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L. F. Richardson proposed the following model to describe the spread of war fever. If \(y=f(t)\) is the percentage of the population advocating war at time \(t,\) the rate of change of \(f(t)\) at any time is proportional to the product of the percentage of the population advocating war and the percentage not advocating war. Set up a differential equation that is satisfied by \(y=f(t),\) and sketch a solution. (Source: Psychometrica.)

Short Answer

Expert verified
The differential equation is \(\frac{dy}{dt} = ky(100 - y)\), representing logistic growth with equilibrium points at 0 and 100.

Step by step solution

01

Understand the Problem

The problem involves modeling the spread of war fever in a population using a differential equation. The rate of change of the percentage advocating war, denoted by \(\frac{dy}{dt}\), is proportional to the product of the percentage advocating war and the percentage not advocating war.
02

Define Variables

Let \(y\) be the percentage of the population advocating for war at time \(t\), and \((100 - y)\) be the percentage not advocating for war at time \(t\).
03

Set Up the Proportionality

Since the rate of change of \(y(t)\) is proportional to the product of \(y\) and \(100 - y\), we can write the differential equation as: \[\frac{dy}{dt} = k y (100 - y)\], where \(k\) is a constant of proportionality.
04

Write the Differential Equation

Combining the previous information, the differential equation that models the spread of war fever is: \[\frac{dy}{dt} = ky(100 - y)\].
05

Sketch the Solution

To sketch the solution, recognize that as \(y(t)\) reaches 0 or 100, the rate of change \(\frac{dy}{dt}\) approaches 0. Therefore, \(y(t)\) will approach one of these two equilibrium points. The function \(y(t)\) will resemble a logistic growth curve, starting from an initial percentage \(y_0\) and either approaching 0 or 100 asymptotically.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

war fever model
L.F. Richardson's war fever model aims to describe how sentiments of war spread through a community over time. Imagine observing a population where some percentage of people support going to war, while others don't. The idea behind this model is simple: the more people advocate for war, the more they influence those who don't, potentially changing their stance.

In mathematical terms, let's say the percentage of the population advocating for war at any time is represented by a function, say, \( y = f(t) \). Here, \( t \) is time. The model posits that the rate of change of people advocating for war (which we denote as \( \frac{dy}{dt} \) ) is influenced by the interactions between the two groups.

By understanding the differential equation at the heart of this model (\frac{dy}{dt} = k y (100 - y)), we can predict how advocacy grows or diminishes over time. This insight is crucial because it can help policymakers understand how strongly a population might lean towards war and how these sentiments can evolve.
rate of change
The rate of change, \( \frac{dy}{dt} \), is a crucial concept in understanding how rapidly the war fever grows or declines in a population. In simple terms, it's like measuring the speed of a car but for our specific case, we're measuring the speed at which people are changing their minds about advocating for war.

In the war fever model, this rate of change is dependent on two factors: the proportion of people already advocating for war \( y \) and those who are not advocating for it (which is \( 100 - y \)). This makes intuitive sense because if everybody or nobody is advocating for war, you would expect little to no change in sentiment.

We capture this idea mathematically by the product \( y (100 - y) \). If very few people are advocating for war, the product is small. If nearly everyone is already advocating, the product is also small. Maximum change happens when the advocates and non-advocates are balanced.
logistic growth
The war fever model's differential equation hints at a logistic growth pattern, which is a common concept in populations dynamics and other fields. Logistic growth models describe populations that start growing exponentially when resources are abundant but slow down as competition grows or resources become limited.

In our context, the percentage of war advocates might increase rapidly at first. But as their numbers grow, it becomes harder to sway the remaining non-advocates. As a result, the growth rate slows, and the percentage advocating war tends towards a stabilization point or equilibrium.

This logistic pattern is illustrated in the differential equation \[ \frac{dy}{dt} = ky(100 - y). \] When most of the population are either strong advocates or emphatic non-advocates for war, the rate of change heads toward zero, leading to equilibrium where the percentage might cap at 0% or 100%, representing no change or complete adoption, respectively. Understanding this growth model can help predict the behavior of complex systems over time.

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Most popular questions from this chapter

A certain piece of news is being broadcast to a potential audience of 200,000 people. Let \(f(t)\) be the number of people who have heard the news after \(t\) hours. Suppose that \(y=f(t)\) satisfies $$y^{\prime}=.07(200,000-y), \quad y(0)=10$$ Describe this initial-value problem in words.

A certain drug is administered intravenously to a patient at the continuous rate of \(r\) milligrams per hour. The paticnt's body removes the drug from the bloodstream at a rate proportional to the amount of the drug in the blood, with constant of proportionality \(k=.5\) (a) Write a differential equation that is satisfied by the amount \(f(t)\) of the drug in the blood at time \(t\) (in hours). (b) Find \(f(t)\) assuming that \(f(0)=0 .\) (Give your answer in terms of \(r .)\) (c) In a therapeutic 2 -hour infusion, the amount of drug in the body should reach 1 milligram within 1 hour of administration and stay above this level for another hour. However, to avoid toxicity, the amount of drug in the body should not exceed 2 milligrams at any time. Plot the graph of \(f(t)\) on the interval \(1 \leq t \leq 2,\) as \(r\) varies between 1 and 2 by increments of \(.1 .\) That is, plot \(f(t)\) for \(r=1,1.1,1.2,1.3, \ldots . .2 .\) By looking at the graphs, pick the values of \(r\) that yield a therapeutic and nontoxic 2-hour infusion.

The fish population in a pond with carrying capacity 1000 is modeled by the logistic equation $$ \frac{d N}{d t}=\frac{.4}{1000} N(1000-N) $$ Here, \(N(t)\) denotes the number of fish at time \(t\) in years. When the number of fish reached \(275,\) the owner of the pond decided to remove 75 fish per year. (a) Modify the differential equation to model the population of fish from the time it reached \(275 .\) (b) Plot several solution curves of the new equation, including the solution curve with \(N(0)=275.\) (c) Is the practice of catching 75 fish per year sustainable, or will it deplete the fish population in the pond? Will the size of the fish population ever come close to the carrying capacity of the pond?

Let \(f(t)\) be the solution of \(y^{\prime}=-(t+1) y^{2}, y(0)=1 .\) Use Euler's method with \(n=5\) to estimate \(f(1) .\) Then, solve the differential equation, find an explicit formula for \(f(t),\) and compute \(f(1) .\) How accurate is the estimated value of \(f(1) ?\).

Solving the differential equations that arise from modeling may require using integration by parts. [See formula (1).] After depositing an initial amount of \(\$ 10,000\) in a savings account that earns \(4 \%\) interest compounded continuously, a person continued to make deposits for a certain period of time and then started to make withdrawals from the account. The annual rate of deposits was given by \(3000-500 t\) dollars per year, \(t\) years from the time the account was opened. (Here, negative rates of deposits correspond to withdrawals.) (a) How many years did the person contribute to the account before starting to withdraw money from it? (b) Let \(P(t)\) denote the amount of money in the account, \(t\) years after the initial deposit. Find an initial-value problem satisfied by \(P(t)\). (Assume that the deposits and withdrawals were made continuously.)

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