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Use your grapher to find the breakeven quantities for the given profit functions and the value of \(x\) that maximizes the profit. $$ P(x)=-x^{2}+5.9 x-7.92 $$

Short Answer

Expert verified
Breakeven points are at approximately \( x = 1.5 \) and \( x = 4.4 \), and the profit is maximized at \( x = 2.95 \).

Step by step solution

01

Set up the profit equation

The problem provides a profit function: \[ P(x) = -x^2 + 5.9x - 7.92 \] We need to find the breakeven points and the value of \( x \) that maximizes this profit function.
02

Find the breakeven points

Breakeven points occur when the profit \( P(x) \) is zero. Therefore, we must solve the equation:\[-x^2 + 5.9x - 7.92 = 0\]Use a graphing calculator or software to visualize the function and identify the values of \( x \) where the graph intersects the x-axis. These intersections are the breakeven points.
03

Find the vertex of the parabola

To find the value of \( x \) that maximizes the profit, note that \( P(x) = -x^2 + 5.9x - 7.92 \) is a downward-opening parabola. The maximum point is at the vertex, given by \( x = -\frac{b}{2a} \), where \( a = -1 \) and \( b = 5.9 \).
04

Calculate the vertex

Substitute the values of \( a \) and \( b \) into the formula to find the vertex:\[x = -\frac{5.9}{2(-1)} = 2.95\] Thus, the value of \( x \) that maximizes the profit is 2.95.
05

Find exact breakeven points numerically

Using the graphing tool, or by solving the quadratic equation numerically or graphically, the breakeven points where the profit function \( P(x) = 0 \) are found. After graphing, these values are approximately \( x = 1.5 \) and \( x = 4.4 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Functions
Quadratic functions are an essential concept in algebra and calculus. They take the general form of a polynomial equation:
\[ ax^2 + bx + c = 0 \]
where \( a \), \( b \), and \( c \) are constants. In this case, a quadratic function represents profit as:
\[ P(x) = -x^2 + 5.9x - 7.92 \]
It's important to note the coefficient of the \( x^2 \) term, \( a = -1 \), indicates the parabola opens downward. This makes sense in profit maximization problems where the function peaks at the vertex, representing maximum profit.
  • **Coefficient \( a \):** Decides the direction (upward or downward) of the parabola.
  • **Coefficient \( b \):** Affects the slope or steepness of the parabola's arms.
  • **Constant \( c \):** Sets the starting point or intercept on the y-axis.
Understanding these components helps you graph quadratic functions, find vertices, and analyze real-world scenarios such as maximizing profits.
Breakeven Analysis
Breakeven analysis is a crucial part of business decision-making. It involves finding the point where total revenues equal total costs, i.e., where profit is zero. For the given profit equation:
\[ -x^2 + 5.9x - 7.92 = 0 \]
Solving this equation helps identify the breakeven points. These points fall where the graph intersects the x-axis. At these intersection points:
  • The company neither makes a profit nor incurs a loss.
  • The mathematical solution involves setting the profit equation equal to zero and solving for \( x \).
  • Graphical solutions use tools like graphing calculators to visually pinpoint these x-intersections.
Breakeven analysis is vital because it helps organizations understand financial boundaries. It directs them on the minimum sales quantity needed to cover costs, avoiding losses.
Graphical Solutions
Graphical solutions provide a visual approach to solving profit maximization problems. Plotting the quadratic function:
\[ P(x) = -x^2 + 5.9x - 7.92 \]
allows you to spot critical points, like the vertex and the breakeven points. Here's how you utilize graphical solutions:
  • **Plotting the Parabola:** Draw the graph using a graphing calculator or software. The x-intercepts are breakeven points where profit is zero.
  • **Identifying the Vertex:** Look for the highest point in the parabola, which shows where profit is maximized.
  • **Intersections:** Note all intersections with the x-axis to find exact breakeven quantities.
Graphical solutions simplify complex mathematical expressions into an easily interpretable visual representation, aiding decision-making in profit analysis.
Vertex Calculation
Vertex calculation is central to determining the maximum or minimum point of a quadratic function. For downward parabolas like
\[ P(x) = -x^2 + 5.9x - 7.92 \]
the vertex marks the peak or maximum profit. To find this:
  • Use the vertex formula \( x = -\frac{b}{2a} \).
  • Substitute \( a = -1 \) and \( b = 5.9 \) to get \[ x = -\frac{5.9}{2(-1)} = 2.95 \].
  • This x-value provides the quantity at which profit is maximized.
Vertex calculation not only reveals maximum profits but underscores the efficiency of quadratic calculations in practice. Proper understanding allows businesses to optimize strategies for peak performance.

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Most popular questions from this chapter

Featherstone and coauthors \(^{37}\) studied 195 Kansas beef cow farms. The average fixed and variable costs are found in the following table. $$ \begin{array}{|c|r|} \hline {\text { Variable and Fixed Costs }} \\ \hline \text { Costs per cow } & \\ \text { Feed costs } & \$ 261 \\ \text { Labor costs } & \$ 82 \\ \text { Utilities and fuel costs } & \$ 19 \\ \text { Veterinary expenses costs } & \$ 13 \\ \text { Miscellaneous costs } & \$ 18 \\ \hline \text { Total variable costs } & \$ 393 \\ \text { Total fixed costs } & \$ 13,386 \\ \hline \end{array} $$ The farm can sell each cow for \(\$ 470 .\) Find the cost, revenue, and profit functions for an average farm. The average farm had 97 cows. What was the profit for 97 cows? Can you give a possible explanation for your answer?

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