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In Exercises 13 through \(24,\) use the quotient rule to find the derivative. $$ f(x)=\frac{e^{x}}{x-2} $$

Short Answer

Expert verified
The derivative is \( f'(x) = \frac{e^x (x-3)}{(x-2)^2} \).

Step by step solution

01

Identify Functions in Quotient

The function given is a quotient: \( f(x) = \frac{e^x}{x-2} \). Here, \( u(x) = e^x \) is the numerator and \( v(x) = x-2 \) is the denominator.
02

Recall the Quotient Rule Formula

The quotient rule states that if \( f(x) = \frac{u(x)}{v(x)} \), then the derivative \( f'(x) = \frac{v(x)u'(x) - u(x)v'(x)}{[v(x)]^2} \).
03

Find Derivatives of u and v

Compute the derivatives:- \( u'(x) = \frac{d}{dx}[e^x] = e^x \).- \( v'(x) = \frac{d}{dx}[x-2] = 1 \).
04

Apply the Quotient Rule

Substitute \( u(x) \), \( v(x) \), \( u'(x) \), and \( v'(x) \) into the quotient rule formula:\[ f'(x) = \frac{(x-2)e^x - e^x \cdot 1}{(x-2)^2} \].
05

Simplify the Expression

Simplify the expression for \( f'(x) \):\[ f'(x) = \frac{e^x (x-2) - e^x}{(x-2)^2} \]\[ = \frac{e^x x - 2e^x - e^x}{(x-2)^2} \]\[ = \frac{e^x (x-3)}{(x-2)^2} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative Computation
Computing derivatives often involves a variety of rules and formulas. In the case of functions presented as quotients, the quotient rule is particularly useful. This rule provides a systematic way to find the derivative of a function that is the ratio of two other functions, say \( u(x) \) and \( v(x) \). When tackling such problems, remember:
  • Identify the numerator (\( u(x) \)) and the denominator (\( v(x) \)) in the given function.
  • Recall and set up the quotient rule formula: \[ f'(x) = \frac{v(x)u'(x) - u(x)v'(x)}{[v(x)]^2} \] It's essential to keep the order of the terms the same, as swapping them changes the result.
  • Compute the derivatives \( u'(x) \) and \( v'(x) \) of the numerator and the denominator, respectively.
  • Substitute these into the formula, then carry through with any necessary simplifications.
Using this rule simplifies the often complex task of differentiating quotients by giving a clear process to follow.
Exponential Functions
Exponential functions are powerful mathematical expressions where a constant base is raised to a variable exponent. In calculus, the exponential function \( e^x \) is particularly significant because it has a unique property: its derivative is the same as the function itself.
  • Understanding this property is crucial for anyone working with exponential growth or decay.
    • It means that if you differentiate \( e^x \), you still end up with \( e^x \).
  • This behavior of exponential functions often simplifies the computation since you do not need to apply product or chain rules as you would with other functions.
Exploring exponential functions goes beyond simply using \( e^x \); it encompasses understanding their behavior, which is consistently smooth and steadily increasing. These functions appear naturally in real-world situations, such as population dynamics and financial models, where they model consistent growth or decay without bounds.
Function Simplification
Simplifying functions and expressions is a vital skill in calculus and broader mathematics. After deriving a complex expression using rules like the quotient rule, it's crucial to simplify the result, both to make it more understandable and easier to use in further calculations.
  • Start by expanding and combining like terms in the numerator. When expressions have common terms, these can often be factored out to reduce the complexity of the fraction.
  • Look for common factors across the numerator and denominator. Removing these can simplify the expression significantly.
For example, in our case, after applying the quotient rule to \( f(x) = \frac{e^x}{x-2} \), the derivative is simplified to:\[ f'(x) = \frac{e^x (x-3)}{(x-2)^2}\] Here, \( e^x \) was factored from the terms in the numerator, making for a cleaner expression. This simplification step is essential for both clarity and minimizing computational errors. It's an especially useful strategy in preparing expressions for graphing or further algebraic manipulation.

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