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Payments The amount of a monthly payment on a loan with \(6 \%\) interest compounded monthly can be calculated as $$ m(A, t)=\frac{0.005 A}{1-0.9419^{t}} \text { dollars } $$ when the loan is for \(A\) dollars and is to be repaid over \(t\) years. a. What is the monthly payment for a loan of \(\$ 10,000\) to be repaid over a period of 5 years? b. Approximate the amount that could be borrowed withour increasing or decreasing the monthly payment determined in part \(a\) if the term of the loan is 4 years instead of \(5 .\)

Short Answer

Expert verified
Part (a): Monthly payment is \( \$187.02 \). Part (b): Borrowed amount is approximately \( \$7900.50 \).

Step by step solution

01

Identify the Given Values for Part (a)

We are given that the loan amount, \( A \), is \( \$10,000 \), and the repayment period, \( t \), is 5 years. We must substitute these values into the formula to calculate the monthly payment.
02

Substitute Into the Formula for Part (a)

Using the formula \( m(A, t) = \frac{0.005A}{1-0.9419^t} \), substitute \( A = 10,000 \) and \( t = 5 \) years:\[ m(10,000, 5) = \frac{0.005 \times 10,000}{1 - 0.9419^5} \]
03

Perform the Calculation for Part (a)

First, calculate \( 0.9419^5 \):\[ 0.9419^5 \approx 0.7326 \]Then, substitute to find the monthly payment:\[ m(10,000, 5) = \frac{50}{1 - 0.7326} \approx \frac{50}{0.2674} \approx 187.02 \]The monthly payment is approximately \( \$187.02 \).
04

Identify the Given Values for Part (b)

For part (b), we maintain the monthly payment of approximately \( \$187.02 \), but the loan term \( t \) is now 4 years. We need to solve for the loan amount \( A \) that results in this payment.
05

Rearrange the Formula for Part (b)

The original formula is \( m(A, t) = \frac{0.005A}{1-0.9419^t} \).Rearrange to solve for \( A \):\[ A = \frac{m(1-0.9419^t)}{0.005} \]Here, \( m = 187.02 \) and \( t = 4 \).
06

Perform the Calculation for Part (b)

Calculate \( 0.9419^4 \):\[ 0.9419^4 \approx 0.7886 \]Substitute into the rearranged formula:\[ A = \frac{187.02(1 - 0.7886)}{0.005} \approx \frac{187.02 \times 0.2114}{0.005} \approx 7900.50 \]The amount that could be borrowed is approximately \( \$7900.50 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Compound Interest
Compound interest is a fundamental concept in financial mathematics. Unlike simple interest, where interest is only applied to the initial principal, compound interest applies interest on accumulated interest over time as well. This means that over the life of a loan, the amount owed grows at an accelerating rate because interest is added to the principal balance at regular intervals.
In loan calculations, interest may be compounded annually, monthly, or at other regular intervals. In our case, the interest rate is compounded monthly, which means it is applied to the balance 12 times a year. This can significantly affect the total amount paid over the term of a loan.
  • Monthly compounding involves dividing the annual interest rate by 12.
  • The effect of compounding means borrowers pay more over the life of a loan compared to simple interest.
Understanding compound interest is crucial for making informed financial decisions as it highlights how fast costs can accumulate.
Monthly Payment Formula
The monthly payment formula is a practical tool designed to determine the fixed amount one must pay monthly to repay a loan within a specific time frame. For a loan with compound interest, the formula becomes necessary to spread the repayment into manageable monthly installments.
In our given exercise, the monthly payment formula is: \[ m(A, t) = \frac{0.005A}{1-0.9419^t}\]This formula takes into account:
  • The loan amount \(A\), representing the total sum borrowed.
  • The interest rate, reflected by the factor 0.005.
  • The loan term \(t\), over which the loan will be repaid, impacting the number of payments.
By plugging in the loan amount and term, this formula calculates the necessary monthly payment. For instance, when \(A = 10,000\) and \(t = 5\), the calculated payment ensures the entire loan plus interest is paid by the end of the term.
Loan Repayment Term
The loan repayment term is a key factor in loan calculations as it determines over what period the loan must be repaid. It directly influences both the total amount of interest paid and the size of the monthly payments.
Shorter loan terms result in higher monthly payments because the principal amount has to be divided over fewer months. However, this often means paying less total interest over the life of the loan. Conversely, longer terms mean smaller monthly payments but can significantly increase the total interest paid.
For example, in the exercise, reducing the loan term from 5 years to 4 years requires recalculating the loan amount that can be borrowed without altering the monthly payment. This demonstrates how the repayment term affects the borrowing capacity.
Financial Mathematics
Financial mathematics forms the backbone of understanding and managing financial commitments like loans. It involves the use of mathematical models and formulas to simplify complex calculations involved in financial transactions.
Key principles in financial mathematics include:
  • Interest calculations (both simple and compound).
  • Time value of money, understanding that future money is worth less than present money.
  • Amortization schedules defining how loans are paid off over time.
This field enables individuals to analyze loan offers, decide on investment strategies, and plan for future financial needs effectively. The exercise showcases how these mathematical concepts provide insights into the implications of borrowing, thereby aiding in better financial decision-making.

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Most popular questions from this chapter

Future Value The future value \(F(t, r)\) of an investment of \(\$ 1000\) after \(t\) years in an account for which the interest rate is \(100 r \%\) compounded continuously is given by the function \(F(t, r)=1000 e^{r t}\) dollars. a. Find and interpret \(F(10, r)\). b. Find and interpret \(\left.\frac{\partial F}{\partial r}\right|_{(t, r)=(10,0.072)}\). c. Explain how the rate of change in part \(b\) is related to a graph of the cross-sectional function in part \(a\). Illustrate graphically.

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