Chapter 9: Problem 24
Determine whether the series converges. $$ \sum_{k=1}^{\infty} \operatorname{sech}^{2} k $$
Short Answer
Expert verified
The series converges.
Step by step solution
01
Understand the Series
We are given the series \( \sum_{k=1}^{\infty} \operatorname{sech}^{2} k \). The hyperbolic secant squared function \( \operatorname{sech}^{2}(k) \) can be expressed as \( \left(\frac{2}{e^k + e^{-k}}\right)^2 \). We need to determine whether this series converges as \( k \to \infty \).
02
Test the Behavior of the General Term
Examine the behavior of the general term \( a_k = \operatorname{sech}^{2} k \). As \( k \to \infty \), the term \( e^{-k} \to 0 \), thus \( e^k + e^{-k} \to e^k \). This implies \( \operatorname{sech}^{2}(k) \approx \left(\frac{2}{e^k}\right)^2 = 4e^{-2k} \).
03
Compare with a Known Convergent Series
Notice that the term \( 4e^{-2k} \) behaves similarly to a geometric series \( \sum 4b^k \) with common ratio \( b = e^{-2} < 1 \). Geometric series converge if the absolute value of the common ratio is less than 1.
04
Apply the Limit Comparison Test
Consider the series \( \sum 4 e^{-2k} \), which is geometric and converges. Calculate the limit: \( \lim_{k \to \infty} \frac{\operatorname{sech}^2(k)}{4 e^{-2k}} = \lim_{k \to \infty} \frac{\left(\frac{2}{e^k + e^{-k}}\right)^2}{4e^{-2k}} = 1 \). Since this limit is a positive finite number, by the Limit Comparison Test, \( \sum \operatorname{sech}^2(k) \) converges.
05
Conclusion
We have shown by comparing with the known convergent series \( 4e^{-2k} \) and using the Limit Comparison Test that the series \( \sum_{k=1}^{\infty} \operatorname{sech}^{2} k \) converges.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit Comparison Test
The Limit Comparison Test is a powerful tool in calculus used to determine whether a series converges or diverges. The test compares an unknown series to a known benchmark series. If the limit of the ratio of the terms from the two series results in a positive finite number, both series either converge or diverge.
Let's break it down step-by-step:
Let's break it down step-by-step:
- Identify: Choose a series that is similar to the one you are analyzing.
- Calculate: Form the limit expression by dividing the term from the unknown series by the term from the known series.
- Simplify and Evaluate: Simplify the expression if necessary and evaluate the limit as the index approaches infinity.
- Result: If the limit is a finite positive number, the behavior of the series (whether it converges or diverges) matches that of the known series.
Geometric Series
A geometric series is a fascinating type of series where each term is a constant multiple of the previous one.
It takes the form:\[ a + ar + ar^2 + ar^3 + \ldots \]where \( a \) is the first term and \( r \) is the common ratio.
One crucial point to remember is the fact that a geometric series converges if the absolute value of the common ratio \( |r| \) is less than 1.
It takes the form:\[ a + ar + ar^2 + ar^3 + \ldots \]where \( a \) is the first term and \( r \) is the common ratio.
One crucial point to remember is the fact that a geometric series converges if the absolute value of the common ratio \( |r| \) is less than 1.
- Convergence: An infinite geometric series converges to \( \frac{a}{1-r} \) if \( |r| < 1 \).
- Divergence: If \( |r| \geq 1 \), the series diverges.
Hyperbolic Functions
Hyperbolic functions are analogs to the trigonometric functions but involve hyperbolas instead of circles.
The hyperbolic secant, \( \operatorname{sech}(x) \), is especially interesting. It is defined as:\[ \operatorname{sech}(x) = \frac{2}{e^x + e^{-x}} \]The hyperbolic secant squared, \( \operatorname{sech}^2(x) \), follows naturally as:\[ \operatorname{sech}^2(x) = \left(\frac{2}{e^x + e^{-x}}\right)^2 \]
These functions are smooth and show rapid decay as their argument \( x \) increases. This property makes them useful for series convergence tests, as shown in the exercise. As \( x \to \infty \), \( \operatorname{sech}^2(x) \) behaves similarly to an exponential decay function. This allows the application of methods like the limit comparison test with geometric series to establish convergence.
The hyperbolic secant, \( \operatorname{sech}(x) \), is especially interesting. It is defined as:\[ \operatorname{sech}(x) = \frac{2}{e^x + e^{-x}} \]The hyperbolic secant squared, \( \operatorname{sech}^2(x) \), follows naturally as:\[ \operatorname{sech}^2(x) = \left(\frac{2}{e^x + e^{-x}}\right)^2 \]
These functions are smooth and show rapid decay as their argument \( x \) increases. This property makes them useful for series convergence tests, as shown in the exercise. As \( x \to \infty \), \( \operatorname{sech}^2(x) \) behaves similarly to an exponential decay function. This allows the application of methods like the limit comparison test with geometric series to establish convergence.