/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Let S be the disk enclosed by th... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let S be the disk enclosed by the curve \(C: \mathbf{r}(t)=\langle\cos \varphi \cos t, \sin t, \sin \varphi \cos t\rangle,\)for \(0 \leq t \leq 2 \pi,\) where \(0 \leq \varphi \leq \pi / 2\) is a fixed angle. What is the length of \(C ?\)

Short Answer

Expert verified
Solution: To find the length of C, we need to integrate the magnitude of the derivative \(\|\mathbf{r'}(t)\|\), which we found to be \(\sqrt{(\cos^2\varphi + \sin^2\varphi) \sin^2 t + \cos^2t}\) from \(0\) to \(2\pi\) with respect to \(t\). The integral is not solvable analytically, but we can approximate the length of C using numerical methods like a computer program or a calculator with integration capabilities. The approximate length of the curve C will be a numerical value that depends on the given values of \(\varphi\).

Step by step solution

01

Parametrize the curve C

We are already given the parametric representation of the curve, $\mathbf{r}(t)=\langle\cos \varphi \cos t, \sin t, \sin \varphi \cos t\rangle$. This makes our job easier, as we can skip directly to calculating the derivative.
02

Calculate the derivative of \(\mathbf{r}(t)\) with respect to \(t\)

To find the derivative of \(\mathbf{r}(t)\) with respect to \(t\), we need to differentiate each component of the vector-valued function. The derivative is calculated as follows: $$ \mathbf{r'}(t) = \langle -\cos \varphi \sin t, \cos t, -\sin \varphi \sin t \rangle. $$
03

Find the magnitude of \(\mathbf{r'}(t)\)

To calculate the magnitude of the derivative, we need to find the square root of the sum of the squares of each component. For \(\mathbf{r'}(t) = \langle -\cos \varphi \sin t, \cos t, -\sin \varphi \sin t \rangle \), the magnitude is: $$ \|\mathbf{r'}(t)\| = \sqrt{(-\cos \varphi \sin t)^2 + (\cos t)^2 + (-\sin \varphi \sin t)^2}. $$ After simplifying, the magnitude of \(\mathbf{r'}(t)\) is: $$ \|\mathbf{r'}(t)\| = \sqrt{(\cos^2 \varphi + \sin^2 \varphi) \sin^2 t + \cos^2 t}. $$
04

Integrate the magnitude of \(\mathbf{r'}(t)\)

Now, we will integrate \(\|\mathbf{r'}(t)\|\) with respect to \(t\) over the interval \([0, 2\pi]\) to find the length of the curve C. $$ \text{Length of C} = \int_{0}^{2\pi} \|\mathbf{r'}(t)\| dt = \int_{0}^{2\pi} \sqrt{(\cos^2\varphi + \sin^2\varphi) \sin^2 t + \cos^2t} dt. $$
05

Solve the integral

Unfortunately, the integral in its current form is quite difficult to solve directly. However, this problem can be solved using numerical methods like a computer program or a calculator with integration capabilities. Since we are asked for the length of C without explicitly requiring the analytical expression, the numerical method would suffice. Using a numerical method, approximate the length of C for the given values of \(\varphi\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parametric Equations
Parametric equations allow us to represent curves by defining the coordinates of the points on the curve as functions of a single variable, commonly called the parameter. In this exercise, the parameter is denoted by \( t \), which varies from 0 to \( 2\pi \). This helps us trace the entire curve as \( t \) changes. The given parametric form \( \mathbf{r}(t) = \langle \cos \varphi \cos t, \sin t, \sin \varphi \cos t \rangle \) provides a 3-dimensional vector representation of the curve, where each component is a function of both the parameter \( t \) and a fixed angle \( \varphi \). By using parametric equations, you gain more flexibility in describing intricate shapes and motions that may not be easily expressed using only one equation.
Curve Length
The length of a curve defined by parametric equations can be found by integrating the magnitude of the derivative of the vector function over the given interval. To determine the curve length, we first need the derivative \( \mathbf{r'}(t) \). This derivative essentially reflects how fast the point moves along the curve. Next, the magnitude of this derivative \( \|\mathbf{r'}(t)\| \) provides a measure of the vector's length at each point, giving insight into the 'speed' at which the point travels.

