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Verify the following statements for the uniform density function $$ u(x)=\left\\{\begin{array}{ll} \frac{1}{b-a} & \text { when } a \leq x \leq b \\ 0 & \text { when } xb \end{array}\right. $$ a. The mean is \(\mu=\frac{a+b}{2}\). b. The standard deviation is \(\sigma=\frac{b-a}{\sqrt{12}}\). c. The cumulative distribution function is $$ F(x)=\left\\{\begin{array}{ll} 0 & \text { when } x<0 \\ \frac{x-a}{b-a} & \text { when } a \leq x \leq b \\ 1 & \text { when } x>b \end{array}\right. $$

Short Answer

Expert verified
All statements are correct based on the properties of uniform distribution.

Step by step solution

01

Calculate the Mean

For a uniform distribution on the interval \([a, b]\), the mean \( \mu \) is given by the formula \( \mu = \frac{a+b}{2} \). This represents the average value of \(x\) over the interval, and it intuitively makes sense because it's the midpoint of the interval \([a, b]\).
02

Calculate the Variance

The variance \( \sigma^2 \) for a uniform distribution on \([a, b]\) is calculated using the formula \( \sigma^2 = \frac{(b-a)^2}{12} \). This formula derives from the nature of the distribution spread evenly across \([a, b]\).
03

Calculate the Standard Deviation

The standard deviation \( \sigma \) is simply the square root of the variance. Using the result from the previous step, \( \sigma = \sqrt{\frac{(b-a)^2}{12}} = \frac{b-a}{\sqrt{12}} \).
04

Derive the Cumulative Distribution Function (CDF)

To find the cumulative distribution function (CDF) for a uniform distribution on \([a, b]\), consider the following cases:1. For \( x < a \), the CDF \( F(x) = 0 \), since no values of \(x\) are captured.2. For \( a \leq x \leq b \), the CDF is the integral of the probability density function (PDF) from \( a \) to \( x \):\[ F(x) = \int_a^x \frac{1}{b-a} \, dt = \frac{x-a}{b-a} \]3. For \( x > b \), the CDF \( F(x) = 1 \), as all the values up to \( b \) are captured.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
The probability density function (PDF) of a uniform distribution describes how probabilities are distributed across the range of possible outcomes. For a uniform distribution defined on the interval \([a, b]\), the PDF is expressed as:
  • \(u(x) = \frac{1}{b-a}\) when \(a \leq x \leq b\)
  • \(u(x) = 0\) when \(x < a\) or \(x > b\)
This tells us that every value within the interval \([a, b]\) is equally likely. It results in a rectangular distribution where the height is constant over the interval, providing a uniform level of probability. Since the total area under the PDF must equal 1, the height of the rectangle is \(\frac{1}{b-a}\). It's important to remember that a PDF does not give probabilities of specific values but rather describes how probability density is distributed.
Cumulative Distribution Function
The cumulative distribution function (CDF) of a uniform distribution gives the probability that the random variable \(X\) is less than or equal to some value \(x\). This is represented by the following piece of wise function:
  • \(F(x) = 0\) for \(x < a\)
  • \(F(x) = \frac{x-a}{b-a}\) for \(a \leq x \leq b\)
  • \(F(x) = 1\) for \(x > b\)
These conditions intuitively capture the essence of increasing probability, as \(x\) expands from \(a\) to \(b\). For values of \(x\) below \(a\), no probability is accumulated, hence \(F(x) = 0\). As \(x\) progresses within the interval, the probability increases linearly, reaching \(1\) once \(x\) surpasses \(b\). The CDF effectively provides a comprehensive view of probability up to any point \(x\) along the interval.
Mean
The mean of a uniform distribution, often denoted as \(\mu\), is the average of all possible outcomes within the interval. For a uniform distribution across the range \([a, b]\), the formula for the mean is:\[\mu = \frac{a+b}{2}\]This is because the distribution is symmetric around its central point. Thus, the mean simply lies halfway between \(a\) and \(b\). It's a straightforward concept as the distribution is uniform and symmetric, leading to a perfectly centered average. Understanding the mean helps identify the 'central' location or 'center of mass' of the distribution.
Standard Deviation
Standard deviation is a measure of how spread out the values in a distribution are. In the context of a uniform distribution from \([a, b]\), the standard deviation \(\sigma\) can be calculated using the formula:\[\sigma = \frac{b-a}{\sqrt{12}}\]This formula comes from taking the square root of the variance, which measures the average squared distance of the distribution's values from the mean. The factor \(\sqrt{12}\) comes from the derivation process, capturing the uniform nature. A higher standard deviation suggests a wider spread of values, while a smaller one indicates a more central-tendency with values closer together. Understanding the standard deviation is critical for assessing the risk or variability in processes modeled by uniform distribution.

