Chapter 3: Problem 14
In Activities 1 through \(30,\) for each of the composite functions, identify an inside function and an outside function and write the derivative with respect to \(x\) of the composite function. $$ f(x)=\frac{350}{4 x+7} $$
Short Answer
Expert verified
The derivative is \( f'(x) = -\frac{1400}{(4x+7)^2} \).
Step by step solution
01
Identifying the Inside Function
First, notice how the function is structured. The denominator of the fraction, \(4x + 7\), acts as the inside function. Let's denote this inside function as \(u(x) = 4x + 7\).
02
Identifying the Outside Function
The outside function operates on the result of the inside function. Here, the outside function is \( g(u) = \frac{350}{u}\). It takes \(u\) as its variable.
03
Applying the Chain Rule
To find the derivative of the composite function \( f(x) = g(u(x)) \), we use the chain rule: \( f'(x) = g'(u(x)) \, u'(x) \).
04
Calculating the Derivative of the Outside Function
The derivative of the outside function \( g(u) = \frac{350}{u} \) with respect to \( u \) is \( g'(u) = -\frac{350}{u^2} \).
05
Calculating the Derivative of the Inside Function
The derivative of the inside function \( u(x) = 4x + 7 \) is \( u'(x) = 4 \).
06
Combining the Derivatives
Substitute back the derivatives into the chain rule: \( f'(x) = -\frac{350}{(4x+7)^2} \times 4 \).
07
Simplifying the Expression
Multiply the derivatives together: \( f'(x) = -\frac{1400}{(4x+7)^2} \). This is the derivative of the composite function.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Composite Functions
In mathematics, a composite function involves two or more functions combined in such a way that the result of one function becomes the input for the next. This concept can feel a bit like a nesting doll, where one element sits inside another.
For example, in the given function \( f(x) = \frac{350}{4x+7} \), the overarching structure of the function suggests one function exists inside another.
By breaking it down, we notice that the denominator, \( 4x + 7 \), acts as an inner layer. When we assign it to \( u(x) \), it stands alone as \( u(x) = 4x + 7 \).
For example, in the given function \( f(x) = \frac{350}{4x+7} \), the overarching structure of the function suggests one function exists inside another.
By breaking it down, we notice that the denominator, \( 4x + 7 \), acts as an inner layer. When we assign it to \( u(x) \), it stands alone as \( u(x) = 4x + 7 \).
- Inner Function: Handles the input \( x \), modifying it as \( 4x + 7 \).
- Outer Function: Takes the result of the inner function \( u \) and uses it further, here represented by \( g(u) = \frac{350}{u} \).
Derivative Calculation
Calculating derivatives might seem like a complex task at first, but by using systematic methods such as the chain rule, the task becomes manageable. The chain rule provides a framework for differentiating composite functions by systematically working with each part. Here's how it works:
\[ f'(x) = -\frac{350}{(4x+7)^2} \times 4 \]
This results in a fully solved derivative:
\[ f'(x) = -\frac{1400}{(4x+7)^2} \]. Using this method ensures accuracy and efficiency in deriving the complicated forms.
- First, differentiate the outer function with respect to its input \( u \). In our example, the outer function is \( g(u) = \frac{350}{u} \), and its derivative is \( g'(u) = -\frac{350}{u^2} \).
- Second, differentiate the inner function with respect to \(x\). For \( u(x) = 4x + 7 \), we find \( u'(x) = 4 \).
\[ f'(x) = -\frac{350}{(4x+7)^2} \times 4 \]
This results in a fully solved derivative:
\[ f'(x) = -\frac{1400}{(4x+7)^2} \]. Using this method ensures accuracy and efficiency in deriving the complicated forms.
Inside and Outside Functions
Understanding inside and outside functions is crucial while dealing with composite functions. Let's explore:
The inside function is the part that initiates changes to the variable \( x \), often encapsulated within brackets or an inner layer of operations. Here, it's the \( 4x + 7 \) inside the denominator.
In contrast, the outside function is what wraps around the outcome of the inside function. For \( f(x) = \frac{350}{4x+7} \), the outside is \( \frac{350}{u} \), where \( u \) stands for the inside.
The inside function is the part that initiates changes to the variable \( x \), often encapsulated within brackets or an inner layer of operations. Here, it's the \( 4x + 7 \) inside the denominator.
In contrast, the outside function is what wraps around the outcome of the inside function. For \( f(x) = \frac{350}{4x+7} \), the outside is \( \frac{350}{u} \), where \( u \) stands for the inside.
- The inside function sets the stage, creating an output that serves as the sole input for the outside function.
- The outside function manipulates the result from the inside function, further transforming it into a final outcome.