Chapter 2: Problem 63
Prove that \(f\) is continuous at \(a\) if and only if $$ \lim _{h \rightarrow 0} f(a+h)=f(a) $$
Short Answer
Expert verified
Function \( f \) is continuous at \( a \) if and only if \( \lim_{{h \to 0}} f(a+h) = f(a) \).
Step by step solution
01
Define Continuity
A function \( f \) is continuous at \( a \) if \( \lim_{{x \to a}} f(x) = f(a) \). This means as \( x \) approaches \( a \), the value of \( f(x) \) gets arbitrarily close to \( f(a) \).
02
Understand the Given Limit
We need to show that \( \lim_{{h \to 0}} f(a+h) = f(a) \) is equivalent to continuity at \( a \). Here, \( h \to 0 \) implies \( a+h \to a \), which means we are observing \( f(x) \) as \( x \to a \).
03
Proof of the Forward Direction
Assume \( f \) is continuous at \( a \). By definition, \( \lim_{{x \to a}} f(x) = f(a) \). Substituting \( x = a + h \), we have \( \lim_{{h \to 0}} f(a+h) = \lim_{{x \to a}} f(x) = f(a) \). Thus, the given condition holds.
04
Proof of the Converse Direction
Assume \( \lim_{{h \to 0}} f(a+h) = f(a) \). We want to prove \( \lim_{{x \to a}} f(x) = f(a) \). Let \( x = a + h \), so \( \lim_{{x \to a}} f(x) = \lim_{{h \to 0}} f(a+h) = f(a) \). Therefore, \( f \) is continuous at \( a \).
05
Conclusion
Both directions are proven: if \( f \) is continuous at \( a \), then \( \lim_{{h \to 0}} f(a+h) = f(a) \); and if \( \lim_{{h \to 0}} f(a+h) = f(a) \), then \( f \) is continuous at \( a \). These statements are equivalent.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits
In mathematics, a limit helps us understand how a function behaves as its input approaches a particular point. When we talk about the limit of a function as the variable approaches a certain value, we're essentially observing where the function values are heading towards from both sides of the point.
For example, if we consider the function \( f(x) \) as \( x \) gets closer and closer to a specific number \( a \), the notion of a limit captures the tendency of \( f(x) \). This leads to the expression \( \lim_{x \to a} f(x) \), meaning the value that \( f(x) \) approaches as \( x \) nears \( a \).
For example, if we consider the function \( f(x) \) as \( x \) gets closer and closer to a specific number \( a \), the notion of a limit captures the tendency of \( f(x) \). This leads to the expression \( \lim_{x \to a} f(x) \), meaning the value that \( f(x) \) approaches as \( x \) nears \( a \).
- It's crucial to note that limits are concerned with the behavior of a function near a point, rather than at that point.
- The concept of limits is foundational for defining continuity and differentiability.
- By using limits, we can handle cases where direct substitution might result in indeterminate forms like \( \frac{0}{0} \).
Epsilon-Delta Definition
The epsilon-delta definition is a rigorous way to define the limit of a function at a point. It's a formalization that provides clarity on how close a function value can get to a particular number as its input approaches a certain point.
In this definition, for any small positive number \( \epsilon \) (representing how close we want the function value to be to its limit), there exists a corresponding small positive number \( \delta \) (indicating the required proximity of the input to the point in question) such that if the distance of \( x \) from \( a \) is less than \( \delta \) (excluding \( a \) itself), then the distance of \( f(x) \) from \( L \) is less than \( \epsilon \) (where \( L \) is the limit value).
In this definition, for any small positive number \( \epsilon \) (representing how close we want the function value to be to its limit), there exists a corresponding small positive number \( \delta \) (indicating the required proximity of the input to the point in question) such that if the distance of \( x \) from \( a \) is less than \( \delta \) (excluding \( a \) itself), then the distance of \( f(x) \) from \( L \) is less than \( \epsilon \) (where \( L \) is the limit value).
- This can be expressed as: if \( 0 < |x - a| < \delta \), then \( |f(x) - L| < \epsilon \).
- The epsilon-delta definition allows us to prove the continuity of a function at a point or over an interval.
- The challenge lies in choosing an appropriate \( \delta \) given an arbitrary \( \epsilon \), which is a common exercise in mathematical analysis.
Pointwise Continuity
Pointwise continuity deals with the behavior of a function at individual points. A function \( f \) is said to be continuous at a point \( a \) if the limit of \( f(x) \) as \( x \) approaches \( a \) is equal to \( f(a) \).
This condition implies that as you get closer to \( a \), \( f(x) \) will be consistently approaching the value \( f(a) \). The formal expression of this is \( \lim_{x \to a} f(x) = f(a) \).
This condition implies that as you get closer to \( a \), \( f(x) \) will be consistently approaching the value \( f(a) \). The formal expression of this is \( \lim_{x \to a} f(x) = f(a) \).
- Pointwise continuity is a local property; it does not consider the entire domain of the function.
- A pointwise continuous function does not "jump" at any specific point within its domain.
- We often demonstrate pointwise continuity using the epsilon-delta definition, which helps to ensure that for every point in its domain, the function behaves without interruption or sudden changes.