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Write derivative formulas for the functions. $$ f(x)=4 x \sqrt{3 x+2}+93 $$

Short Answer

Expert verified
The derivative is \( f'(x) = \frac{18x + 8}{\sqrt{3x+2}} \).

Step by step solution

01

Identify the function's components

The function given is \( f(x) = 4x \sqrt{3x + 2} + 93 \). It has two components: the term \( 4x \sqrt{3x + 2} \) and the constant 93. The derivative of the constant is zero, so we only need to focus on the term \( 4x \sqrt{3x + 2} \).
02

Use the product rule for derivatives

The term \( 4x \sqrt{3x + 2} \) is a product of two functions: \( 4x \) and \( \sqrt{3x + 2} \). To differentiate this, we will use the product rule, which states that if \( u(x) \) and \( v(x) \) are functions of \( x \), then \( (u(x)v(x))' = u'(x)v(x) + u(x)v'(x) \). Here, let \( u(x) = 4x \) and \( v(x) = \sqrt{3x + 2} \).
03

Differentiate each component separately

First, find \( u'(x) \): the derivative of \( 4x \) is 4. Next, find \( v'(x) \): the derivative of \( \sqrt{3x + 2} \) is found using chain rule. Let \( g(x) = 3x + 2 \), then \( v(x) = (g(x))^{1/2} \).This implies \( v'(x) = \frac{1}{2}(g(x))^{-1/2} g'(x) \), with \( g'(x) = 3 \), leading to: \[ v'(x) = \frac{1}{2}(3x+2)^{-1/2} \times 3 = \frac{3}{2\sqrt{3x + 2}}. \]
04

Apply the product rule

Now, apply the product rule using the derivatives found:\[ (4x \sqrt{3x + 2})' = u'(x)v(x) + u(x)v'(x) = 4 \cdot \sqrt{3x + 2} + 4x \cdot \frac{3}{2\sqrt{3x + 2}}. \]
05

Simplify the expression

Simplify the terms: First term remains \( 4 \sqrt{3x + 2} \).Second term can be simplified as: \[ 4x \times \frac{3}{2\sqrt{3x + 2}} = \frac{12x}{2\sqrt{3x + 2}} = \frac{6x}{\sqrt{3x + 2}}.\]Combine the two terms: \[ (4x \sqrt{3x + 2})' = 4 \sqrt{3x+2} + \frac{6x}{\sqrt{3x+2}} = \frac{4(3x+2) + 6x}{\sqrt{3x+2}}. \] Further simplify:\[ = \frac{12x + 8 + 6x}{\sqrt{3x+2}} = \frac{18x + 8}{\sqrt{3x+2}}. \]
06

Write the final derivative

As the derivative of the constant 93 is 0, the final derivative of the function \( f(x) \) is: \[ f'(x) = \frac{18x + 8}{\sqrt{3x+2}}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Product Rule
Understanding the product rule is essential when differentiating a function composed of two or more multiplicative parts. In calculus, the product rule provides a way to differentiate a product of two functions. Let's say you have two functions, \( u(x) \) and \( v(x) \), whose product is expressed as \( u(x) \cdot v(x) \). The derivative of this product is found using the formula:
  • \( (u(x)v(x))' = u'(x)v(x) + u(x)v'(x) \)
To apply this rule, differentiate each function separately and then insert them into the formula. For example, given the function \( 4x \sqrt{3x + 2} \), identify \( u(x) = 4x \) and \( v(x) = \sqrt{3x + 2} \). For \( u'(x) = 4 \) and the more complex \( v(x) \), we'll need another rule: the chain rule. Use the product rule methodically, and always check your function's structure to determine which parts need differentiation first.
Chain Rule
The chain rule is invaluable when differentiating compositions of functions — specifically when one function is within another, like \( \sqrt{3x + 2} \). Here, the inner function \( g(x) = 3x + 2 \) is 'inside' the square root function. The chain rule helps us find the derivative of such complex functions, expressed as:
  • \( \frac{d}{dx} [f(g(x))] = f'(g(x)) \cdot g'(x) \)
In our example, the outer function is a square root, and the inner function is \( 3x + 2 \). Differentiating \( \sqrt{3x+2} \) involves using the chain rule, resulting in:
  • First find the derivative of the outer function: if \( v(x) = (3x+2)^{1/2}\), then differentiate as \( \frac{1}{2}(3x+2)^{-1/2} \).
  • Next, differentiate the inner function: \( g(x) = 3x+2 \), so \( g'(x) = 3 \).
  • Combining them, \( v'(x) = \frac{1}{2}(3x+2)^{-1/2} \times 3 \), which simplifies to \( \frac{3}{2\sqrt{3x + 2}} \).
This calculated derivative of the composite function beautifully demonstrates the efficiency of the chain rule.
Differentiation Techniques
Mastering different techniques in differentiation is crucial. These techniques allow you to handle various forms of functions efficiently. Here are some common differentiation techniques:
  • Constant Rule: The derivative of a constant is always 0, simplifying expressions considerably when it appears alone.
  • Power Rule: For any function \( x^n \), its derivative is \( nx^{n-1} \), providing a quick route to differentiation for polynomial terms.
  • Product Rule: As detailed earlier, this rule is key when dealing with multiplicative functions.
  • Chain Rule: Essential for composite functions—differentiates inside-out, reflecting the nested nature of composed functions.
  • Sum Rule: This allows you to differentiate each term in a sum separately, which offers a straightforward approach when dealing with addition.
Using these techniques in tandem, as shown in the step-by-step solution of differentiating \( f(x) = 4x \sqrt{3x+2} + 93 \), we can handle a wide array of function types. This knowledge greatly aids in simplifying calculations and enhancing problem-solving skills.

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