To find the total length of the curve, we integrate \( \|\mathbf{r'}(t)\| \) with respect to \( t \) over the interval from 0 to \( 2\pi \). This integral accounts for all the small distances covered as \( t \) changes, summing them up to obtain the total curve length. Because the integral can be complex, numerical methods are often applied to approximate the curve's length accurately.
Vector Calculus
Vector calculus is a branch of mathematics focused on the application of calculus in multiple dimensions through vectors. By using vectors, we can describe and manipulate quantities that have both magnitude and direction, such as positions, velocities, and accelerations. This exercise involves the differentiation of a vector-valued function \( \mathbf{r}(t) \), which is a prime example of vector calculus in action.

When we differentiate a vector function, we find a new vector \( \mathbf{r'}(t) \) whose components are the derivatives of the original vector's components. In vector calculus, we explore not only rates of change but also how these vectors change direction or curl. Derivatives and integrals of vectors are tools used to solve a wide variety of problems, from physics to engineering and beyond.
Numerical Integration
In many cases, especially in more complex models like the one given, integrals may not have straightforward analytic solutions. Numerical integration comes into play by providing methods for approximating the value of these integrals. This is especially useful when we want to compute the length of a curve based on its parametric representation.

Numerical methods like the trapezoidal rule, Simpson's rule, or more advanced algorithms can compute an approximation by evaluating the integral at a finite number of points. These techniques help estimate the total length of the curve accurately, despite the integral itself being difficult to solve by hand. By using technology, like a computer or a scientific calculator, numerical integration allows for practical solutions to complex integrals, making it an essential tool in both academic and applied mathematics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let \(\mathbf{F}\) be a radial field \(\mathbf{F}=\mathbf{r} /|\mathbf{r}|^{p},\) where \(p\) is a real number and \(\mathbf{r}=\langle x, y, z\rangle .\) With \(p=3, \mathbf{F}\) is an inverse square field. a. Show that the net flux across a sphere centered at the origin is independent of the radius of the sphere only for \(p=3\) b. Explain the observation in part (a) by finding the flux of \(\mathbf{F}=\mathbf{r} /|\mathbf{r}|^{p}\) across the boundaries of a spherical box \(\left\\{(\rho, \varphi, \theta): a \leq \rho \leq b, \varphi_{1} \leq \varphi \leq \varphi_{2}, \theta_{1} \leq \theta \leq \theta_{2}\right\\}\) for various values of \(p\)

Prove that for a real number \(p,\) with \(\mathbf{r}=\langle x, y, z\rangle, \nabla\left(\frac{1}{|\mathbf{r}|^{p}}\right)=\frac{-p \mathbf{r}}{|\mathbf{r}|^{p+2}}.\)

If two functions of one variable, \(f\) and \(g\), have the property that \(f^{\prime}=g^{\prime},\) then \(f\) and \(g\) differ by a constant. Prove or disprove: If \(\mathbf{F}\) and \(\mathbf{G}\) are nonconstant vector fields in \(\mathbb{R}^{2}\) with curl \(\mathbf{F}=\operatorname{curl} \mathbf{G}\) and \(\operatorname{div} \mathbf{F}=\operatorname{div} \mathbf{G}\) at all points of \(\mathbb{R}^{2},\) then \(\mathbf{F}\) and \(\mathbf{G}\) differ by a constant vector.

Consider the vector field \(\mathbf{F}=\langle y, x\rangle\) shown in the figure. a. Compute the outward flux across the quarter circle \(C: \mathbf{r}(t)=\langle 2 \cos t, 2 \sin t\rangle,\) for \(0 \leq t \leq \pi / 2\) b. Compute the outward flux across the quarter circle \(C: \mathbf{r}(t)=\langle 2 \cos t, 2 \sin t\rangle,\) for \(\pi / 2 \leq t \leq \pi\) c. Explain why the flux across the quarter circle in the third quadrant equals the flux computed in part (a). d. Explain why the flux across the quarter circle in the fourth quadrant equals the flux computed in part (b). e. What is the outward flux across the full circle?

Let \(\mathbf{F}=\langle z, 0,0\rangle\) and let \(\mathbf{n}\) be a unit vector aligned with the axis of a paddle wheel located on the \(x\) -axis (see figure). a. If the paddle wheel is oriented with \(\mathbf{n}=\langle 1,0,0\rangle,\) in what direction (if any) does the wheel spin? b. If the paddle wheel is oriented with \(\mathbf{n}=\langle 0,1,0\rangle,\) in what direction (if any) does the wheel spin? c. If the paddle wheel is oriented with \(\mathbf{n}=\langle 0,0,1\rangle,\) in what direction (if any) does the wheel spin?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.