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Find, without graphing, where each of the given functions is continuous. $$ f(x)=\left\\{\begin{array}{ll} -x+2 & \text { if } x<1 \\ 0 & \text { if } x=1 \\ x^{2} & \text { if } x>1 \end{array}\right. $$

Short Answer

Expert verified
The function is continuous everywhere except at \( x = 1 \).

Step by step solution

01

Identify the Continuity of Each Piece

The function \( f(x) \) is a piecewise function with three parts: \(-x + 2\) for \(x < 1\), \(0\) for \(x = 1\), and \(x^2\) for \(x > 1\). Each part is itself a basic function, specifically a linear function for \(x < 1\) and a quadratic function for \(x > 1\). Both linear and quadratic functions are continuous on their respective domains.
02

Evaluate Continuity at x = 1

To find where the function \( f(x) \) is continuous, we need to check the point \( x = 1 \), where the formula for \( f(x) \) changes. We check if the left-hand limit as \( x \) approaches 1 from the left equals the right-hand limit as \( x \) approaches 1 from the right, and if both are equal to \( f(1) \).
03

Calculate Limits and Function Value at x = 1

Compute the left-hand limit: \( \lim_{x \to 1^-} (-x + 2) = -(1) + 2 = 1 \). Compute the right-hand limit: \( \lim_{x \to 1^+} x^2 = 1^2 = 1 \).Evaluate the function at \( x = 1: f(1) = 0 \).
04

Determine Continuity at x = 1

The left-hand limit and the right-hand limit as \( x \to 1 \) are both equal to 1, but \( f(1) = 0 \). Therefore, the function is not continuous at \( x = 1 \) because the limits do not equal the function value.
05

State Overall Continuity of the Function

Since the function is continuous on the individual intervals \( x < 1 \) and \( x > 1 \) and discontinuous at \( x = 1 \), the function \( f(x) \) is continuous for all real numbers except at \( x = 1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limits and Continuity
In mathematics, understanding the concept of limits and continuity is crucial for grasping how functions behave. Limits help us know what value a function approaches as the input approaches a certain point. Continuity, on the other hand, is about knowing whether a function remains smooth without any breaks or gaps at a given point.

To analyze a function's continuity using limits, we must examine both one-sided limits as well as the exact value of the function at that point. Consider a function like our piecewise example. We look at the left-hand limit (as we approach the point from values less than the point) and the right-hand limit (as we approach from greater values).

  • If the left-hand limit, right-hand limit, and the function's actual value at the point are all equal, then the function is continuous at that point.
  • If they do not match, the function has a discontinuity.
In the given piecewise function, such analysis helps us isolate and confirm points of discontinuity like at \(x = 1\).
Piecewise Functions
Piecewise functions are mathematical expressions defined by multiple sub-functions, each applying to a certain interval of the input domain. They allow for versatile modeling of real-life situations where behavior changes at certain thresholds.

Our function, for example, uses three distinct expressions in different intervals:
  • The part \(-x + 2\) is linear and applies when \(x < 1\),
  • The constant \(0\) takes over exactly at \(x = 1\),
  • Finally, \(x^2\) applies when \(x > 1\) which is a quadratic function.
Each of these segments individually spans its own interval continuously. However, the challenge is stitching these seamlessly together.

When dealing with piecewise functions, analyzing each interval helps in identifying any possible points of discontinuity. The transitions between different functional expressions require careful examination through the concept of continuity, ensuring they connect without any breaks.
Discontinuity Analysis
Discontinuity in functions refers to points where a function is not continuous, essentially places where the function "jumps" or "drops". Understanding and identifying the nature of these discontinuities is essential for a comprehensive function analysis.

In the context of our piecewise function, we see that a potential point of discontinuity occurs at \(x = 1\). To confirm, we perform a discontinuity analysis by checking:
  • The left-hand limit at \(x = 1\): found from \(-x + 2\), which evaluates to \(1\).
  • The right-hand limit at \(x = 1\): evaluated from \(x^2\), which is also \(1\).
  • The actual function value at \(x = 1\): explicitly given as \(0\).
Since the limits are both \(1\) but do not match the function value of \(0\), this confirms a jump discontinuity at \(x = 1\).

Such analysis helps in determining the complete behavior of the function, pinpointing areas where normal smoothness is interrupted, vital for many applications within mathematics and its related fields.

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Most popular questions from this chapter

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