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Give a geometric description of the following sets of points. $$x^{2}+y^{2}+z^{2}-8 x-14 y-18 z \leq 79$$

Short Answer

Expert verified
Answer: The geometric shape represented by the given inequality is a sphere with center (4, 7, 9) and a radius of 15. All points within the sphere satisfy the inequality.

Step by step solution

01

Rewrite inequality by completing the square

To rewrite the inequality by completing the square, we will rewrite it in the form of \((x-a)^2+(y-b)^2+(z-c)^2 \leq r^2\): $$x^{2}+y^{2}+z^{2}-8 x-14 y-18 z \leq 79$$ To complete the square, we need to find the square of the half of the coefficient of \(x\), \(y\), and \(z\) terms: For \(x\), \((-8/2)^2 = 16\); For \(y\), \((-14/2)^2 = 49\); For \(z\), \((-18/2)^2 = 81\). Now, add and subtract these values to the inequality: $$ (x^2-8x + 16) + (y^2-14y + 49) + (z^2 -18z + 81) \leq 79 + 16 + 49 + 81$$
02

Simplify inequality and rewrite as a standard equation

Now, we can group and simplify the inequality expression and rewrite it in the form of a standard equation: $$(x-4)^2+(y-7)^2+(z-9)^2 \leq 225$$
03

Interpret the geometric shape and its properties

Comparing this inequality to the standard form of the equation of a sphere, \((x-a)^2+(y-b)^2+(z-c)^2\leq r^2\), we can deduce that: The geometric shape represented by the inequality is a sphere with center \((a, b, c) = (4, 7, 9)\) and a radius \(r = 15\). All points within the sphere satisfy the inequality.

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