Chapter 4: Problem 45
Find \(\frac{d}{d t} f(t)\) $$ f(t)=\sqrt[3]{t}-\frac{1}{\sqrt[3]{t}} $$
Short Answer
Expert verified
The derivative \( \frac{d}{dt} f(t) \) is \( \frac{1}{3}t^{-2/3} + \frac{1}{3}t^{-4/3} \).
Step by step solution
01
Understand the Problem
We are asked to find the derivative of the function \( f(t) = \sqrt[3]{t} - \frac{1}{\sqrt[3]{t}} \). This involves applying rules of differentiation to each term in the function separately.
02
Rewrite the Functions
Express each component of the function in a form suitable for differentiation. The first term \( \sqrt[3]{t} \) can be expressed as \( t^{1/3} \). The second term \( \frac{1}{\sqrt[3]{t}} \) can be rewritten as \( t^{-1/3} \). Thus, \( f(t) = t^{1/3} - t^{-1/3} \).
03
Differentiate Each Term
Apply the power rule \( \frac{d}{dt}[t^n] = n \cdot t^{n-1} \) to each term. For the first term \( t^{1/3} \), the derivative is \( \frac{1}{3}t^{1/3 - 1} = \frac{1}{3}t^{-2/3} \). For the second term \( t^{-1/3} \), the derivative is \( -\frac{1}{3}t^{-1/3 - 1} = -\frac{1}{3}t^{-4/3} \).
04
Combine the Derivatives
Combine the differentiated terms to find the derivative of the entire function. The derivative of \( f(t) \) is \( f'(t) = \frac{1}{3}t^{-2/3} - \left(-\frac{1}{3}t^{-4/3}\right) \).
05
Simplify the Expression
Simplify the expression by combining like terms. This results in \( f'(t) = \frac{1}{3}t^{-2/3} + \frac{1}{3}t^{-4/3} \). Further simplification might not combine these terms easily, so it is correct as it stands.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
In differential calculus, the Power Rule is a basic principle used for finding the derivative of a function of the form \(t^n\). When you encounter an expression like \(f(t) = t^{1/3} - t^{-1/3}\), the Power Rule comes in handy to derive it easily. The Power Rule states that the derivative of \(t^n\), where \(n\) is any real number, is \(n \cdot t^{n-1}\). To differentiate \(t^{1/3}\), follow these steps:
- Identify \(n\) as \(1/3\) from \(t^{1/3}\).
- Apply the Power Rule: \(\frac{d}{dt}[t^{1/3}] = \frac{1}{3} \cdot t^{1/3-1}\).
- This simplifies to \(\frac{1}{3}t^{-2/3}\).
- Identify \(n\) as \(-1/3\).
- Apply the Power Rule: \(\frac{d}{dt}[t^{-1/3}] = -\frac{1}{3} \cdot t^{-1/3-1}\).
- This simplifies to \(-\frac{1}{3}t^{-4/3}\).
Derivative
A derivative represents how a function changes as its input changes. It shows the rate of change or the slope of a curve at any point along its length. In the context of the given problem, finding the derivative \(\frac{d}{dt}f(t)\) means calculating how the function \(f(t) = \sqrt[3]{t} - \frac{1}{\sqrt[3]{t}}\) changes concerning \(t\).By expressing each term in the function using exponents, the function becomes \(f(t) = t^{1/3} - t^{-1/3}\). Using the Power Rule, we calculate the derivative as follows:
- The derivative of the first term \(t^{1/3}\) is \(\frac{1}{3}t^{-2/3}\).
- The derivative of the second term \(t^{-1/3}\) is \(-\frac{1}{3}t^{-4/3}\).
Differential Calculus
Differential Calculus is a field in mathematics focused on how functions change, and the derivatives that represent these changes. It provides tools to measure how a quantity occurs over time or under various conditions. By studying derivatives, differential calculus allows us to understand and predict complex systems.The task of differentiation involves finding the derivative, a central theme in differential calculus. For instance, in our exercise where \(f(t)\) is defined, applying differential calculus principles helps in finding \(f'(t)\). This concept of differentiation helps reveal deeper insights:
- Predictive Analysis: Derivatives help predict future values based on current data trends.
- Optimization: Identifying maximum or minimum values of functions is possible using derivatives.