/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Evaluate the integral. $$ \i... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the integral. $$ \int \frac{d x}{\left(1-x^{2}\right)^{3 / 2}} $$

Short Answer

Expert verified
The integral evaluates to \( \frac{x}{\sqrt{1-x^2}} + C \).

Step by step solution

01

Identify the Integral Type

First, we recognize the integral of the form \( \int \frac{1}{\left(1-x^2\right)^{3/2}} \, dx \). This resembles a form of a trigonometric substitution integral.
02

Choose a Trigonometric Substitution

The integral involves \( 1-x^2 \), which suggests the substitution \( x = \sin \theta \). This choice leads to \( dx = \cos \theta \, d\theta \). Also, \( \sqrt{1-x^2} = \cos \theta \).
03

Substitute and Simplify the Integral

Substitute \( x = \sin \theta \) and \( dx = \cos \theta \, d\theta \) into the integral: \[\int \frac{\cos \theta \, d\theta}{(\cos \theta)^{3}} = \int \cos^{-2} \theta \, d\theta = \int \sec^2 \theta \, d\theta.\]
04

Solve the Integral

The integral \( \int \sec^2 \theta \, d\theta \) is a standard integral, with the result \( \tan \theta + C \).
05

Reverse the Substitution

We made the substitution \( x = \sin \theta \), which implies \( \theta = \arcsin x \). Therefore, \( \tan \theta = \frac{x}{\sqrt{1-x^2}} \). Thus, the solution becomes: \[ \int \frac{dx}{(1-x^2)^{3/2}} = \frac{x}{\sqrt{1-x^2}} + C \] where \( C \) is the constant of integration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Substitution
Trigonometric substitution is a valuable technique used in calculus to simplify integrals involving square roots of expressions such as \(1-x^2\), \(a^2-x^2\), or \(x^2-a^2\). When an integral features these forms, replacing the variable with a trigonometric function can transform the integral into an easier form to solve. For example, if you encounter \(1-x^2\), you can use the substitution \(x=\sin \theta\). This is because sine and cosine functions have natural connections to the Pythagorean identity, \(\sin^2\theta + \cos^2\theta = 1\).
When \(x=\sin\theta\), the derivative \(dx=\cos\theta \, d\theta\) and \(\sqrt{1-x^2}\) conveniently becomes \(\cos \theta\). This substitution exploits the geometric properties of trigonometric functions, turning complex radicals into basic trigonometric identities.
Such substitutions are not arbitrary. They are strategically chosen based on the integral's structure to simplify and eventually solve the integral.
Definite Integrals
Definite integrals are integral expressions evaluated over a specific range, resulting in a numerical value. Unlike indefinite integrals, which include an arbitrary constant \(C\), definite integrals have limits of integration, say from \(a\) to \(b\). They represent the area under the curve of the function between these two points.
To evaluate a definite integral, you first find the indefinite integral of the function and then apply the Fundamental Theorem of Calculus. This theorem connects differentiation with integration, where you evaluate the antiderivative at the upper limit and subtract its value at the lower limit:
  • Find the antiderivative \(F(x)\).
  • Compute \(F(b) - F(a)\).
This process gives you the total accumulated change or net area between the curve and the x-axis over the interval \([a, b]\). In the context of trigonometric substitution, if performing these substitutions is required, the limits of integration need to be adjusted accordingly.
Integration Techniques
Integration is a core concept of calculus with various techniques designed to tackle different forms of integrals. Familiarity with methods like substitution, integration by parts, partial fraction decomposition, and trigonometric substitution can greatly enhance one's ability to solve complex integrals.
Substitution, such as trigonometric substitution, often simplifies the integral by swapping complex expressions with simpler trigonometric ones. Integration by parts is useful for products of functions and relies on the formula \(\int u \, dv = uv - \int v \, du\). Partial fraction decomposition breaks down complex rational expressions into simpler fractions, making integration more manageable.
When choosing an integration technique, the integral's structure and the functions involved will guide you toward the most efficient method. Practice and experience will help you recognize these patterns and apply suitable strategies quickly and effectively.

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Most popular questions from this chapter

Use any method to find the area of the surface generated by revolving the curve about the \(x\) -axis. $$ y=1 / x, 1 \leq x \leq 4 $$

The exact value of the given integral is \(\pi\) (verify). Approximate the integral using (a) the midpoint approximation \(M_{10},(\mathrm{~b})\) the trapezoidal approximation \(T_{10}\), and (c) Simpson's rule approximation \(S_{20}\) using Formula (7). Approximate the absolute error and express your answers to at least four decimal places. $$ \int_{0}^{2} \frac{8}{x^{2}+4} d x $$

(a) Make an appropriate \(u\) -substitution of the form \(u=x^{1 / n}\) or \(u=(x+a)^{1 / n}\), and then evaluate the integral. (b) If you have a CAS, use it to evaluate the integral, and then confirm that the result is equivalent to the one that you found in part (a). $$ \int \frac{d x}{x^{1 / 2}-x^{1 / 3}} $$

Use any method to find the volume of the solid generated when the region enclosed by the curves is revolved about the \(y\) -axis. $$ y=e^{-x}, \quad y=0, x=0, x=3 $$

Medication can be administered to a patient using a variety of methods. For a given method, let \(c(t)\) denote the concentration of medication in the patient's bloodstream (measured in \(\mathrm{mg} / \mathrm{L}) t\) hours after the dose is given. The area under the curve \(c=c(t)\) over the time interval \([0,+\infty)\) indicates the "availability" of the medication for the patient's body. Determine which method provides the greater availability. Method \(1: c_{1}(t)=6\left(e^{-0.4 t}-e^{-1.3 t}\right)\) Method \(2: c_{2}(t)=5\left(e^{-0.4 t}-e^{-3 t}\right)\)

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