/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Biology Schotzko and Smith \(^{9... [FREE SOLUTION] | 91Ó°ÊÓ

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Biology Schotzko and Smith \(^{90}\) showed that the number y of wheat aphids in an experiment was given approximately by \(y=f(t)=5.528+1.360 t^{2.395},\) where \(t\) is the time measured in days. Find \(f^{\prime}(t)\) and explain what this means.

Short Answer

Expert verified
\( f'(t) = 3.2582 t^{1.395} \); it represents the rate of change of aphid population over time.

Step by step solution

01

Identify the function

The function given in the problem is \( y = f(t) = 5.528 + 1.360 t^{2.395} \). This function models the number of wheat aphids in terms of time \( t \) measured in days.
02

Differentiate the function

To find \( f'(t) \), we need to differentiate the function \( f(t) = 5.528 + 1.360 t^{2.395} \) with respect to \( t \). Use the power rule of differentiation, which states that \( \frac{d}{dt}[t^n] = n \cdot t^{n-1} \).
03

Differentiate the constant term

The derivative of the constant \( 5.528 \) is zero, because the derivative of any constant is zero.
04

Differentiate the power term

Differentiate the term \( 1.360 t^{2.395} \) using the power rule: \[ \frac{d}{dt}[1.360 t^{2.395}] = 1.360 \cdot 2.395 \cdot t^{2.395-1} = 3.2582 t^{1.395} \].
05

Write the derivative

Combine the results of Steps 3 and 4 to write the derivative: \[ f'(t) = 3.2582 t^{1.395} \].
06

Interpretation of the derivative

The derivative \( f'(t) = 3.2582 t^{1.395} \) represents the rate of change of the number of wheat aphids at any time \( t \). It tells us how quickly or slowly the population of aphids is increasing at a specific day.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
The power rule is a fundamental concept in calculus used to differentiate functions of the form \( t^n \) where \( n \) is a constant. It provides a simple formula: \( \frac{d}{dt}[t^n] = n \cdot t^{n-1} \). This rule is incredibly useful because it allows us to handle polynomial terms quickly.
In the exercise, we differentiated the term \( 1.360 t^{2.395} \). By applying the power rule, we multiplied 2.395 (the exponent) by the coefficient 1.360, then reduced the exponent by one:
  • Original term: \( 1.360 t^{2.395} \)
  • Differentiate: \( 1.360 \times 2.395 = 3.2582 \)
  • New exponent: \( 2.395 - 1 = 1.395 \)
This results in the derivative \( 3.2582 t^{1.395} \). The power rule simplifies finding derivatives, especially for polynomial functions, allowing us to understand how a function changes as \( t \) changes over time.
Rate of Change
The concept of the rate of change is critically important in understanding how a quantity, like the number of wheat aphids, evolves over time. In calculus, the rate of change is represented by the derivative of a function. Essentially, it tells us how fast something is increasing or decreasing.
For the given function \( y = 5.528 + 1.360 t^{2.395} \), differentiating gives \( f'(t) = 3.2582 t^{1.395} \). This derivative tells us that at any given time \( t \), the aphid population is changing at a rate of \( 3.2582 t^{1.395} \).
  • A positive derivative indicates that the population is growing.
  • The magnitude of the derivative shows how rapidly the population changes.
  • A larger value of \( t \) will generally lead to a greater rate of change, implying accelerated growth as time progresses.
Understanding the rate of change is essential for predicting trends and making informed decisions based on the changes over time.
Biology Applications
Differentiation is not just a mathematical concept but a significant tool in biology, especially in understanding growth patterns and interactions among organisms. In the context of the wheat aphid population model \( y = f(t) = 5.528 + 1.360 t^{2.395} \), differentiation helps to analyze how the aphid population changes week by week.
This application provides insights into biological processes by allowing scientists to:
  • Identify the growth rate of populations under study.
  • Understand the potential impacts of environmental factors on growth.
  • Predict future population sizes based on current growth trends.
In our particular exercise, the concept of differentiation is employed to estimate how fast aphid populations are expected to grow over several days. These insights can inform agricultural strategies and pest control measures by anticipating when aphid populations might reach harmful levels.

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