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Most popular questions from this chapter

Plow Patents The number of patents issued for plow sulkies between 1865 and 1925 was increasing with respect to time at a rate jointly proportional to the number of patents already obtained and to the difference between the number of patents already obtained and the carrying capacity of the system. The carrying capacity was approximately 2700 patents, and the constant of proportionality was about \(7.52 \cdot 10^{-5} .\) By 1883,980 patents had been obtained. (Source: Hamblin, Jacobsen, and Miller, \(A\) Mathematical Theory of Social Change, New York: Wiley, 1973 ) a. Write a differential equation describing the rate of change in the number of patents with respect to the number of years since 1865 b. Write a general solution for the differential equation. c. Write the particular solution for the differential equation. d. Estimate the number of patents obtained by 1900 .

Sculptures The average quantity of sculptures consumers will demand can be modeled as $$ D(p)=-1.003 p^{2}-20.689 p+850.375 \text { sculptures } $$ and the average quantity producers will supply can be modeled as $$ S(p)=\left\\{\begin{array}{ll} 0 & \text { for } p<4.5 \\ 0.26 p^{2}+8.1 p+250 & \text { for } p \geq 4.5 \end{array}\right. $$ where \(S(p)\) is measured in sculptures and the market price is \(p\) hundred dollars per sculpture. a. How much are consumers willing and able to spend for 20 sculptures? b. How many sculptures will producers supply at \(\$ 500\) per sculpture? Will supply exceed demand at this quantity? c. Calculate the total social gain when sculptures are sold at the equilibrium price.

Postage Rates Between 1919 and \(1995,\) the rate of change in the rate of change of the postage required to mail a first-class, 1 -ounce letter was approximately 0.022 cent per year squared. The postage was 2 cents in \(1919,\) and it was increasing at the rate of approximately 0.393 cent per year in \(1958 .\) (Source: Based on data from the United States Postal Service) a. Write a differential equation for the rate of change in the rate of change of the first-class postage for a 1 -ounce letter in year \(t,\) where \(t\) is the number of years after 1900 . b. Find both a general and a particular solution to the differential equation in part \(a\). c. Use the previous results to estimate how rapidly the postage is changing in the current year and the current first-class postage for a 1 -ounce letter. Comment on the accuracy of the results. If they are not reasonable, give possible explanations.

Learning Time The time (in minutes) required to learn the procedure for performing a certain task is uniformly distributed on the interval from 30 minutes to 50 minutes. a. What is the probability that it takes more than \(42 \mathrm{~min}-\) utes to learn the procedure? b. What is the average time required to learn the procedure?

Iowa Muskrats From 1936 through \(1957,\) a population of 15,000 muskrats in Iowa bred at a rate of 468 new muskrats per year and had a survival rate of \(75 \%\) (Source: Paul L. Errington, Muskrat Population, Ames: Iowa State University Press, 1963 ) a. How many of the muskrats alive in 1936 were still alive in \(1957 ?\) b. Write a function for the number of muskrats that were born \(t\) years after 1936 and were still alive in \(1957 .\) c. Estimate the muskrat population in \(1957 .\)

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