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Sketch a two-dimensional vector field that has zero divergence everywhere in the plane.

Short Answer

Expert verified
Answer: A suitable example of a vector field with zero divergence everywhere in the plane is F(x, y) = (y, -x). To sketch this vector field, we place a vector with components (y, -x) at each point (x, y) in the plane, and the sketch should depict vectors pointing in a counterclockwise circular direction around the origin where the length of the vector increases as we move away from the origin.

Step by step solution

01

Vector Field DivergenceDefinition

The divergence of a vector field F(x, y) = (P(x, y), Q(x, y)) is the scalar function that measures the tendency of the field to "spread out" or "converge" at a point. The mathematical formulation of divergence is given as: $$ \text{div } F = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} $$ Our task is to find a vector field F(x, y) that has zero divergence everywhere in the plane, meaning the above equation should equal zero for all points (x, y) in the plane.
02

Identifying a Vector Field with Zero Divergence

One simple example of a vector field with zero divergence everywhere in the plane is F(x, y) = (y, -x). Here, P(x, y) = y and Q(x, y) = -x. Let's check that the divergence of this field is zero everywhere: $$ \text{div } F = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} = \frac{\partial y}{\partial x} + \frac{\partial (-x)}{\partial y} = 0 + 0 = 0 $$ So, F(x, y) = (y, -x) is a suitable example of a vector field with zero divergence everywhere in the plane.
03

Sketching the Vector Field

To sketch the vector field F(x, y) = (y, -x), we can place a vector with components (y, -x) at each point (x, y) in the plane. We can notice a pattern in the vector field: the vectors are pointing in a counterclockwise circular direction. This makes sense because the rotation of a vector field F(x, y) = (y, -x) equals the negative derivative of P(x, y) with respect to x (i.e., -y) minus the negative derivative of Q(x, y) with respect to y (i.e., -x) at each point (x, y). The circular pattern ensures every time that the divergence of the field is zero everywhere in the plane. So, the sketch of the vector field F(x, y) = (y, -x) should depict vectors pointing in a counterclockwise circular direction around the origin where the length of the vector increases as we move away from the origin.

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Most popular questions from this chapter

Consider the potential function \(\varphi(x, y, z)=G(\rho),\) where \(G\) is any twice differentiable function and \(\rho=\sqrt{x^{2}+y^{2}+z^{2}} ;\) therefore, \(G\) depends only on the distance from the origin. a. Show that the gradient vector field associated with \(\varphi\) is \(\mathbf{F}=\nabla \varphi=G^{\prime}(\rho) \frac{\mathbf{r}}{\rho},\) where \(\mathbf{r}=\langle x, y, z\rangle\) and \(\rho=|\mathbf{r}|\) b. Let \(S\) be the sphere of radius \(a\) centered at the origin and let \(D\) be the region enclosed by \(S\). Show that the flux of \(\mathbf{F}\) across \(S\) is $$\iint_{S} \mathbf{F} \cdot \mathbf{n} d S=4 \pi a^{2} G^{\prime}(a) $$ c. Show that \(\nabla \cdot \mathbf{F}=\nabla \cdot \nabla \varphi=\frac{2 G^{\prime}(\rho)}{\rho}+G^{\prime \prime}(\rho)\) d. Use part (c) to show that the flux across \(S\) (as given in part (b)) is also obtained by the volume integral \(\iiint_{D} \nabla \cdot \mathbf{F} d V\). (Hint: use spherical coordinates and integrate by parts.)

Let S be the disk enclosed by the curve \(C: \mathbf{r}(t)=\langle\cos \varphi \cos t, \sin t, \sin \varphi \cos t\rangle,\)for \(0 \leq t \leq 2 \pi,\) where \(0 \leq \varphi \leq \pi / 2\) is a fixed angle. What is the length of \(C ?\)

Prove the following identities. Assume that \(\varphi\) is \(a\) differentiable scalar-valued function and \(\mathbf{F}\) and \(\mathbf{G}\) are differentiable vector fields, all defined on a region of \(\mathbb{R}^{3}\). $$\nabla \times(\varphi \mathbf{F})=(\nabla \varphi \times \mathbf{F})+(\varphi \nabla \times \mathbf{F}) \quad \text { (Product Rule) }$$

Use the procedure in Exercise 57 to construct potential functions for the following fields. $$\mathbf{F}=\langle-y,-x\rangle$$

Begin with the paraboloid \(z=x^{2}+y^{2},\) for \(0 \leq z \leq 4,\) and slice it with the plane \(y=0\) Let \(S\) be the surface that remains for \(y \geq 0\) (including the planar surface in the \(x z\) -plane) (see figure). Let \(C\) be the semicircle and line segment that bound the cap of \(S\) in the plane \(z=4\) with counterclockwise orientation. Let \(\mathbf{F}=\langle 2 z+y, 2 x+z, 2 y+x\rangle\) a. Describe the direction of the vectors normal to the surface that are consistent with the orientation of \(C\). b. Evaluate \(\iint_{S}(\nabla \times \mathbf{F}) \cdot \mathbf{n} d S\) c. Evaluate \(\oint_{C} \mathbf{F} \cdot d \mathbf{r}\) and check for agreement with part (b).

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