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Find an equation of the line segment joining the first point to the second point. $$(1,0,1) \text { and }(0,-2,1)$$

Short Answer

Expert verified
Answer: The equation of the line segment is x = 1 - t, y = -2t, z = 1, where 0 ≤ t ≤ 1.

Step by step solution

01

Calculate the direction ratios

To find the direction ratios (k, l, m), subtract the coordinates of the second point from the first point: k = x2 - x1, l = y2 - y1, and m = z2 - z1. So we have: k=-1, l=-2, and m=0.
02

Write the parametric equation of the line

Now we can write the parametric equation of the line using the direction ratios (k, l, m) and the initial point (x1, y1, z1) = (1, 0, 1). The parametric equation of the line is: x = x1 + kt = 1 - t, y = y1 + lt = -2t, z = z1 + mt = 1.
03

Write the line segment equation

We have the parametric equation of the line passing through the given points. Since it's a line segment, the parameter t must fall within a certain range. In this case, the range is 0 ≤ t ≤ 1. The equation of the line segment joining the points (1,0,1) and (0,-2,1) is: x = 1 - t, y = -2t, z = 1, where 0 ≤ t ≤ 1.

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