{64 - x^2} \) to \( 8\cos(\theta) \), thus making the integration process more straightforward. The identity effectively reduces the complexity by converting multi-term expressions into manageable single-term functions.
In the exercise, we use the identity to simplify \( \sqrt{64 - x^2} \) to \( 8\cos(\theta) \), thus making the integration process more straightforward. The identity effectively reduces the complexity by converting multi-term expressions into manageable single-term functions.
- Helps in converting square root expressions.
- Simplifies complicated trigonometric integrals to more solvable forms.
Double Angle Formulas
The **double angle formulas** are essential for converting expressions involving powers of sine and cosine into simpler forms. One of these formulas states:\[\cos^2(\theta) = \frac{1 + \cos(2\theta)}{2}\]This expression is particularly useful when dealing with integrals of trigonometric functions squared, such as \( \cos^2(\theta) \).
In integration, using the double angle formula allows us to break complex expressions into a sum of simpler terms. For instance, the integral \( \int \cos^2(\theta) \; d\theta \) can be transformed into\[\int \frac{1 + \cos(2\theta)}{2} \; d\theta\]Through this transformation, evaluating indefinite integrals of cosine squared becomes more manageable. This process can be split into simpler integrals \( \int 1 \;d\theta \)and \( \int \cos(2\theta) \; d\theta \).
In integration, using the double angle formula allows us to break complex expressions into a sum of simpler terms. For instance, the integral \( \int \cos^2(\theta) \; d\theta \) can be transformed into\[\int \frac{1 + \cos(2\theta)}{2} \; d\theta\]Through this transformation, evaluating indefinite integrals of cosine squared becomes more manageable. This process can be split into simpler integrals \( \int 1 \;d\theta \)and \( \int \cos(2\theta) \; d\theta \).
- Simplifies integrating powers of trigonometric functions.
- Transforms products into sums, which are easier to integrate.