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Write an equation or differential equation for the given information. The rate of change in the height \(h\) of a tree with respect to its age \(a\) is inversely proportional to the tree's height.

Short Answer

Expert verified
The differential equation is \( \frac{dh}{da} = \frac{k}{h} \).

Step by step solution

01

Understand the Proportionality

The problem states that the rate of change of the height of the tree, \( \frac{dh}{da} \), is inversely proportional to the height itself, \( h \). This means we can express this relationship mathematically as \( \frac{dh}{da} = \frac{k}{h} \), where \( k \) is a constant of proportionality.
02

Formulate the Differential Equation

Using the inverse proportionality, the differential equation representing the relationship can be written as \( \frac{dh}{da} = \frac{k}{h} \). This equation states that the derivative of height with respect to age is equal to a constant divided by the height.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportionality
Proportionality is a concept that describes a relationship between two quantities. When we say that one quantity is proportional to another, it means that they increase or decrease together at the same rate. We often express this using equations like
  • Direct Proportionality: \( y = kx \) where \( k \) is the constant of proportionality.
  • Inverse Proportionality: \( y = \frac{k}{x} \) where \( k \) remains constant as \( x \) changes.
In the context of our problem, we are dealing with inverse proportionality, where the rate of change in the height of a tree is inversely proportional to its height. This means that as the height of the tree increases, the rate at which it grows becomes slower, and vice versa.
Rate of Change
The rate of change is a measure of how one quantity changes in relation to another quantity. In our exercise, we are interested in how the height of a tree (\( h \)) changes as its age (\( a \)) increases. This is typically represented by the derivative, or \( \frac{dh}{da} \), which expresses how much the height changes for a small change in age.
The derivative allows us to understand the growth pattern of the tree. When we say the rate of change is related to another variable through proportionality, it becomes easy to draw equations representing real-world scenarios involving growth and decay, such as in trees, bacteria, or any other living organisms these examples might relate to.
Understanding rates of change is crucial in calculus and differential equations as it lays the groundwork for analyzing how things evolve over time.
Inverse Proportionality
Inverse proportionality means that as one quantity increases, the other decreases in such a way that their product remains constant. Mathematically, this is represented as\( y = \frac{k}{x} \), where \( k \) is a constant. In our differential equation context, the rate of change of the tree's height, \( \frac{dh}{da} \), is inversely proportional to the height itself.
This inverse relationship implies that the taller the tree gets, the slower its rate of growth in height. In the equation \( \frac{dh}{da} = \frac{k}{h} \), if the height of the tree is large, \( \frac{dh}{da} \) becomes small, and vice versa. This situation is common in natural growth processes where certain constraints cause growth to slow down as the entity becomes larger.

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Most popular questions from this chapter

Iowa Muskrats From 1936 through \(1957,\) a population of 15,000 muskrats in Iowa bred at a rate of 468 new muskrats per year and had a survival rate of \(75 \%\) (Source: Paul L. Errington, Muskrat Population, Ames: Iowa State University Press, 1963 ) a. How many of the muskrats alive in 1936 were still alive in \(1957 ?\) b. Write a function for the number of muskrats that were born \(t\) years after 1936 and were still alive in \(1957 .\) c. Estimate the muskrat population in \(1957 .\)

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Identify the differential equation as one that can be solved using only antiderivatives or as one for which separation of variables is required. Then find a general solution for the differential equation. $$ \frac{d y}{d x}=-x $$

Sculptures The average quantity of sculptures consumers will demand can be modeled as $$ D(p)=-1.003 p^{2}-20.689 p+850.375 \text { sculptures } $$ and the average quantity producers will supply can be modeled as $$ S(p)=\left\\{\begin{array}{ll} 0 & \text { for } p<4.5 \\ 0.26 p^{2}+8.1 p+250 & \text { for } p \geq 4.5 \end{array}\right. $$ where \(S(p)\) is measured in sculptures and the market price is \(p\) hundred dollars per sculpture. a. How much are consumers willing and able to spend for 20 sculptures? b. How many sculptures will producers supply at \(\$ 500\) per sculpture? Will supply exceed demand at this quantity? c. Calculate the total social gain when sculptures are sold at the equilibrium price.

Identify the differential equation as one that can be solved using only antiderivatives or as one for which separation of variables is required. Then find a general solution for the differential equation. $$ \frac{d y}{d x}=7 x(5-y) $$

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