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For Activities 9 through \(16,\) write formulas for the indicated partial derivatives for each of the multivariable functions. \(g(k, m)=k^{3} m^{5}-2 k m\) a. \(g_{k}\) b. \(g_{m}\) c. \(\left.g_{m}\right|_{k=2}\)

Short Answer

Expert verified
\(g_k = 3k^2 m^5 - 2m\), \(g_m = 5k^3 m^4 - 2k\), \(g_m|_{k=2} = 40m^4 - 4\).

Step by step solution

01

Understanding Partial Derivatives

First, recall that a partial derivative of a function with respect to a variable is the derivative of the function while treating all other variables as constants. In this exercise, we will differentiate the function \( g(k, m) = k^3 m^5 - 2km \) with respect to \( k \) and \( m \).
02

Finding \( g_k \)

To find the partial derivative of \( g \) with respect to \( k \) (denoted \( g_k \)), differentiate the function \( g(k, m) = k^3 m^5 - 2km \) with respect to \( k \) only, treating \( m \) as a constant:\[\frac{\partial}{\partial k}(k^3 m^5 - 2km) = 3k^2 m^5 - 2m.\]
03

Finding \( g_m \)

To find the partial derivative of \( g \) with respect to \( m \) (denoted \( g_m \)), differentiate the function \( g(k, m) = k^3 m^5 - 2km \) with respect to \( m \) only, treating \( k \) as a constant:\[\frac{\partial}{\partial m}(k^3 m^5 - 2km) = 5k^3 m^4 - 2k.\]
04

Evaluating \( g_m \) at \( k=2 \)

For \( g_m \) evaluated at \( k = 2 \), substitute \( k = 2 \) into the partial derivative \( g_m = 5k^3 m^4 - 2k \):\[5(2)^3 m^4 - 2(2) = 40m^4 - 4.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Multivariable Functions
Multivariable functions are intriguing mathematical entities that involve two or more variables. In simpler terms, these are functions where the output depends on several inputs. For example, the function given in the exercise is \(g(k, m) = k^3 m^5 - 2km\). Here, the output of the function depends on both variables, \(k\) and \(m\).

To understand multivariable functions, it is helpful to think about how changing one variable can affect the overall function. Each variable can influence the function's outcome in a different way.

  • \(k^3 m^5\): The term in the function where both \(k\) and \(m\) interact in more complex ways.
  • \(-2km\): Shows a direct interaction between the two variables.
While single-variable functions describe a line or curve in a two-dimensional space, multivariable functions represent surfaces or more complex shapes within three or higher dimensions.

This makes working with them a fascinating part of calculus, especially when exploring how changes in one variable affect the whole system.
Derivative with respect to a variable
In the context of multivariable functions, taking the derivative with respect to a single variable means finding out how the function's value changes as only that particular variable changes, keeping others constant. This process is called partial differentiation.

To take the derivative with respect to a variable, focus on treating other variables as constants. For example, in the function \(g(k, m) = k^3 m^5 - 2km\), when you find the partial derivative with respect to \(k\), you treat \(m\) as a constant, and vice versa.

  • Partial derivative with respect to \(k\): Derivate \(g\) by treating \(m\) as a constant, resulting in \(g_k = 3k^2 m^5 - 2m\).
  • Partial derivative with respect to \(m\): Derivate \(g\) by treating \(k\) as constant, yielding \(g_m = 5k^3 m^4 - 2k\).
Finding each partial derivative helps in understanding the function's sensitivity regarding each specific variable, while keeping in mind that each variable can have a distinct impact on the outcome.
Evaluating Partial Derivatives
Once you have calculated the partial derivatives for each variable, as in the exercise, the next step is often to evaluate these at specific values to understand the behavior of the function at particular points. This involves substituting specific values of the variables into the partial derivative.

For example, evaluating the partial derivative \(g_m\) when \(k = 2\) means substitute \(k = 2\) into \(g_m = 5k^3 m^4 - 2k\):
  • This gives \(5(2)^3 m^4 - 2(2) = 40m^4 - 4\).
By doing such evaluations, you can observe how parts of a system are interrelated, and predict how changes in variables affect the whole structure.

Evaluating partial derivatives is key in applications like optimization, where you might seek to maximize or minimize certain functions by analyzing their derivatives at specific points.

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Most popular questions from this chapter

Timber Volume In the timber industry, being able to predict the volume of wood in a tree stem is important,especially when one is trying to determine the number of boards a tree will yield. In \(1973,\) Brackett developed the following model for predicting the total-stem (inside bark) volume for Douglas fir trees in British Columbia: $$ V(d, b)=0.002198 d^{1.739925} h^{1.133187} \text { cubic feet } $$ where \(d\) is the diameter of the tree at breast height (4.5 feet above the ground), which is denoted by dbh and measured in inches, and \(b\) is the height of the tree in feet. (Source: J. L. Clutter et al., Timber Management: A Quamtitative Approach, New York: Wiley, 1983\()\) a. Find the stem volume of a Douglas fir with a dbh of 1 foot and a height of 32 feet. b. Draw a contour curve representing the volume found in part \(a\) for \(\mathrm{dbh}(\mathrm{s})\) between 8 inches and 18 inches. c. Explain how a change in dbh affects height if volume remains constant.

For Activities 17 through \(22,\) write the first and second partial derivatives. $$ h(x, y)=e^{2 x-3 y} $$

Sketch the contour curve indicated in the activity. Sketch the tangent line indicated and calculate its slope. $$ \begin{aligned} &f(s, t)=s \ln (2 t)+e^{-1.34 t}\\\ &f(s, t)=2 \text { for } 1 \leq t \leq 20\\\ &\text { tangent line at } t=10 \end{aligned} $$

Payments The amount of a monthly payment on a loan with \(6 \%\) interest compounded monthly can be calculated as $$ m(A, t)=\frac{0.005 A}{1-0.9419^{t}} \text { dollars } $$ when the loan is for \(A\) dollars and is to be repaid over \(t\) years. a. What is the monthly payment for a loan of \(\$ 10,000\) to be repaid over a period of 5 years? b. Approximate the amount that could be borrowed withour increasing or decreasing the monthly payment determined in part \(a\) if the term of the loan is 4 years instead of \(5 .\)

Future Value The future value \(F(P, r)\) of an investment of \(P\) dollars after 2 years in an account with annual percentage yield \(100 r \%\) is given by the function \(F(P, r)=P(1+r)^{2}\) dollars. a. Write a model for \(F(14,000, r)\). b. Calculate and interpret \(\left.\frac{\partial F}{\partial r}\right|_{(P, r)=(14,000,0.1272)} .\) c. Explain how the rate of change in part \(b\) is related to a graph of the cross-sectional function in part \(a\). Illustrate graphically.

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