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Suppose that \(g\) with input \(t\) is an exponential density function with \(k=2\). a. Find \(G,\) the corresponding cumulative distribution function. b. Use both \(g\) and \(G\) to calculate the probability that \(t \leq 0.35\) c. Use \(G\) to calculate the probability that \(t>0.86\).

Short Answer

Expert verified
a. \(G(t) = 1 - e^{-2t}\). b. \(P(t \leq 0.35) \approx 0.5034\). c. \(P(t > 0.86) \approx 0.178\).

Step by step solution

01

Identify the Exponential Density Function

The probability density function (PDF) for an exponential distribution with rate parameter \(k\) is given by \(g(t) = ke^{-kt}\) for \(t \geq 0\). Here, the rate parameter \(k\) is given as 2, so the PDF is \(g(t) = 2e^{-2t}\).
02

Determine the Cumulative Distribution Function (CDF)

The cumulative distribution function \(G(t)\) is found by integrating the PDF from 0 to \(t\). Thus, \(G(t) = \int_{0}^{t} 2e^{-2x}dx\). Solving this integral, we get \(G(t) = 1 - e^{-2t}\).
03

Calculate Probability for Part (b)

To find \(P(t \leq 0.35)\) using \(G(t)\), substitute \(t = 0.35\) into the CDF: \(G(0.35) = 1 - e^{-2 \times 0.35}\). Compute this to get \(G(0.35) = 1 - e^{-0.7}\), which approximately equals 0.5034. This is the probability \(P(t \leq 0.35)\).
04

Verify with PDF for Part (b)

Calculate \(P(t \leq 0.35)\) using \(g(t)\) by integrating the PDF from 0 to 0.35: \(\int_{0}^{0.35} 2e^{-2x}dx = 1 - e^{-0.7}\). This result verifies our CDF calculation: approximately 0.5034.
05

Calculate Probability for Part (c)

To calculate \(P(t > 0.86)\) using \(G(t)\), recognize that \(P(t > 0.86) = 1 - P(t \leq 0.86)\). First, find \(G(0.86) = 1 - e^{-2 \times 0.86}\). Then, \(P(t > 0.86) = 1 - (1 - e^{-1.72}) = e^{-1.72}\), which is approximately 0.178.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Distribution
The exponential distribution is a continuous probability distribution used to model the time until an event occurs. Typically, this involves scenarios like the time until a machine fails or the waiting time for a bus. It is characterized by a constant rate, meaning the event's occurrence is memoryless, which signifies that past events do not affect future probabilities. This makes it an essential tool in reliability testing and queuing theory.

Its probability density function (PDF) is given by:
  • \( g(t) = ke^{-kt} \) for \( t \geq 0 \)
The parameter \(k\) here influences the shape and rate of the distribution. The higher the value of \(k\), the steeper the decline of the function, indicating a shorter expected wait time until the event occurs. The exponential distribution is integrally tied to the Poisson distribution, often representing the time between Poisson occurrences.
Cumulative Distribution Function
The cumulative distribution function (CDF) of an exponential distribution provides a way to calculate the probability that a random variable \(t\) will take a value less than or equal to a specific value. It accumulates probabilities from the left and reaches 1 as \(t\) approaches infinity.

The CDF is defined as:
  • \( G(t) = p{0}^{t}g(x)dx \)
For the exponential distribution with \(g(t) = 2e^{-2t}\), integrating from 0 to \(t\) gives the cumulative function:
  • \( G(t) = 1 - e^{-2t} \)
This equation highlights how the distribution's memoryless property operates over time. The cumulative function \(G(t)\) is particularly useful for calculating probabilities for ranges in continuous distributions.
Rate Parameter
The rate parameter \(k\) is a critical component in understanding the exponential distribution. It represents how quickly the event you're studying is expected to happen. In mathematical terms, it is the reciprocal of the mean; thus,
  • \( ext{mean} = rac{1}{k} \)
A higher \(k\) value implies that the event is more frequent, leading to a steeper probability curve and shorter average time to the event. In the given problem, \(k\) is set to 2, meaning the average wait time for the event is 0.5 units of whatever time measurement is used.

The rate parameter is intrinsic to both the PDF and CDF, directly affecting the entire distribution's shape and behavior. It is vital in models where estimating time intervals is essential, like predicting life expectancy of systems or survival analysis.
Integration
Integration is a fundamental mathematical operation that helps determine the area under a curve. In the context of probability and statistics, integrating a Probability Density Function (PDF) over a specific range provides the probability of the random variable falling within that interval. For continuous distributions such as the exponential, this process is used to derive the cumulative distribution function (CDF).

To find the CDF \(G(t)\) of an exponential function, you integrate the PDF from zero to \(t\):
  • \( G(t) = p{0}^{t} ke^{-kx}dx \)
In our example, evaluating this integral gives:
  • \( G(t) = 1 - e^{-2t} \)
Essentially, integration transforms the instantaneous rate given by the PDF into a cumulative measure represented by the CDF. The process involves applying integration techniques, often requiring rules of calculus, to solve these mathematical expressions and translate them into probabilities.

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Most popular questions from this chapter

Frozen Yogurt Sales Let \(x\) represent the amount of frozen yogurt (in hundreds of gallons) sold by the G\&T restaurant on any day during the summer. Storage limitations dictate that the maximum amount of frozen yogurt that can be kept at G\&T on any given day is 250 gallons. Records of past sales indicate that the probability density function for \(x\) is approximated by \(y(x)=0.32 x\) for \(0 \leq x \leq 2.5\) a. What is the probability that on some summer day, G\&T will sell less than 100 gallons of frozen yogurt? b. What is the mean number of gallons of frozen yogurt G\&T expects to sell on a summer day? c. Sketch a graph of \(y\) and locate the mean on the graph and shade the region whose area is the answer to part \(a\).

Write an equation or differential equation for the given information. The rate of change in the height \(h\) of a tree with respect to its age \(a\) is inversely proportional to the tree's height.

Write a sentence of interpretation for the probability statement in the context of the given situation. \(P(d<72)=0.34,\) where the random variable \(d\) is the distance, in feet, between any two cars on a certain two-lane highway.

Postage Rates Between 1919 and \(1995,\) the rate of change in the rate of change of the postage required to mail a first-class, 1 -ounce letter was approximately 0.022 cent per year squared. The postage was 2 cents in \(1919,\) and it was increasing at the rate of approximately 0.393 cent per year in \(1958 .\) (Source: Based on data from the United States Postal Service) a. Write a differential equation for the rate of change in the rate of change of the first-class postage for a 1 -ounce letter in year \(t,\) where \(t\) is the number of years after 1900 . b. Find both a general and a particular solution to the differential equation in part \(a\). c. Use the previous results to estimate how rapidly the postage is changing in the current year and the current first-class postage for a 1 -ounce letter. Comment on the accuracy of the results. If they are not reasonable, give possible explanations.

Plow Patents The number of patents issued for plow sulkies between 1865 and 1925 was increasing with respect to time at a rate jointly proportional to the number of patents already obtained and to the difference between the number of patents already obtained and the carrying capacity of the system. The carrying capacity was approximately 2700 patents, and the constant of proportionality was about \(7.52 \cdot 10^{-5} .\) By 1883,980 patents had been obtained. (Source: Hamblin, Jacobsen, and Miller, \(A\) Mathematical Theory of Social Change, New York: Wiley, 1973 ) a. Write a differential equation describing the rate of change in the number of patents with respect to the number of years since 1865 b. Write a general solution for the differential equation. c. Write the particular solution for the differential equation. d. Estimate the number of patents obtained by 1900 .

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