/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 Graph the curves described by th... [FREE SOLUTION] | 91Ó°ÊÓ

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Graph the curves described by the following functions, indicating the direction of positive orientation. Try to anticipate the shape of the curve before using a graphing utility. $$\mathbf{r}(t)=4 \sin t \mathbf{i}+4 \cos t \mathbf{j}+e^{-t / 10} \mathbf{k}, \text { for } 0 \leq t < \infty$$

Short Answer

Expert verified
Answer: The curve has a downward spiral shape in the positive orientation, with its x and y components forming a circle of radius 4 in the xy-plane and its z-component decreasing as t increases.

Step by step solution

01

Write the function in parametric form

First, let's write the function in its parametric form. This will help us observe each component with respect to the independent variable 't'. $$x(t) = 4\sin t$$ $$y(t) = 4\cos t$$ $$z(t) = e^{-t/10}$$
02

Observe the components

By looking at the x and y components, which are given by trigonometric functions \(\sin\) t and \(\cos\) t, respectively, we can observe that they describe a circle of radius 4 in the xy-plane. The z-component is an exponential function, meaning that it will either increase or decrease as t varies.
03

Analyze the z-component

Now let's look closer at the z-component, $$z(t) = e^{-t/10}$$. Notice that for t = 0, z = 1 and as t approaches infinity, z approaches 0. This tells us that the z-component starts at height 1 and gradually decreases toward the xy-plane.
04

Sketch the curve

Now we can sketch the curve in 3D space with the information we've gathered. A circle of radius 4 is drawn in the xy-plane, and as we move in the positive direction of t, it spirals downward toward the xy-plane, due to the decreasing z-component.
05

Show the positive orientation

The positive orientation of the curve is given by an increase in the parameter t. The curve will move in a circular motion in the xy-plane, starting at the point (0, 4, 1) and gradually spiraling down towards the xy-plane. To summarize, the curve described by the given function is a downward spiral in the positive orientation, with its x and y components forming a circle of radius 4 in the xy-plane and its z-component decreasing as t increases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Functions
Trigonometric functions, such as sine and cosine, play a crucial role in understanding parametric curves, especially in a circle's formation. These functions allow us to map angles to ratios, describing circular motion. For the function given by
  • \(x(t) = 4 \sin t\)
  • \(y(t) = 4 \cos t\)
these trigonometric functions describe a circle of radius 4 in the xy-plane. This happens because
  • \(\sin^{2} t + \cos^{2} t = 1\),
  • which transforms to \((\frac{x}{4})^2 + (\frac{y}{4})^2 = 1\).
This is the equation of a circle centered at the origin with a radius of 4. Therefore, as the parameter \(t\) changes, it sweeps out a circle in the xy-plane, a fundamental property of trigonometric functions in parametric equations.
Understanding the connection between trigonometric functions and circular motion is key to visualizing and analyzing the shape of such curves.
Exponential Functions
The z-component of our curve involves an exponential function. In the context of parametric curves, exponential functions describe growth or decay processes. Here with the function:
  • \(z(t) = e^{-t/10}\)
Starting from 1 when \(t = 0\), the exponential decrease indicates a decline towards 0 as \(t\) increases. This natural decay implies that our curve descends from its initial height to approach the plane where \(z = 0\), giving us the downward spiral effect. Exponential functions are unique in their asymptotic behavior, which means they approach a particular value (0 in this case) but never quite touch it.
It's important to recognize how exponential functions influence the three-dimensional shape of parametric curves by modulating the z-component, transitioning from initial values and moving asymptomatically over time.
3D Graphing
Graphing in three dimensions allows us to visualize spatial relationships and movements that cannot be seen on a 2D plane. Through the coordinates generated by the parametric functions for \(x(t), y(t), z(t)\), we can understand how a curve progresses through space. In this scenario:
  • The xy-plane forms a base circle via trigonometric functions.
  • The z-component's exponential decay adds a vertical element, causing the curve to spiral down.
In 3D graphing, you need to consider all three axes simultaneously, observing how the x, y, and z components interact over the parameter \(t\). Using graphing tools or software can significantly aid understanding as they create dynamic visuals, helping to predict the curve's behavior. Drawing these sections occurs layer by layer, with each new t-value adding to the existing structure, until you have a fully formed 3D curve. It's crucial to appreciate how the parametric equations drive these compositions to visualize them accurately.
Orientation of Curves
Understanding the orientation is essential in the creation and interpretation of parametric curves. The orientation is determined by the way the parameter \(t\) progresses, in this case, over the interval \([0, \infty)\). This decides the path and the direction a point moves along the curve. As outlined:
  • The positive orientation implies starting at the point \((0, 4, 1)\).
  • Then, the curve spirals downward in a counterclockwise direction within the xy-plane due to trigonometric properties.
This movement reflects the spiral's downward trajectory and how it wraps around, creating a helix-like shape above the xy-plane. Recognizing the orientation helps fully understand practical applications like determining paths in trajectory problems or visualizing helical springs in physics. To determine orientation precisely in complex problems, it can be beneficial to test various 't'-values and observe the resulting vector positions for direction clues. Ensuring clarity in orientation clarifies and consolidates your understanding of 3D parametric curves.

