Chapter 7: Problem 13
Evaluate the integral. $$ \int \ln (3 x-2) d x $$
Short Answer
Expert verified
The integral is \( x \ln(3x-2) - x + \frac{2}{3} \ln|3x-2| + C \).
Step by step solution
01
Choose a Method
To evaluate the integral \( \int \ln (3x - 2) \, dx \), we will use integration by parts. This method is useful for integrals involving a product of functions, one of which is easily differentiated.
02
Recall Integration by Parts Formula
Integration by parts formula is given by:\[\int u \, dv = uv - \int v \, du\]We need to identify \( u \) and \( dv \) for the function \( \ln (3x - 2) \).
03
Identify \( u \) and \( dv \)
Let \( u = \ln(3x - 2) \) and \( dv = dx \). This choice is strategic since \( \ln(3x-2) \) is easily differentiable and \( dx \) is easily integrable.
04
Differentiate \( u \) and Integrate \( dv \)
Differentiate \( u \) to find \( du \):\[ du = \frac{1}{3x - 2} \cdot 3 \, dx = \frac{3}{3x - 2} \, dx \]Integrate \( dv \) to find \( v \):\[ v = x \]
05
Substitute into Integration by Parts Formula
Substitute \( u \), \( v \), \( du \), and \( dv \) into the integration by parts formula:\[\int \ln (3x - 2) \, dx = x \ln(3x-2) - \int x \left( \frac{3}{3x - 2} \right) \, dx\]
06
Simplify the Remaining Integral
First, simplify the integral:\[ \int x \cdot \frac{3}{3x - 2} \, dx \]This simplifies algebraically to:\[ 3 \int \frac{x}{3x - 2} \, dx \]
07
Integrate Remaining Integral
Use substitution method for the integral \( 3 \int \frac{x}{3x - 2} \, dx \).Let \( v = 3x - 2 \), then \( dv = 3 \, dx \), thus, \( dx = \frac{dv}{3} \). Substitute into the integral:\[ \int \frac{x}{v} \cdot \frac{dv}{3} \]Express \( x \) in terms of \( v \): \((x = \frac{v+2}{3})\) and substitute:\[ \int \frac{v + 2}{3v} \cdot \frac{dv}{3} \]This can then be integrated directly.
08
Evaluate the Sub Integral and Final Expression
Sub-integrating, factor out the constants and integrate:\[\int \left(\frac{1}{3} + \frac{2}{3v}\right) \, dv = \frac{1}{3}v + \frac{2}{3} \ln|v|\]Convert back to \( x \):\[ = \frac{1}{3}(3x - 2) + \frac{2}{3} \ln|3x - 2|\]Combine results with Step 5:\[ x \ln(3x-2) - \frac{1}{3}(3x - 2) - \frac{2}{3} \ln|3x-2|+ C\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Natural Logarithm
The natural logarithm, often written as \( \ln(x) \), is a fundamental logarithmic function in calculus. It is the logarithm to the base \( e \), where \( e \) is approximately equal to 2.71828, an important mathematical constant. The function \( \ln(x) \) is specifically useful for describing growth processes such as population growth and compound interest.
Under globalization:
Under globalization:
- The derivative of \( \ln(x) \) is \( \frac{1}{x} \). This property is key in calculus since it makes differentiation straightforward.
- The natural logarithm is the inverse function of the exponential function. This means that \( e^{\ln(x)} = x \) for \( x > 0 \).
- It is essential for solving integrals involving a natural logarithm as its derivative simplifies complex functions.
Integration Techniques
Integration techniques are strategies used to simplify and solve integrals in calculus. Given the integral\[\int \ln(3x - 2) \, dx\]integration by parts is one common technique employed.
- Integration by Parts: This technique is derived from the product rule for differentiation, expressed as \( \int u \, dv = uv - \int v \, du \). It is particularly useful when dealing with the product of functions, where one is easy to differentiate, like \( \ln(3x-2) \) being \( u \).
- Substitution: Sometimes it might be necessary to change variables to simplify an integral, as was done in the exercise to manage the expression \( \frac{x}{3x-2} \).
- Other techniques include partial fraction decomposition or trigonometric identities, although not needed here, are good to recognize within the toolbox of integration skills.
Calculus Integration Methods
Calculus integration methods encompass a wide range of approaches to find antiderivatives. These methods are pivotal in solving problems like evaluating the integral of \( \ln(3x - 2) \), concretely using integration by parts.
- Direct Integration: Often the fastest method if the integrand is a straightforward function that fits basic integration rules.
- Integration by Parts: Considered when direct integration isn't straightforward, particularly for function products where rearranging the integral yields simpler sub-integrals.
- Substitution: Applies well when changing variables simplifies the integral, as it was used in the exercise by introducing \( v = 3x - 2 \) to simplify \( \frac{x}{3x - 2} \).