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Find the Taylor polynomials of orders \(n=0,1,2,3\) and 4 about \(x=x_{0},\) and then find the \(n\) th Taylor polynomial for the function in sigma notation. $$\frac{1}{x+2} ; x_{0}=3$$

Short Answer

Expert verified
The Taylor polynomials are found using derivatives and evaluating at \( x_0 = 3 \). The nth degree polynomial is expressed in sigma notation as \( P_n(x) = \sum_{k=0}^{n} \frac{(-1)^k k!}{(5^{k+1})}(x-3)^k \).

Step by step solution

01

Understand the Function and Center of Expansion

We are given the function \( f(x) = \frac{1}{x+2} \) and asked to find Taylor polynomials centered at \( x_0 = 3 \). The Taylor polynomial approximates the function around this point.
02

Compute Derivatives of the Function

Calculate the first few derivatives of \( f(x) = \frac{1}{x+2} \).1. \( f(x) = \frac{1}{x+2} \)2. \( f'(x) = -\frac{1}{(x+2)^2} \)3. \( f''(x) = \frac{2}{(x+2)^3} \)4. \( f'''(x) = -\frac{6}{(x+2)^4} \)5. \( f''''(x) = \frac{24}{(x+2)^5} \)
03

Evaluate Derivatives at the Center \( x_0 = 3 \)

Substitute \( x_0 = 3 \) into each derivative:1. \( f(3) = \frac{1}{5} \)2. \( f'(3) = -\frac{1}{25} \)3. \( f''(3) = \frac{2}{125} \)4. \( f'''(3) = -\frac{6}{625} \)5. \( f''''(3) = \frac{24}{3125} \)
04

Construct Taylor Polynomials

Construct the Taylor polynomials of different orders \( n = 0, 1, 2, 3, 4 \). The general formula is:\[P_n(x) = \sum_{k=0}^{n} \frac{f^k(x_0)}{k!}(x-x_0)^k\]- \( P_0(x) = \frac{1}{5} \)- \( P_1(x) = \frac{1}{5} - \frac{1}{25}(x-3) \)- \( P_2(x) = \frac{1}{5} - \frac{1}{25}(x-3) + \frac{1}{125}(x-3)^2 \)- \( P_3(x) = \frac{1}{5} - \frac{1}{25}(x-3) + \frac{1}{125}(x-3)^2 - \frac{1}{104.17}(x-3)^3 \)- \( P_4(x) = \frac{1}{5} - \frac{1}{25}(x-3) + \frac{1}{125}(x-3)^2 - \frac{1}{104.17}(x-3)^3 + \frac{1}{520.83}(x-3)^4 \)
05

Express the nth Taylor Polynomial in Sigma Notation

The \( n \)th Taylor polynomial in sigma notation is given by:\[P_n(x) = \sum_{k=0}^{n} \frac{(-1)^k k!}{(5^{k+1})}(x-3)^k\]This formula reflects the pattern of signs and factorials obtained from each derivative evaluation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivatives
Derivatives play a crucial role in understanding the behavior of functions and are central to the concept of Taylor Polynomials. When we talk about derivatives in this context, we are referring to how a function changes with small variations in its input. For the function given in our example, \(f(x) = \frac{1}{x+2}\), derivatives tell us how the slope of this function behaves at different points. The first derivative, \(f'(x) = -\frac{1}{(x+2)^2}\), provides the rate of change of the function. Similarly, the subsequent derivatives provide different layers of this rate change, such as concavity and higher order curvature of the function.
  • The first derivative gives the slope or the rate at which the function's value is changing.
  • The second derivative indicates the concavity, showing if the function is curving upwards or downwards.
  • Higher-order derivatives continue to describe more complex characteristics of the function's shape.
By evaluating these derivatives at the center of expansion, \(x_0 = 3\), we can capture the precise behavior of the function locally, which is essential for constructing Taylor polynomials.
Taylor Series
The Taylor Series is a fundamental concept in calculus used to approximate functions with polynomials. The idea is to express a function as an infinite sum of terms calculated from the derivatives of the function at a single point. For the given function \(f(x) = \frac{1}{x+2}\), we find that by taking derivatives, evaluating them at \(x_0 = 3\), and plugging these into the sum, we can construct a polynomial that approximates our function near this point.
This polynomial, often called a Taylor polynomial, is defined for a specific degree \(n\), indicating how many terms (or derivatives) are used in the approximation. The polynomial becomes an exact representation of the function as \(n\) approaches infinity.
  • The Taylor polynomial of order 0 is a constant representing the function's value at that point.
  • Polynomials of orders 1, 2, 3, and higher include more terms, adding linearity, curvature, and more complex patterns to better fit the function.
Thus, the Taylor Series provides a convenient method for approximating complex functions with simple polynomial expressions.
Polynomial Approximation
Polynomial Approximation is a technique where simple polynomial functions are used to estimate more complex ones. By using Taylor Polynomials, we approximate functions through their derivatives. The Taylor Polynomial is essentially a local approximation of the function around a particular point. The order of the polynomial, \(n\), determines the accuracy of this approximation.
For \(n = 0\), this approximation is just the value of the function at that point. Increasing \(n\) incorporates more derivatives into the polynomial, leading to a more accurate approximation of the function within a certain range from the point of expansion.
  • The zeroth-order approximation, \(P_0(x)\), is a flat line tangent to the function at \(x_0\).
  • Adding more terms provides curvature and form, allowing the polynomial to more closely follow the shape of the original function.
  • The nth-order polynomial is given in sigma notation as \(P_n(x) = \sum_{k=0}^{n} \frac{f^k(x_0)}{k!}(x-x_0)^k\), establishing a systematic way to calculate each term.
Ultimately, polynomial approximation is a powerful tool in mathematics, serving both analytical and computational purposes to simplify complicated functions.

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