Chapter 2: Problem 27
Prove the statement using the \(\varepsilon, \delta\) definition of a limit. $$ \lim _{x \rightarrow 0}|x|=0 $$
Short Answer
Expert verified
The limit is proven using \( \delta = \varepsilon \).
Step by step solution
01
Understanding the Limit Definition
To prove the limit \( \lim_{x \to 0} |x| = 0 \) using the \( \varepsilon, \delta \) definition, we must show that for every \( \varepsilon > 0 \), there exists a \( \delta > 0 \) such that if \( 0 < |x - 0| < \delta \), then \( | |x| - 0 | < \varepsilon \).
02
Define the Relevant Expressions
In this case, \( |x - 0| = |x| \) and \( ||x| - 0| = |x| \). Thus, we are looking at \( |x| < \varepsilon \) whenever \( |x| < \delta \).
03
Choose a Specific Delta
A natural choice is to set \( \delta = \varepsilon \). This means that if \( |x| < \delta \), then \( |x| < \varepsilon \).
04
Verify the Condition
Verify that this choice of \( \delta \) satisfies the \( \varepsilon, \delta \) condition. Indeed, if \( 0 < |x| < \delta \), we directly have \( |x| < \varepsilon \), which matches the requirement.
05
Complete the Proof
By choosing \( \delta = \varepsilon \), we have shown that for every \( \varepsilon > 0 \), there exists a \( \delta = \varepsilon \) such that whenever \( 0 < |x| < \delta \), \( |x| < \varepsilon \). Hence, \( \lim_{x \to 0} |x| = 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit
The concept of a limit is central to calculus and is used to describe how a function behaves as its input approaches a particular point. In the statement \( \lim_{x \to 0} |x| = 0 \), we are observing what happens to the function \(|x|\) as \(x\) gets closer and closer to 0. This doesn't mean that \(x\) has to exactly be 0, but rather it gets infinitely close to 0.
- We write \(\lim_{x \to 0} |x| = 0\) to show that as \(x\) approaches 0, the absolute value \(|x|\) approaches 0.
- The limit is all about closeness and behavior near a point, rather than the point itself.
Absolute Value
The absolute value of a number, denoted by \(|x|\), represents its distance from zero on the number line. It’s always a non-negative number, meaning \(|x|\) can be zero or positive, but never negative. For example, both \(|5|\) and \(|-5|\) equal 5, since both 5 and -5 are 5 units away from zero.
When dealing with limits, the absolute value helps in understanding the magnitude or size of a number without regard to its direction (positive or negative).
When dealing with limits, the absolute value helps in understanding the magnitude or size of a number without regard to its direction (positive or negative).
- In our limit problem, \(|x| = 0\) represents \(x\) being exactly at 0.
- When \(x\) approaches 0, \(|x|\) simply represents how far \(x\) is from 0, without caring if \(x\) is a little more or less.
Calculus Proof
Proving a statement using calculus involves logical reasoning and understanding definitions thoroughly. In the case of proving \(\lim_{x \to 0} |x| = 0\) using the \(\varepsilon, \delta\) definition of a limit, we focus on ensuring the function behaves as expected under specific conditions.
- The \(\varepsilon, \delta\) definition is a formal way to confirm that the limit holds true.
- For any positive number \(\varepsilon\), no matter how small, we must find a positive \(\delta\) such that, if \(x\) is within distance \(\delta\) from 0 (not including 0 itself), then \(|x|\) is within \(\varepsilon\) from 0.