/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Algebraically determine the limi... [FREE SOLUTION] | 91Ó°ÊÓ

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Algebraically determine the limits. $$ \lim _{x \rightarrow 2}(3 x+7) $$

Short Answer

Expert verified
The limit is 13.

Step by step solution

01

Identify the Type of Limit

This problem gives us a basic polynomial expression and asks for the limit as \( x \) approaches 2. Since this is a simple linear polynomial, we know it is continuous everywhere, which means we can directly substitute \( x = 2 \) into the expression.
02

Substitute the Value into the Expression

Given the expression \( 3x + 7 \), substitute \( x = 2 \) into it. This calculation is simply evaluating the polynomial at the given point.
03

Evaluate the Expression

Perform the arithmetic by calculating \( 3 \times 2 + 7 \). First, multiply \( 3 \) by \( 2 \) to get \( 6 \), then add \( 7 \) to get \( 13 \).
04

State the Result

Since we've substituted \( x = 2 \) and evaluated the expression, the limit of \( 3x + 7 \) as \( x \) approaches 2 is \( 13 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Expressions
Polynomial expressions are mathematical phrases involving a sum of powers in one or more variables multiplied by coefficients. They can look like simple linear expressions, such as \( 3x + 7 \), or more complex ones with higher powers, like \( x^2 + 4x + 4 \). Each "piece" of the expression, like \( 3x \) or \( 7 \), is called a term. Polynomials are the building blocks in algebra, and they play a crucial role in calculus too. Specifically, when dealing with limits, polynomials are important because of their simple, predictable behavior. Polynomial functions are continuous and differentiable everywhere, making them straightforward to work with.
In our example, the polynomial \( 3x + 7 \) is a linear expression. For any value we choose, we can easily compute its corresponding value using basic arithmetic operations.
Continuity in Functions
Continuity is a fundamental concept in calculus that describes a function that is smooth and unbroken. If you can draw a function without lifting your pen, that function is continuous. This property is essential when evaluating limits. A continuous function means there are no holes, jumps, or asymptotes in the graph, and you can predict the function's behavior at any point within its domain. Linear polynomials, like the expression \( 3x + 7 \), are continuous everywhere because they are simply straight lines. This makes it easy to find limits, as you can directly substitute the value of \( x \) without encountering undefined points.
Remember, not all functions are continuous everywhere, but polynomial functions offer the kind of regularity that allows us to apply limits easily and without special techniques.
Substitution Method in Limits
The substitution method is the go-to approach for finding limits in continuous functions, especially polynomial expressions. This method involves directly replacing the variable \( x \) with the value it approaches in the limit. Here's how:- **Recognize the Function Type**: Ensure the function is a type where substitution is valid, such as a polynomial which is continuous.- **Substitute the Variable**: Carefully replace \( x \) with the number it's approaching. In our case, we substitute \( 2 \) into \( 3x + 7 \).- **Evaluate the Expression**: Conduct arithmetic as usual. In step-by-step form for our example:- Substitute \( x = 2 \) into \( 3x + 7 \), which becomes \( 3(2) + 7 \).
- Compute it to find \( 6 + 7 = 13 \).
This simplicity and directness in substitution underscore why understanding continuity in context of limits is powerful.

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