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Prove that for integers \(m\) and \(n\), the curve $$\mathbf{r}(t)=\langle a \sin m t \cos n t, b \sin m t \sin n t, c \cos m t\rangle$$ lies on the surface of a sphere provided \(a^{2}+b^{2}=c^{2}\).

Short Answer

Expert verified
Answer: The curve will lie on the surface of a sphere if the condition $a^2 + b^2 = c^2$ is satisfied.

Step by step solution

01

Substitute the parameter t into the expression for the curve

We begin by substituting the value of the parameter \(t\) into the expression of the parametric curve \(\mathbf{r}(t)\): $$ \mathbf{r}(t) = \langle a \sin(mt) \cos(nt), b \sin(mt) \sin(nt), c \cos(mt) \rangle. $$ Let the coordinates be \(x, y, z\): $$ x = a \sin(mt) \cos(nt), $$ $$ y = b \sin(mt) \sin(nt), $$ $$ z = c \cos(mt). $$
02

Square and add the coordinates

Now, we will square each coordinate and add them together to see if we can manipulate the resulting expression to get the equation of a sphere. $$ x^2 + y^2 + z^2 = (a \sin(mt) \cos(nt))^2 + (b \sin(mt) \sin(nt))^2 + (c \cos(mt))^2. $$
03

Manipulate the expression

Next, we will manipulate the expression to get an equation in the form \((x-x_0)^2 + (y-y_0)^2 + (z-z_0)^2 = R^2\). Let's rewrite the sum as follows: $$ x^2 + y^2 + z^2 = a^2 \sin^2(mt) \cos^2(nt) + b^2 \sin^2(mt) \sin^2(nt) + c^2 \cos^2(mt). $$ Observe that \(\cos^2(nt) + \sin^2(nt) = 1\) and factor out \(\sin^2(mt)\) and \(\cos^2(mt)\) from the first two terms: $$ x^2 + y^2 + z^2 = (\sin^2(mt))(a^2\cos^2(nt) + b^2\sin^2(nt)) + c^2\cos^2(mt). $$ Now use the identity \(\sin^2(mt) + \cos^2(mt) = 1\): $$ x^2 + y^2 + z^2 = (\sin^2(mt))(a^2\cos^2(nt) + b^2\sin^2(nt)) + c^2(1 - \sin^2(mt)). $$
04

Verify the condition

We must show that the expression above will lead to the equation of a sphere provided \(a^2 + b^2 = c^2\). Rewrite the condition as \(c^2 - a^2 = b^2\). Now let's substitute the condition into our expression: $$ x^2 + y^2 + z^2 = (\sin^2(mt))(a^2\cos^2(nt) + (c^2 - a^2)\sin^2(nt)) + c^2(1 - \sin^2(mt)). $$ After simplifying the equation, we get: $$ x^2 + y^2 + z^2 = c^2. $$ This is the equation of a sphere with center \((0,0,0)\) and radius \(c\), which is the desired result. So, for integers \(m\) and \(n\), the curve lies on the surface of a sphere if the condition \(a^2 + b^2 = c^2\) is satisfied.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sphere
A sphere is a perfectly round three-dimensional shape, similar to a ball. It can be defined mathematically as the set of all points in space that are equidistant from a given point called the center. The distance from any point on the sphere to the center is known as the radius.
The standard equation for a sphere centered at the origin with radius \( R \) is given by:
  • \( x^2 + y^2 + z^2 = R^2 \)
This means any point \( (x, y, z) \) that satisfies this equation lies on the sphere's surface.
Spheres are often encountered in physics, engineering, and various mathematical contexts, such as when studying geometric properties and volume.
In the given exercise, the problem confirms whether a specific parametric curve lies on the surface of a sphere by reformulating the parametric equations to fit the equation of a sphere.
Curve
In mathematics, a curve is a continuous and smooth flowing line without sharp corners or singularities. Curves can exist in two-dimensional or three-dimensional spaces and are described using parametric equations, which define a set of parameters often related to time.
The given exercise describes a curve using a parametric equation in three-dimensional space:
  • \( \mathbf{r}(t) = \langle a\sin(mt)\cos(nt), b\sin(mt)\sin(nt), c\cos(mt) \rangle \)
Curves can take various shapes and must be analyzed to understand their behavior, such as knowing if they lie on certain geometrical surfaces like spheres.
The properties of a curve can be explored by algebraically manipulating its equations, which in this case involves trigonometric identities and the condition \( a^2 + b^2 = c^2 \) to verify if it lies on a sphere.
Trigonometric Identities
Trigonometric identities are mathematical equations involving trigonometric functions that hold true for all values of the variables involved. They simplify complex trigonometric expressions and are crucial for solving problems in calculus and geometry.
Common trigonometric identities include:
  • \( \sin^2(\theta) + \cos^2(\theta) = 1 \)
  • \( \sin(2\theta) = 2\sin(\theta)\cos(\theta) \)
  • \( \cos(2\theta) = \cos^2(\theta) - \sin^2(\theta) \)
In the provided exercise, the identity \( \sin^2(mt) + \cos^2(mt) = 1 \) is particularly important. It helps confirm that the sum of squares \( x^2 + y^2 + z^2 \) conforms to an equation of a sphere when manipulated appropriately.
Understanding and applying these identities helps reduce the complexity of trigonometric expressions, making it easier to draw conclusions about the nature of curves and their relation to geometric shapes.
Vectors
Vectors are mathematical objects used to represent quantities that have both magnitude and direction. They are essential in physics, engineering, and mathematics, particularly when analyzing motion and forces in three-dimensional space.
A vector can be denoted in terms of its components along the coordinate axes. In 3D, a vector \( \mathbf{v} \) is written as:
  • \( \mathbf{v} = \langle v_x, v_y, v_z \rangle \)
In the given problem, the equation \( \mathbf{r}(t) = \langle a \sin(mt)\cos(nt), b \sin(mt)\sin(nt), c \cos(mt) \rangle \) is a parametric representation of a vector that describes a point on the curve as a function of the parameter \( t \).
Manipulating vectors and understanding their relationships is key to solving problems that involve trajectories, rotations, and positioning in space. The exercise demonstrates how vectors are used to describe geometrical shapes like spheres through parametric equations.