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Most popular questions from this chapter

A baseball leaves the hand of a pitcher 6 vertical feet above home plate and \(60 \mathrm{ft}\) from home plate. Assume that the coordinate axes are oriented as shown in the figure. a. In the absence of all forces except gravity, assume that a pitch is thrown with an initial velocity of \(\langle 130,0,-3\rangle \mathrm{ft} / \mathrm{s}\) (about \(90 \mathrm{mi} / \mathrm{hr}\) ). How far above the ground is the ball when it crosses home plate and how long does it take for the pitch to arrive? b. What vertical velocity component should the pitcher use so that the pitch crosses home plate exactly \(3 \mathrm{ft}\) above the ground? c. A simple model to describe the curve of a baseball assumes that the spin of the ball produces a constant sideways acceleration (in the \(y\) -direction) of \(c \mathrm{ft} / \mathrm{s}^{2}\). Assume a pitcher throws a curve ball with \(c=8 \mathrm{ft} / \mathrm{s}^{2}\) (one-fourth the acceleration of gravity). How far does the ball move in the \(y\) -direction by the time it reaches home plate, assuming an initial velocity of (130,0,-3) ft/s? d. In part (c), does the ball curve more in the first half of its trip to the plate or in the second half? How does this fact affect the batter? e. Suppose the pitcher releases the ball from an initial position of (0,-3,6) with initial velocity \((130,0,-3) .\) What value of the spin parameter \(c\) is needed to put the ball over home plate passing through the point (60,0,3)\(?\)

Determine the equation of the line that is perpendicular to the lines \(\mathbf{r}(t)=\langle-2+3 t, 2 t, 3 t\rangle\) and \(\mathbf{R}(s)=\langle-6+s,-8+2 s,-12+3 s\rangle\) and passes through the point of intersection of the lines \(\mathbf{r}\) and \(\mathbf{R}\).

Consider the parallelogram with adjacent sides \(\mathbf{u}\) and \(\mathbf{v}\). a. Show that the diagonals of the parallelogram are \(\mathbf{u}+\mathbf{v}\) and \(\mathbf{u}-\mathbf{v}\). b. Prove that the diagonals have the same length if and only if \(\mathbf{u} \cdot \mathbf{v}=0\). c. Show that the sum of the squares of the lengths of the diagonals equals the sum of the squares of the lengths of the sides.

An object moves on the helix \(\langle\cos t, \sin t, t\rangle,\) for \(t \geq 0\) a. Find a position function \(\mathbf{r}\) that describes the motion if it occurs with a constant speed of \(10 .\) b. Find a position function \(\mathbf{r}\) that describes the motion if it occurs with speed \(t\)

For the following vectors u and \(\mathbf{v}\) express u as the sum \(\mathbf{u}=\mathbf{p}+\mathbf{n},\) where \(\mathbf{p}\) is parallel to \(\mathbf{v}\) and \(\mathbf{n}\) is orthogonal to \(\mathbf{v}\). \(\mathbf{u}=\langle 4,3\rangle, \mathbf{v}=\langle 1,1\rangle\)

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