Chapter 9: Problem 19
Determine whether the series converges. $$\sum_{k=1}^{\infty} \frac{\tan ^{-1} k}{1+k^{2}}$$
Short Answer
Step by step solution
Analyze the General Term
Apply Limit Comparison Test Setup
Calculate the Limit for Comparison
Evaluate the Limit
Conclude Using Limit Comparison Test
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit Comparison Test
To use the Limit Comparison Test:
- Identify a known series \( \sum b_k \) where you understand its convergence behavior, like a p-series.
- Calculate the limit \( \lim_{k \to \infty} \frac{a_k}{b_k} \) using the general term \( a_k \) of your series.
- If the limit is a positive, finite number, and \( \sum b_k \) converges, then \( \sum a_k \) converges as well.
- Similarly, if \( \sum b_k \) diverges and the limit is finite and positive, then \( \sum a_k \) diverges too.
p-series
The p-series is crucial in comparison tests like the Limit Comparison Test. Its simple form and well-defined behavior make it a foundational tool for understanding other, more complex series.
In our exercise, we used \( b_k = \frac{1}{k^2} \), which is a p-series with \( p = 2 \). This series known to converge helped in determining that the original series converges.
Asymptotic Behavior
- For example, \( \tan^{-1} k \) asymptotically approaches \( \frac{\pi}{2} \) as \( k \to \infty \). This gives an insight into the eventual value or limit of these functions.
- When analyzing series, we often look at the asymptotic behavior of the terms to predict how the series will behave.
General Term Analysis
- Analyze if the term is bounded or non-bounded, and if there's a distinct limit as \( k \to \infty \).
- In our exercise, we identified \( a_k = \frac{\tan^{-1} k}{1 + k^2} \). By recognizing that \( \tan^{-1} k \) is bounded and approaches a limit, we set the stage for the subsequent steps.
- Understanding this prepares you for choosing suitable known series for comparison testing.