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Most popular questions from this chapter

A golfer launches a tee shot down a horizontal fairway and it follows a path given by \(\mathbf{r}(t)=\left\langle a t,(75-0.1 a) t,-5 t^{2}+80 t\right\rangle,\) where \(t \geq 0\) measures time in seconds and \(\mathbf{r}\) has units of feet. The \(y\) -axis points straight down the fairway and the z-axis points vertically upward. The parameter \(a\) is the slice factor that determines how much the shot deviates from a straight path down the fairway. a. With no slice \((a=0),\) sketch and describe the shot. How far does the ball travel horizontally (the distance between the point the ball leaves the ground and the point where it first strikes the ground)? b. With a slice \((a=0.2),\) sketch and describe the shot. How far does the ball travel horizontally? c. How far does the ball travel horizontally with \(a=2.5 ?\)

Trajectory with a sloped landing Assume an object is launched from the origin with an initial speed \(\left|\mathbf{v}_{0}\right|\) at an angle \(\alpha\) to the horizontal, where \(0 < \alpha < \frac{\pi}{2}\) a. Find the time of flight, range, and maximum height (relative to the launch point) of the trajectory if the ground slopes downward at a constant angle of \(\theta\) from the launch site, where \(0 < \theta < \frac{\pi}{2}\) b. Find the time of flight, range, and maximum height of the trajectory if the ground slopes upward at a constant angle of \(\theta\) from the launch site.

Consider the curve \(\mathbf{r}(t)=(a \cos t+b \sin t) \mathbf{i}+(c \cos t+d \sin t) \mathbf{j}+(e \cos t+f \sin t) \mathbf{k}\) where \(a, b, c, d, e,\) and fare real numbers. It can be shown that this curve lies in a plane. Find a general expression for a nonzero vector orthogonal to the plane containing the curve. $$\begin{aligned} \mathbf{r}(t)=&(a \cos t+b \sin t) \mathbf{i}+(c \cos t+d \sin t) \mathbf{j} \\\ &+(e \cos t+f \sin t) \mathbf{k} \end{aligned}$$ where \(\langle a, c, e\rangle \times\langle b, d, f\rangle \neq \mathbf{0}.\)

Find the domains of the following vector-valued functions. $$\mathbf{r}(t)=\sqrt{t+2} \mathbf{i}+\sqrt{2-t} \mathbf{j}$$

In contrast to the proof in Exercise \(81,\) we now use coordinates and position vectors to prove the same result. Without loss of generality, let \(P\left(x_{1}, y_{1}, 0\right)\) and \(Q\left(x_{2}, y_{2}, 0\right)\) be two points in the \(x y\) -plane and let \(R\left(x_{3}, y_{3}, z_{3}\right)\) be a third point, such that \(P, Q,\) and \(R\) do not lie on a line. Consider \(\triangle P Q R\). a. Let \(M_{1}\) be the midpoint of the side \(P Q\). Find the coordinates of \(M_{1}\) and the components of the vector \(\overrightarrow{R M}_{1}\) b. Find the vector \(\overrightarrow{O Z}_{1}\) from the origin to the point \(Z_{1}\) two-thirds of the way along \(\overrightarrow{R M}_{1}\). c. Repeat the calculation of part (b) with the midpoint \(M_{2}\) of \(R Q\) and the vector \(\overrightarrow{P M}_{2}\) to obtain the vector \(\overrightarrow{O Z}_{2}\) d. Repeat the calculation of part (b) with the midpoint \(M_{3}\) of \(P R\) and the vector \(\overline{Q M}_{3}\) to obtain the vector \(\overrightarrow{O Z}_{3}\) e. Conclude that the medians of \(\triangle P Q R\) intersect at a point. Give the coordinates of the point. f. With \(P(2,4,0), Q(4,1,0),\) and \(R(6,3,4),\) find the point at which the medians of \(\triangle P Q R\) intersect.

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