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91Ó°ÊÓ

Radon A building is found to contain radioactive radon gas. Thirty hours later, \(80 \%\) of the initial amount of gas is still present. a. Write a model for the percentage of the initial amount of radon gas present after \(t\) hours. b. Calculate the half-life of the radon gas.

Short Answer

Expert verified
a. The model is \( N(t) = N_0 \cdot e^{-0.00754t} \). b. The half-life is approximately 91.6 hours.

Step by step solution

01

Understand the Problem

We need to create a model for the radioactive decay of radon gas and calculate its half-life. Radioactive decay follows an exponential model. We're given that after 30 hours, 80% of the radon remains.
02

Write the Decay Model

The decay model for radioactive substances is given by \( N(t) = N_0 \cdot e^{-kt} \), where \( N(t) \) is the amount remaining after time \( t \), \( N_0 \) is the initial amount, and \( k \) is the decay constant.
03

Use Given Data to Find the Decay Constant

We're given that after 30 hours, 80% of the gas remains, so \( 0.8N_0 = N_0 \cdot e^{-30k} \). Cancel \( N_0 \) and solve for \( k \):\[ 0.8 = e^{-30k} \]Taking the natural logarithm of both sides:\[ \ln(0.8) = -30k \]Solve for \( k \):\[ k = \frac{-\ln(0.8)}{30} \approx 0.00754 \]
04

Formulate the Model

Substitute the decay constant \( k \) back into the exponential model:\[ N(t) = N_0 \cdot e^{-0.00754t} \]This model describes the percentage of initial radon gas present after \( t \) hours.
05

Calculate the Half-Life

The half-life is the time \( t \) when \( N(t) = \frac{N_0}{2} \). Set up the equation:\[ \frac{N_0}{2} = N_0 \cdot e^{-0.00754t_{1/2}} \]Simplify and solve for \( t_{1/2} \):\[ \frac{1}{2} = e^{-0.00754t_{1/2}} \]Taking the natural logarithm of both sides:\[ \ln(0.5) = -0.00754t_{1/2} \]Solve for \( t_{1/2} \):\[ t_{1/2} = \frac{\ln(0.5)}{-0.00754} \approx 91.6 \text{ hours} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Model
When we talk about radioactive decay, we often use the exponential model to represent how the quantity of a substance decreases over time. This model describes a situation where the decay happens at a rate proportional to the current amount of substance. This means the larger the amount you have, the faster it decays. This is why radioactive substances like radon gas decrease gradually, rather than all at once.

The basic formula for this is represented as:
  • \( N(t) = N_0 \cdot e^{-kt} \)
    • \( N(t) \) is the amount remaining at time \( t \).
    • \( N_0 \) is the initial amount of the substance.
    • \( e \) is the mathematical constant approximately equal to 2.71828.
    • \( k \) is the decay constant, which we will explain further.
This formula is so powerful because it can show us not only how quickly a substance decays but also how much remains after any time \( t \). The exponential model is a cornerstone for understanding how radioactivity and decay work in different substances.
Half-Life
The half-life is a unique concept that helps us understand how long it takes for half of a radioactive substance to decay. It's the time required for the amount of something to reduce to half its initial quantity. In simpler terms, if you start with 100 grams of radon, after one half-life, you'll only have 50 grams left.

The process is exponentially decreasing, so each half-life results in a smaller portion of the initial quantity being lost:
  • After the first half-life, you have 50% left.
  • After the second half-life, you're left with 25% of the original amount.
  • Subsequent half-lives reduce the quantity by half again and again.
To calculate the half-life using our exponential model, we can substitute \( \frac{N_0}{2} \) for \( N(t) \) and solve for \( t \), giving us a formula:
  • \( t_{1/2} = \frac{\ln(0.5)}{-k} \)
Finding the half-life can be essential for understanding how quickly a dangerous substance like radon decays, helping us in planning and safety judgments.
Decay Constant
The decay constant \( k \) is an important number that represents the rate at which a radioactive substance decays. It tells us how quickly or slowly the decay process happens. A larger \( k \) means faster decay.

To find the decay constant, we take a known amount of decay over a period of time and fit it into our exponential model formula. For the radon example, if we know that 80% remains after 30 hours, this data helps calculate \( k \):
  • First, we set up the equation: \( 0.8 = e^{-30k} \)
  • We interpret the problem and multiply through by \( e \) to simplify and solve for \( k \).
Using logarithms, we get the decay constant formula:
  • \( k = \frac{-\ln(0.8)}{30} \)
  • This gives \( k \approx 0.00754 \) for our radon problem.
Understanding the decay constant helps in predicting the behavior of the substance over time, providing critical insights in fields like environmental science and nuclear physics.

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Most popular questions from this chapter

Stolen Bases San Francisco Giants legend Willie Mays's cumulative numbers of stolen bases between 1951 and 1963 are as shown below. Bases Stolen by Willie Mays (cumulative) \begin{tabular}{|c|c|c|c|} \hline Year & Stolen Bases & Year & Stolen Bases \\ \hline 1951 & 7 & 1958 & 152 \\ \hline 1952 & 11 & 1959 & 179 \\ \hline 1953 & 11 & 1960 & 204 \\ \hline 1954 & 19 & 1961 & 222 \\ \hline 1955 & 43 & 1962 & 240 \\ \hline 1956 & 83 & 1963 & 248 \\ \hline 1957 & 121 & & \\ \hline \end{tabular} (Source: www.baschall-reference.com) a. Find a logistic model for the data with input data aligned so that \(t=0\) in \(1950 .\) b. According to the model, how many bases did Mays steal in 1964 ? c. In 1964 Mays stole 19 bases. Does the model overestimate or underestimate the actual number? By how much?

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