/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Solve for \(x\). $$ 5^{3 x}=... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve for \(x\). $$ 5^{3 x}=125^{4 x-4} $$

Short Answer

Expert verified
The solution is \(x = \frac{4}{3}\).

Step by step solution

01

Write Both Sides with the Same Base

We know that both 5 and 125 are powers of 5. Since \(125 = 5^3\), we can rewrite the equation \(5^{3x} = (5^3)^{4x-4}\). This helps us to express both sides of the equation with the same base.
02

Simplify the Right Side Using Exponent Rule

Apply the exponent rule \((a^m)^n = a^{m\cdot n}\) to simplify the right side. The expression \((5^3)^{4x-4}\) becomes \(5^{3 \cdot (4x-4)}\), which simplifies to \(5^{12x - 12}\). Thus, our equation becomes \(5^{3x} = 5^{12x - 12}\).
03

Equate Exponents and Solve for \(x\)

Since the bases are the same, we can set the exponents equal to each other: \(3x = 12x - 12\). Our next goal is to solve this linear equation for \(x\).
04

Isolate \(x\)

Rearrange the equation \(3x = 12x - 12\) to isolate \(x\). Subtract \(12x\) from both sides, resulting in \(3x - 12x = -12\). This simplifies to \(-9x = -12\).
05

Solve for \(x\)

Now divide both sides of \(-9x = -12\) by \(-9\) to get \(x\). This gives \(x = \frac{-12}{-9} = \frac{4}{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Algebra
Algebra is a branch of mathematics that focuses on finding solutions to equations. It uses symbols and letters to represent numbers, allowing us to work with unknown values in a systematic way.
One of the essential skills in algebra is manipulating equations to isolate and solve for variables. This involves several fundamental operations such as addition, subtraction, multiplication, and division. In more complex problems, it may also involve exponentiation, which is raising a number to a power.
A critical aspect of algebra is understanding and applying the laws of exponents. For example, when multiplying like bases, you add the exponents, and when dividing, you subtract the exponents. These rules help simplify expressions and solve equations efficiently.
Knowing how to express numbers with the same base is particularly useful, as it allows us to work with the exponents directly. This technique was applied in the exercise above to rewrite the equation in a simpler form.
Linear Equations
Linear equations are equations of the first degree. They are called "linear" because their graph is a straight line when plotted on a coordinate plane.
These equations generally take the form of \(ax + b = 0\), where \(a\) and \(b\) are constants, and \(x\) is the variable. Linear equations are straightforward to solve as they involve finding the value of \(x\) that makes the equation true.
This concept is evident in the exercise where the equation \(3x = 12x - 12\) is obtained after simplifying the original exponential equation. Even though the problem initially involved exponentiation, it eventually boiled down to a simple linear equation.
Solving linear equations often involves steps like rearranging terms to isolate the variable or performing operations that simplify the equation, as seen when both sides were manipulated to isolate \(x\).
Solving Equations
Solving equations is a systematic process that involves finding the value(s) of the variable(s) that satisfy the equation. For exponential equations, the goal is often to manipulate the equation so that both sides share a common base.
  • By writing both sides of the equation with the same base, you can then equate the exponents directly. This will simplify the problem significantly.
  • This method was utilized effectively here, converting the equation into a linear form.
For linear equations, the strategy is usually to isolate the variable on one side of the equation. This may involve adding, subtracting, multiplying, or dividing both sides of the equation by the same number to maintain equality.
The final solution of the exercise demonstrated this approach where rearranging the terms and simplifying resulted in finding \(x = \frac{4}{3}\). By understanding the principles behind different types of equations and their solutions, you can tackle various mathematical problems with confidence.

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Most popular questions from this chapter

Diamond and colleagues \(^{90}\) studied the growth habits of the Atlantic croaker, one of the most abundant fishes of the southeastern United States. The mathematical model that they created for the ocean larva stage was given by the equation $$L(t)=0.26 e^{2.876\left[1-e^{-0.0623 t}\right]}$$ where \(t\) is age in days and \(L\) is length in millimeters. Graph this equation. Find the expected age of a 3 -mm-long larva algebraically.

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A company includes a manual with each piece of software it sells and is trying to decide whether to contract with an outside supplier to produce the manual or to produce it in-house. The lowest bid of any outside supplier is \(\$ 0.75\) per manual. The company estimates that producing the manuals in-house will require fixed costs of \(\$ 10,000\) and variable costs of \(\$ 0.50\) per manual. Which alternative has the lower total cost if demand is 20,000 manuals?

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